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The primary coil of an ideal transformer is connected to a \(120-\mathrm{V}\) source and draws \(1.0 \mathrm{~A} .\) The secondary coil has 800 turns and supplies an output current of \(10 \mathrm{~A}\) to run an electrical device. (a) What is the voltage across the secondary coil? (b) How many turns are in the primary coil? (c) If the maximum power allowed by the device (before it is destroyed) is \(240 \mathrm{~W}\), what is the maximum input current to this transformer?

Short Answer

Expert verified
(a) 12 V, (b) 8000 turns, (c) 2.0 A.

Step by step solution

01

Understanding the Transformer Equation

For an ideal transformer, the ratio of the primary voltage \( V_p \) to the secondary voltage \( V_s \) is equal to the ratio of the number of turns in the primary coil \( N_p \) to the number of turns in the secondary coil \( N_s \), i.e., \( \frac{V_p}{V_s} = \frac{N_p}{N_s} \). Also, for conservation of power in an ideal transformer, \( V_p I_p = V_s I_s \).
02

Calculate Secondary Voltage

**Given:** Primary voltage \( V_p = 120 \text{ V} \), primary current \( I_p = 1.0 \text{ A} \), secondary current \( I_s = 10 \text{ A} \). Using \( V_p I_p = V_s I_s \) to find \( V_s \):\[ V_s = \frac{V_p I_p}{I_s} = \frac{120 \times 1}{10} = 12 \text{ V}. \]
03

Calculate Primary Turns

**Given:** Secondary turns \( N_s = 800 \). Using the relationship \( \frac{V_p}{V_s} = \frac{N_p}{N_s} \), and rearranging for \( N_p \):\[ N_p = \left(\frac{V_p}{V_s}\right) N_s = \left(\frac{120}{12}\right) \times 800 = 8000 \text{ turns}. \]
04

Determine Maximum Input Current

**Given:** Maximum power \( P = 240 \text{ W} \). Since \( P = V_p I_p \), solve for \( I_p \):\[ I_p = \frac{P}{V_p} = \frac{240}{120} = 2.0 \text{ A}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Transformer
An ideal transformer is a theoretical model of a transformer that exhibits perfect efficiency. It means that all the electrical power that enters the transformer on the primary side is transferred to the secondary side without any losses. In practice, actual transformers have some energy losses due to resistance, hysteresis and eddy currents, but in an ideal transformer, these are nonexistent.

The core idea of an ideal transformer revolves around two main principles: the voltage transformation and the conservation of electrical power. The voltage transformation is dictated by the turns ratio of the primary coil to the secondary coil. Meanwhile, the conservation of electrical power is maintained through the equation: \[ V_p I_p = V_s I_s \] where \( V_p \) and \( I_p \) are the voltage and current on the primary coil, and \( V_s \) and \( I_s \) are those on the secondary coil.
Electrical Power
In the context of transformers, electrical power is conserved between the primary and secondary coils, especially in an ideal transformer. Power in electrical systems is calculated using the formula:\[ P = VI \] where \( P \) is the power in watts, \( V \) is the voltage in volts, and \( I \) is the current in amperes.

When we discuss an ideal transformer, it means that the power input to the primary coil (\( V_p I_p \)) is equal to the power output from the secondary coil (\( V_s I_s \)). This fundamental aspect of transformers is what allows for the efficient transfer of power without loss. In real-world applications, keeping the power consistent across the transformer helps design systems that are efficient and cost-effective.
Voltage and Current Ratio
In a transformer, the voltage and current ratios are crucial for understanding how they function. These ratios stem from the principle of power conservation in transformers. Specifically, the relationship is characterized by:- **Voltage Ratio:** \( \frac{V_p}{V_s} = \frac{N_p}{N_s} \) - **Current Ratio:** Given the conservation of power, we have the current relationship: \( V_p I_p = V_s I_s \), simplifying to \( \frac{I_s}{I_p} = \frac{V_p}{V_s} \).

