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The secondary coil of an ideal transformer has 450 turns, and the primary coil has 75 turns. (a) Is this transformer a (1) step-up or (2) step-down transformer? Explain your choice. (b) What is the ratio of the current in the primary coil to the current in the secondary coil? (c) What is the ratio of the voltage across the primary coil to the voltage in the secondary coil?

Short Answer

Expert verified
(a) Step-up transformer. (b) Current ratio is 1:6. (c) Voltage ratio is 1:6.

Step by step solution

01

Identifying Transformer Type

The type of transformer depends on the turn ratio: \( \frac{N_s}{N_p} \), where \(N_s\) is the number of turns in the secondary coil and \(N_p\) is the number of turns in the primary coil. Here, \(N_s = 450\) and \(N_p = 75\). Hence, the turn ratio is \( \frac{450}{75} = 6 \). Since the secondary turns are greater than the primary, it is a step-up transformer.
02

Calculating Current Ratio

For an ideal transformer, the current ratio is the inverse of the turn ratio: \( \frac{I_p}{I_s} = \frac{N_s}{N_p} \). Substituting the values, we get \( \frac{I_p}{I_s} = \frac{450}{75} = 6 \). Thus, the current in the primary coil is 1/6th of that in the secondary coil.
03

Calculating Voltage Ratio

The voltage ratio for an ideal transformer is equal to the turns ratio: \( \frac{V_p}{V_s} = \frac{N_p}{N_s} \). Using the given values, we have \( \frac{V_p}{V_s} = \frac{75}{450} = \frac{1}{6} \). So, the voltage in the primary coil is 1/6th of that in the secondary coil.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Turn Ratio
The turn ratio of a transformer is a fundamental concept to grasp. It represents the relationship between the number of turns in the secondary coil (N_s) and the number of turns in the primary coil (N_p). This is expressed as \( \frac{N_s}{N_p} \). In the given example, the secondary coil has 450 turns and the primary coil has 75 turns, giving us a turn ratio of \( \frac{450}{75} = 6 \).
The turn ratio is crucial because it directly affects both the voltage transformation and current transformation within the system. A higher turn ratio indicates that more energy is transferred between the coils, affecting how the voltage and current levels change from primary to secondary.
When considering the turn ratio:
  • A higher ratio suggests a greater increase in voltage
  • The current will decrease as the voltage increases
Understanding turn ratio aids in determining the type of transformer and its functioning.
Step-up Transformer
In this example, we are dealing with a step-up transformer. This type of transformer increases the voltage from the primary side to the secondary side. The key indicator of a step-up transformer is that the number of turns in the secondary coil (N_s) is greater than in the primary coil (N_p). The ratio \( \frac{N_s}{N_p} = 6 \) confirms this as the secondary coil has six times more turns than the primary.
A step-up transformer is widely used in applications requiring voltage amplification, as it effectively increases the voltage output while decreasing the current output, maintaining the same power level. In everyday use, this can be seen in electricity grid systems, where voltage needs to be increased for efficient long-distance transmission.
To summarize, step-up transformers:
  • Increase secondary voltage relative to primary
  • Decrease in current on the secondary side
  • Feature higher turns in secondary than in primary
This understanding helps to determine their applications and working principle.
Current Ratio
The current ratio in an ideal transformer provides insight into how the current changes across the primary and secondary coils. It is the inverse of the turn ratio. In mathematical terms, it's described by \( \frac{I_p}{I_s} = \frac{N_s}{N_p} \). In our example, the turn ratio is 6, so the current ratio will be \( \frac{1}{6} \).
This tells us that the current in the primary coil is one-sixth of the current in the secondary coil. This relationship is consistent with the law of conservation of energy, implying that as voltage increases, the current must decrease to conserve power (P = VI).
Key takeaways on current ratio include:
  • Inversely related to the turn ratio
  • Increased voltage leads to decreased current, and vice versa
  • Keeps power transmission efficient without energy loss
This fundamental knowledge is necessary to understand how transformations of electrical quantities occur in transformers.
Voltage Ratio
The voltage ratio is another critical concept for understanding transformers. It directly relates the primary and secondary voltages and is represented by the same ratio as the turn ratio: \( \frac{V_p}{V_s} = \frac{N_p}{N_s} \). Using our specific numbers, this results in \( \frac{75}{450} = \frac{1}{6} \), meaning the primary voltage is one-sixth of the secondary voltage.
In practical terms, this confirms the function of a step-up transformer, where the voltage is increased from primary to secondary. The power remains equal (assuming 100% efficiency in an ideal transformer), so increased voltage means reduced current.
Essential points about voltage ratio:
  • It is equal to the turn ratio
  • Higher secondary voltage corresponds to larger number of turns in the secondary
  • Voltage enhancement is crucial for various electrical systems
Understanding the voltage ratio is vital for designing systems that efficiently transform voltage levels, ensuring functional and safe electrical power distribution.

