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In two successive chess moves, a player first moves his queen two squares forward, then moves the queen three steps to the left (from the player's view). Assume each square is \(3.0 \mathrm{~cm}\) on a side. (a) Using forward (toward the player's opponent) as the positive \(y\) -axis and right as the positive \(x\) -axis, write the queen's net displacement in component form. (b) At what net angle was the queen moved relative to the leftward direction?

Short Answer

Expert verified
(a) The net displacement is \((-9.0, 6.0)\) cm. (b) The net angle is approximately \(-33.69^\circ\).

Step by step solution

01

Determine Displacement in Components for Forward Move

The player moves the queen two squares forward. Since forward movement is along the positive \(y\)-axis, with each square being \(3.0\, \mathrm{cm}\), the queen's forward move is \(2 \times 3.0\, \mathrm{cm} = 6.0\, \mathrm{cm}\) along the positive \(y\)-axis. The movement in the \(x\)-direction is 0 at this step. Thus, the displacement vector for this move is \((0, 6.0)\).
02

Determine Displacement in Components for Leftward Move

Next, the queen moves three squares to the left. In this context, moving left means moving in the negative \(x\)-direction. Each square is \(3.0\, \mathrm{cm}\), so the left move is \(3 \times (-3.0)\, \mathrm{cm} = -9.0\, \mathrm{cm}\) along the \(x\)-axis. There is no change in the \(y\)-direction for this move, giving a displacement vector of \((-9.0, 0)\).
03

Calculate the Net Displacement Vector

Add the displacement vectors obtained from Steps 1 and 2. The net displacement vector is:\[(0, 6.0) + (-9.0, 0) = (-9.0, 6.0)\, \mathrm{cm}\]
04

Calculate the Net Angle Relative to the Leftward Direction

To find the angle relative to the leftward direction (negative \(x\)-axis), use the tangent function: \[\theta = \tan^{-1}\left( \frac{\text{change in } y }{\text{change in } x} \right) = \tan^{-1}\left( \frac{6.0}{-9.0} \right)\]This gives a negative angle since the forward direction is treated as positive in the \(y\)-axis and leftward is in the negative \(x\)-axis direction. Calculate this:\[\theta = \tan^{-1}\left( -0.6667 \right) \approx -33.69^\circ\]The angle is negative indicating a direction above the horizontal left line.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement in Physics
Displacement in physics is a fundamental concept that describes the change in position of an object. It is a vector quantity, which means it takes into account both the magnitude and direction of the movement. Displacement is different from distance because distance considers only how much ground is covered, whereas displacement considers the starting and ending points.
When calculating displacement, you need to identify the initial and final position of an object, along with any movements in between. These movements are usually described in vector components. For example, if an object moves from point A to point B, the displacement is a straight line vector from point A to B, irrespective of the actual path taken.
To determine the displacement of the queen in the exercise, we consider two component movements: forward and leftward. Forward displacement occurs along the positive y-axis, while leftward movement occurs along the negative x-axis. Combining these vectors gives us the net displacement of \((-9.0, 6.0) \text{ cm}\). This net displacement vector provides both the direction and magnitude of the total movement.
Vector Components
In physics, vectors are used to represent quantities that have both magnitude and direction, such as displacement, velocity, or force. Vector components are the projections of these vectors along the coordinate axes, usually labeled as the x-axis and y-axis.
For the given problem, the displacement due to each chess move can be broken down into its vector components. The first move of the chess queen, two squares forward, contributes entirely to the y-component: \((0, 6.0) \text{ cm}\).
The second move, three squares to the left, contributes to the x-component: \((-9.0, 0) \text{ cm}\).
To find the net displacement, the components of the vector from each move are combined. This means adding up the x-components and separately adding the y-components. Thus, the net displacement becomes \((-9.0, 6.0) \text{ cm}\), which considers both the change in the x- and y-directions.
  • Understanding how to break complex movements into vector components simplifies the analysis of motion.
  • Each component reflects contribution to the movement along specific axes.
  • Combining these components provides a clear picture of the total displacement.
Angle Calculation
Angle calculation in physics is an essential step when understanding direction in vector analysis. The angle often indicates the direction of a vector relative to a baseline, such as one of the coordinate axes.
In our problem, calculating the angle involves the use of trigonometric functions. Specifically, the tangent function helps find the angle when dealing with right triangles formed by vector components.
To find the angle \(\theta\) relative to the negative x-axis or leftward direction:
  • Express the relationship using the tangent function: \(\theta = \tan^{-1}\left( \frac{6.0}{-9.0} \right)\).
  • This gives an angle approximately equal to \(-33.69^\circ\).
  • The negative sign in this context indicates the angle is measured clockwise from the leftward direction.
Understanding angle calculation helps in interpreting the vector directions and hence, the overall movement direction of an object.

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