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A flight controller determines that an airplane is 20.0 mi south of him. Half an hour later, the same plane is 35.0 mi northwest of him. (a) The general direction of the airplane's velocity is (1) east of south, (2) north of west, (3) north of east, (4) west of south. (b) If the plane is flying with constant velocity, what is its velocity during this time?

Short Answer

Expert verified
(a) North of west (option 2). (b) Velocity = 102.3 mi/h, direction: NW.

Step by step solution

01

Understanding Directions and Positions

First, identify the initial and final positions of the airplane relative to the flight controller. The initial position is 20.0 miles south of the flight controller. The final position is 35.0 miles northwest of him after half an hour.
02

Analyzing Directions

Consider the final direction given: northwest. This is a combination of north and west directions. The change from a southward to a northwest direction indicates the plane has moved in a north of west direction (option 2).
03

Calculating Change in Position

Determine the effective change in position by breaking down the movement into components. Initially, the plane is 20.0 miles south, meaning the coordinates relative to the controller are (0, -20). The final position 35.0 miles northwest can be broken down into components using a 45-degree angle (NW).For northwest, both north and west components are equal in magnitude:\[x = -35.0 \times \cos(45^\circ) = -24.75 \text{ mi} \y = 35.0 \times \sin(45^\circ) = 24.75 \text{ mi} \]Thus, the final position is (-24.75, 24.75).
04

Determining Displacement Vector

The displacement vector is obtained by subtracting the initial position from the final position:\[\Delta x = -24.75 - 0 = -24.75 \text{ mi} \\Delta y = 24.75 - (-20) = 44.75 \text{ mi} \]This displacement indicates a change in position to the northwest.
05

Calculating Velocity

Velocity is the change in position over the change in time. We know the change in time is half an hour.The velocity components are:\[v_x = \frac{\Delta x}{\Delta t} = \frac{-24.75}{0.5} = -49.5 \text{ mi/h} \v_y = \frac{\Delta y}{\Delta t} = \frac{44.75}{0.5} = 89.5 \text{ mi/h} \]Thus, the velocity vector is (-49.5, 89.5) mi/h, indicating a direction of north (positive y) and west (negative x).
06

Magnitude of Velocity

Calculate the magnitude of the velocity vector using the Pythagorean theorem:\[|v| = \sqrt{(-49.5)^2 + (89.5)^2} = \sqrt{2450.25 + 8010.25} = \sqrt{10460.5} \approx 102.3 \text{ mi/h} \]The magnitude of the velocity is approximately 102.3 mi/h.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Calculation
In order to understand how fast an object is moving, the concept of velocity becomes crucial. Velocity is not just about how much distance is covered but also in which direction this happens. Typically, velocity can be broken down into two components: speed and direction.

When dealing with problems involving changing positions, like the airplane in our example, we first identify the initial and final positions relative to a fixed point—in this case, a flight controller. After determining the displacement over a certain time duration, we can calculate the velocity.

For our scenario, we start by finding the displacement, which is essentially how far and in what direction the plane moved. Once we have this, we divide by the total time taken to find velocity. Here’s the breakdown:
  • Calculate the change in x and y coordinates.
  • Determine the time interval (here it’s 0.5 hours).
  • Divide the displacement by the time to find each component of velocity.
Thus, for the airplane, the velocity components were found as (-49.5, 89.5) mi/h, meaning the plane moves northwest, specifically west for the x-component and north for the y-component.
Vector Analysis
Vectors are essential in physics, especially when describing motion because they include both magnitude and direction.

When analyzing vectors, like with the airplane’s path, we break down movements into their respective directional components. This is done using trigonometry, often involving angles of 0, 90, and in this case, 45 degrees. Here's a quick guide:
  • Recognize the direction: Northwest means the movement is equally split between north and west.
  • Use trigonometric ratios: Components like cosine and sine of 45 degrees help split the vector into north and west components.
  • Calculate the x and y parts: By multiplying the total displacement by these trigonometric functions.
Through this process, we find that northwest movement breaks into two equal parts, maintaining uniform distribution between x (west) and y (north) components. This allows for an accurate computation of displacement.
Displacement Vector
The displacement vector in physics signifies the overall change in position from one point to another, considering direction and distance.

In scenarios like our aircraft movement, determining the displacement vector helps to understand how far the object has traveled in a straight line from its starting point. Here’s how it unfolds:
  • Identify starting and ending coordinates of the path.
  • Subtract initial positions from final positions to find each component of the displacement vector.
  • This gives a vector that includes magnitude and direction, reflecting total movement.
For the airplane example, the displacement changes were computed by subtracting the initial position from the final position, resulting in a vector of (-24.75 mi, 44.75 mi). This indicates movement towards the northwest, aligning with the observations provided initially. Analyzing the displacement vector thus gives a clear picture of the whole travel journey.

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Most popular questions from this chapter

A hockey puck slides along a horizontal ice surface at \(20.0 \mathrm{~m} / \mathrm{s}\), hits a flat vertical wall, and bounces off. Its initial velocity vector makes an angle of \(35^{\circ}\) with the wall and it comes off at an angle of \(25^{\circ}\) moving at \(10.0 \mathrm{~m} / \mathrm{s}\). Choose the \(+x\) -axis to be along the wall in the direction of motion and the \(y\) -axis to be perpendicular (into) to the wall. (a) Write each velocity in unit vector notation. (b) Determine the change in velocity in unit vector notation. (c) Determine the magnitude and direction, relative to the wall, of this velocity change.

Given two vectors, \(\overrightarrow{\mathrm{A}}\) which has a length of 10.0 and makes an angle of \(45^{\circ}\) below the \(-x\) -axis, and \(\overrightarrow{\mathbf{B}}\) which has an \(x\) -component of +2.0 and \(\mathrm{a} y\) -component of +4.0 (a) sketch the vectors on \(x-y\) axes, with all their "tails" starting at the origin, and (b) calculate \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\).

Using the triangle method, show graphically that (a) \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}=\overrightarrow{\mathrm{B}}+\overrightarrow{\mathrm{A}}\) and \((\mathrm{b})\) if \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}=\overrightarrow{\mathrm{C}},\) then \(\overrightarrow{\mathbf{A}}=\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{C}}\)

Two displacements, one with a magnitude of \(15.0 \mathrm{~m}\) and a second with a magnitude of \(20.0 \mathrm{~m},\) can have any angle you want. (a) How would you create the sum of these two vectors so it has the largest magnitude possible? What is that magnitude? (b) How would you orient them so the magnitude of the sum was at its minimum? What value would that be? (c) Generalize the result to any two vectors.

A motorboat's speed in still water is \(2.0 \mathrm{~m} / \mathrm{s}\). The driver wants to go directly across a river with a current speed of \(1.5 \mathrm{~m} / \mathrm{s}\). At what angle upstream should the boat be steered?

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