A higher turns ratio on the primary side compared to the secondary side will lead to a step-down transformer, resulting in lower voltage on the secondary side while increasing the current. Conversely, a higher number of turns on the secondary side results in a step-up transformer, increasing the voltage and reducing current.
Transformer Turns Ratio
The transformer turns ratio is an essential parameter that dictates the voltage transformation capability of a transformer. It is defined as the ratio of the number of turns in the primary coil to the number of turns in the secondary coil: \[ \text{Turns Ratio} = \frac{N_p}{N_s} \] The turns ratio fundamentally determines the increase or decrease in voltage across the coils.

For instance, in step-up transformers, the secondary coil has more turns than the primary, resulting in a higher output voltage compared to the input voltage. In contrast, step-down transformers have fewer turns in the secondary coil, thereby reducing the voltage. This principle outlines how altering the turns can adjust the transformer to exhibit either an increase or a decrease in voltage for various applications.

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Most popular questions from this chapter

In \(0.20 \mathrm{~s}\), a coil of wire with 50 loops experiences an average induced emf of \(9.0 \mathrm{~V}\) due to a changing magnetic field perpendicular to the plane of the coil. The radius of the coil is \(10 \mathrm{~cm}\), and the initial strength of the magnetic field is 1.5 T. Assuming that the strength of the field decreased with time, (a) what is the final strength of the field? (b) If the field strength had, instead, increased, what would its final value have been? (c) Explain a method whereby you could, in principle, tell whether the field was increasing or decreasing in magnitude.

A meteorologist for a TV station is using radar to determine the distance to a cloud. He notes that a time of \(0.24 \mathrm{~ms}\) elapses between the sending and the return of a radar pulse. How far away is the cloud?

(a) A square loop of wire with sides of length \(40 \mathrm{~cm}\) is in a uniform magnetic field perpendicular to its area. If the field's strength is initially \(100 \mathrm{mT}\) and it decays to zero in \(0.010 \mathrm{~s}\), what is the magnitude of the average emf induced in the loop? (b) What would be the average emf if the sides of the loop were only \(20 \mathrm{~cm} ?\)

A boy is traveling due north at a constant speed while carrying a metal rod. The rod's length is oriented in the east-west direction and is parallel to the ground. (a) There will be no induced emf when the rod is (1) at the equator, (2) near the Earth's magnetic poles, (3) somewhere between the equator and the poles. Why? (b) Assume that the Earth's magnetic field is \(1.0 \times 10^{-4} \mathrm{~T}\) near the North Pole and \(1.0 \times 10^{-5} \mathrm{~T}\) near the equator. If the boy runs with a speed of \(1.3 \mathrm{~m} / \mathrm{s}\) northward near each location, and the rod is \(1.5 \mathrm{~m}\) long, calculate the induced emf in the rod in each location.

Assume that a uniform magnetic field exists perpendicular to the plane of this page (into it) and has a strength of \(0.150 \mathrm{~T}\). Assume further that this field ends sharply at the paper's edges. A single circular loop of wire is also in the plane of the paper and moves across it from left to right at a speed of \(1.00 \mathrm{~m} / \mathrm{s}\). The loop has a radius of \(1.50 \mathrm{~cm}\). The loop starts with its center \(10.0 \mathrm{~cm}\) to the left of the left edge, in zero field, enters the field, then exits at the right edge back into zero field until its center is \(10.0 \mathrm{~cm}\) to the right of the right edge. (a) Make a sketch of the induced emf in the coil versus time, putting numbers on the time axis and taking positive emf to indicate clockwise direction and negative emf to indicate counterclockwise (the emf axis will not have any numbers on it.) (b) What is the average emf (magnitude) induced in the coil when it is (1) to the left of the left edge, (2) entering the left side of the field, (3) completely in the field region, (4) exiting the right field edge, and (5) out in the zero field region to the right of the right edge.

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