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Two long, parallel wires separated by \(50 \mathrm{~cm}\) each carry currents of \(4.0 \mathrm{~A}\) in a horizontal direction. Find the magnetic field midway between the wires if the currents are (a) in the same direction and (b) in opposite directions.

Short Answer

Expert verified
(a) 0 T, (b) 6.4 μT.

Step by step solution

01

Understanding the Problem

We have two parallel wires separated by a distance of 50 cm, each carrying a current of 4.0 A. We want to find the magnetic field at the midpoint between these wires for two scenarios: when the currents are in the same direction and when they are in opposite directions.
02

Use of Biot-Savart Law

The magnetic field due to a long, straight wire carrying current can be given by the Biot-Savart Law. The magnitude of the magnetic field at distance \(r\) from the wire is \( B = \frac{\mu_0 I}{2\pi r} \), where \( \mu_0 \) is the permeability of free space \( \left(4\pi \times 10^{-7} \frac{T\cdot m}{A}\right) \) and \( I \) is the current.
03

Calculate Magnetic Field from One Wire

Calculate the magnetic field at the midpoint (25 cm or 0.25 m away from each wire) due to one wire carrying 4.0 A: \[ B_1 = \frac{4\pi \times 10^{-7} \cdot 4.0}{2\pi \cdot 0.25} = \frac{16 \times 10^{-7}}{\pi \cdot 0.25} \approx 3.2 \times 10^{-6} \text{T}. \]
04

Scenario A: Currents in the Same Direction

When the currents are in the same direction, the magnetic fields due to both wires at the midpoint will have opposite directions (according to the right-hand rule). Thus they will subtract. Therefore, the net magnetic field at the midpoint is \( B_{net} = B_1 - B_1 = 0 \text{ T}. \)
05

Scenario B: Currents in Opposite Directions

When the currents are in opposite directions, the magnetic fields at the midpoint will have the same direction and thus add up. So the net magnetic field is \( B_{net} = B_1 + B_1 = 2 \times 3.2 \times 10^{-6} \text{ T} = 6.4 \times 10^{-6} \text{ T}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot-Savart Law
The Biot-Savart Law is a fundamental principle in electromagnetism that describes how electric currents create magnetic fields. It is crucial for understanding the behavior of magnetic fields around current-carrying wires. The Biot-Savart Law states that the magnetic field, \( B \), due to a current element is directly proportional to the current, \( I \), and inversely proportional to the distance, \( r \), from the current element. For a long, straight wire carrying a uniform current, the magnetic field at a perpendicular distance \( r \) from the wire can be expressed as:\[ B = \frac{\mu_0 I}{2\pi r} \]where:
  • \( \mu_0 \) is the permeability of free space \( (4\pi \times 10^{-7} \frac{T\cdot m}{A}) \).
  • \( I \) is the current passing through the wire.
  • \( r \) is the distance from the wire to the point where the magnetic field is being calculated.
The Biot-Savart Law helps us calculate how strong the magnetic field will be at any point around a wire based on these parameters. It shows how changes in current or distance influence the magnetic field, making it a pivotal tool for analyzing situations involving electromagnetic fields.
parallel currents
Parallel currents occur when two or more wires carry electrical currents either in the same or opposite directions, aligned parallel to each other. Understanding the interactions between these currents is key in many electromagnetic applications. When dealing with parallel currents, it's important to remember how they affect magnetic fields: - **Same Direction:** When the currents in the wires are flowing in the same direction, their magnetic fields at any point between the wires are in opposing directions. This means the fields cancel each other out at the exact midpoint between the wires, resulting in a net magnetic field of zero. - **Opposite Direction:** On the other hand, when the currents flow in opposite directions, their magnetic fields enhance each other between the wires. The net magnetic field at the midpoint is essentially the sum of the fields from each wire. This interaction is vital in crafting circuits and understanding phenomena such as magnetic levitation and coil configurations where parallel currents play significant roles. Both scenarios demonstrate the fundamental principle that current direction significantly impacts the resultant magnetic field in a system.
right-hand rule
The right-hand rule is a convenient mnemonic used to determine the direction of the magnetic field produced by a current-carrying wire. This simple yet effective tool helps in visualizing the orientation of magnetic fields in relation to the direction of current flow. To use the right-hand rule, imagine holding the wire in your right hand such that: - Your thumb points in the direction of the current. - Your fingers naturally curl around the wire. The direction your fingers curl represents the direction of the magnetic field lines encircling the wire. This rule makes it easier to predict and understand how magnetic fields behave around wires and is particularly useful when analyzing multiple currents. In scenarios involving parallel currents, such as in this exercise, the right-hand rule helps visualize how reversing the current direction in one wire changes the direction of the magnetic field it produces. This intuitive approach aids students and professionals alike in grasping the interactions between electricity and magnetism more profoundly.

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Most popular questions from this chapter

A \(2.0-\mathrm{m}\) length of straight wire carries a current of 20 A in a uniform magnetic field of \(50 \mathrm{mT}\) whose direction is at an angle of \(37^{\circ}\) from the direction of the current. Find the force on the wire.

A beam of protons is accelerated to a speed of \(5.0 \times 10^{6} \mathrm{~m} / \mathrm{s}\) in a particle accelerator and emerges horizontally from the accelerator into a uniform magnetic field. What magnetic field (give its direction and magnitude) oriented perpendicularly to the velocity of the proton would cancel the force of gravity and keep the beam moving exactly horizontally?

An ionized deuteron (a bound proton-neutron system with a net \(+e\) charge) passes through a velocity selector whose perpendicular magnetic and electric fields have magnitudes of \(40 \mathrm{mT}\) and \(8.0 \mathrm{kV} / \mathrm{m}\), respectively. Find the speed of the ion.

A cylindrical solenoid \(10 \mathrm{~cm}\) long has 3000 turns of wire and carries a current of 5.0 A. A second solenoid, consisting of 2000 turns of wire and the same length as the first solenoid, surrounds it and is concentric (shares a common central axis) with it. The outer coil carries a current of 10 A in the same direction as the current in inner one. (a) Find the magnetic field near their common center. (b) What current in the second solenoid (magnitude and relative direction) would make the net field strength at the center twice that of the first solenoid alone? (c) What current in the second solenoid (magnitude and relative direction) would result in zero net magnetic field near their common center?

In a mass spectrometer, a doubly charged ion having a particular velocity is selected by using a magnetic field of \(100 \mathrm{mT}\) perpendicular to an electric field of \(1.0 \mathrm{kV} / \mathrm{m}\). This same magnetic field is then used to deflect the ion in a circular path with a radius of \(15 \mathrm{~mm}\). Find (a) the mass of the ion and (b) the kinetic energy of the ion. (c) Does the kinetic energy of the ion increase in the circular path? Explain.

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