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Most popular questions from this chapter

Assume that a uniform magnetic field exists perpendicular to the plane of this page (into it) and has a strength of \(0.150 \mathrm{~T}\). Assume further that this field ends sharply at the paper's edges. A single circular loop of wire is also in the plane of the paper and moves across it from left to right at a speed of \(1.00 \mathrm{~m} / \mathrm{s}\). The loop has a radius of \(1.50 \mathrm{~cm}\). The loop starts with its center \(10.0 \mathrm{~cm}\) to the left of the left edge, in zero field, enters the field, then exits at the right edge back into zero field until its center is \(10.0 \mathrm{~cm}\) to the right of the right edge. (a) Make a sketch of the induced emf in the coil versus time, putting numbers on the time axis and taking positive emf to indicate clockwise direction and negative emf to indicate counterclockwise (the emf axis will not have any numbers on it.) (b) What is the average emf (magnitude) induced in the coil when it is (1) to the left of the left edge, (2) entering the left side of the field, (3) completely in the field region, (4) exiting the right field edge, and (5) out in the zero field region to the right of the right edge.

A solenoid of length \(40.0 \mathrm{~cm}\) is made of 10000 circular coils. It carries a steady current of 12.0 A. Near its center is placed a small, flat, circular metallic coil of 200 circular loops, each with a radius of \(2.00 \mathrm{~mm}\). This small coil is oriented so that it receives half of the maximum magnetic flux. A switch is opened in the solenoid circuit and its current drops to zero in \(25.0 \mathrm{~ms}\). (a) What was the initial flux through the small coil? (b) Determine the average induced emf in the small coil during the \(25.0 \mathrm{~ms}\). (c) If you look along the long axis of the solenoid so that the initial 12.0 A current is clockwise, determine the direction of the induced current in the small inner coil during the time the current drops to zero. (d) During the \(25.0 \mathrm{~ms}\), what was the average current in the small coil, assuming it has a resistance of \(0.15 \Omega ?\)

The primary coil of an ideal transformer is connected to a \(120-\mathrm{V}\) source and draws \(1.0 \mathrm{~A} .\) The secondary coil has 800 turns and supplies an output current of \(10 \mathrm{~A}\) to run an electrical device. (a) What is the voltage across the secondary coil? (b) How many turns are in the primary coil? (c) If the maximum power allowed by the device (before it is destroyed) is \(240 \mathrm{~W}\), what is the maximum input current to this transformer?

An ac generator operates at a rotational frequency of \(60 \mathrm{~Hz}\) and produces a maximum emf of \(100 \mathrm{~V}\). Assume that its output at \(t=0\) is zero. What is the instantaneous \(\mathrm{emf}(\mathrm{a})\) at \(t=1 / 240 \mathrm{~s} ?(\mathrm{~b})\) at \(t=1 / 120 \mathrm{~s} ?(\mathrm{c})\) at \(t ?\) (d) How much time elapses between successive 0 -volt outputs? (e) What maximum emf would this generator produce if it were operated, instead, at \(120 \mathrm{~Hz} ?\)

A circular loop (radius of \(20 \mathrm{~cm}\) ) is in a uniform magnetic field of \(0.15 \mathrm{~T}\). What angle(s) between the normal to the plane of the loop and the field would result in a flux with a magnitude of \(1.4 \times 10^{-2} \mathrm{~T} \cdot \mathrm{m}^{2} ?\)

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