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A \(2.0-\mathrm{m}\) length of straight wire carries a current of 20 A in a uniform magnetic field of \(50 \mathrm{mT}\) whose direction is at an angle of \(37^{\circ}\) from the direction of the current. Find the force on the wire.

Short Answer

Expert verified
The force on the wire is approximately 1.2 N.

Step by step solution

01

Understanding the Problem

We have a straight wire carrying a current of 20 A and placed in a uniform magnetic field of 50 mT. The direction of the magnetic field is at an angle of \(37^{\circ}\) to the direction of the current. We need to find the magnetic force acting on the wire.
02

Identify the Formula Needed

The magnetic force \( F \) on a current-carrying wire in a magnetic field is given by the formula: \( F = I \cdot L \cdot B \cdot \sin(\theta) \), where \( I \) is the current, \( L \) is the length of the wire, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the magnetic field and the direction of the current.
03

Substitute Given Values

Substitute the given values into the formula: \( I = 20 \) A, \( L = 2.0 \) m, \( B = 50 \) mT or \( 0.050 \) T, and \( \theta = 37^{\circ} \). Thus, \( F = 20 \cdot 2.0 \cdot 0.050 \cdot \sin(37^{\circ}) \).
04

Calculate \( \sin(37^{\circ}) \)

Use a calculator to find \( \sin(37^{\circ}) \). We find that \( \sin(37^{\circ}) \approx 0.6018 \).
05

Compute the Force

Substitute \( \sin(37^{\circ}) \approx 0.6018 \) into the equation: \[ F = 20 \cdot 2.0 \cdot 0.050 \cdot 0.6018 \]. Calculate the force \( F \), getting \( F = 1.2036 \) N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current-Carrying Wire
In electrical circuits and magnetic phenomena, a current-carrying wire is fundamental. It refers to a wire through which an electric current is flowing. This current is what interacts with magnetic fields to produce magnetic forces, an essential concept in electromagnetism.
A larger current usually leads to a more significant interaction with the magnetic field, and hence a greater force is exerted on the wire. Current is measured in amperes (A), and in our example, the wire carries a 20 A current.
  • Current (I): The flow of electric charge, measured in amperes.
  • Direction: The way in which the current is flowing, important for determining the angle of incidence with a magnetic field.
The interaction between a current-carrying wire and an external magnetic field is what leads to the generation of a force, which can be calculated using specific equations. It’s crucial to understand these interactions to grasp how motors, generators, and numerous electronic devices function.
Every time a current flows through a wire in a magnetic field, it experiences a force, which depends on several factors including the strength of the current and the orientation of the wire.
Uniform Magnetic Field
A uniform magnetic field is a magnetic field that has the same magnitude and direction at every point within it. This is an important concept because it simplifies calculations involving magnetic force, allowing us to treat the force as consistent along the length of a wire. In simple terms, this makes mathematics more straightforward.
In the given problem, the magnetic field strength is 50 milliteslas (mT). To use this in calculations, it’s often converted to Tesla, the SI unit for magnetic field strength, by dividing by 1000. So, 50 mT becomes 0.050 T.
  • Magnetic Field (B): A vector field surrounding magnets, electric currents, or changing electric fields, measured in Teslas (T).
  • Uniformity: Ensures consistent interaction with the wire over its length.
Uniform magnetic fields are typically idealized situations, but they can be approximated in reality using certain configurations of magnets or coils. They are particularly useful in solving exercises because they allow the simplification of complex interactions to more manageable equations.
Angle of Incidence
The angle of incidence, when discussing magnetic fields and currents, is the angle between the direction of the current and the direction of the magnetic field. This angle is crucial because it determines the magnitude of the force exerted on the current-carrying wire.
According to the formula for magnetic force, the force is directly proportional to the sine of the angle of incidence, \( F = I \cdot L \cdot B \cdot \sin(\theta) \).
In our problem, the angle is 37 degrees. The sine of this angle, approximately 0.6018, is used in calculating the force. Here's why the angle is crucial:
  • Maximal interaction occurs when the field and current are perpendicular (\(\theta = 90^{\circ}\)).
  • No force acts if they are parallel (\(\theta = 0^{\circ}\) or \(\theta = 180^{\circ}\)).
Understanding this concept helps predict and control how much force acts on a wire in various setups. Angles affect many scientific and engineering applications, from designing electric motors to interpreting geological magnetic data.

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Most popular questions from this chapter

A beam of protons exits from a particle accelerator due east at a speed of \(3.0 \times 10^{5} \mathrm{~m} / \mathrm{s}\). The protons then enter a uniform magnetic field of magnitude \(0.50 \mathrm{~T}\) that is oriented at \(37^{\circ}\) above the horizontal relative to the beam direction. (a) What is the initial acceleration of a proton as it enters the field? (b) What if the magnetic field were angled at \(37^{\circ}\) below the horizontal instead? (c) If the beam were made of electrons traveling at the same speed rather than protons and the field were angled upward at \(37^{\circ},\) would there be any difference in the force on the electrons compared to the protons? Explain. (d) In part (c), what would be the ratio of the acceleration of an electron to that of a proton?

A straight, horizontal segment of wire carries a current in the \(+x\) -direction in a magnetic field that is directed in the \(-z\) -direction. (a) Is the magnetic force on the wire directed in the \((1)-x-,(2)+z-,(3)+y-,\) or (4) \(-y\) -direction? Explain. (b) If the wire is \(1.0 \mathrm{~m}\) long and carries a current of \(5.0 \mathrm{~A}\) and the magnitude of the magnetic field is \(0.30 \mathrm{~T}\), what is the magnitude of the force on the wire?

A horizontal magnetic field of \(1.0 \times 10^{-4} \mathrm{~T}\) is at an angle of \(30^{\circ}\) to the direction of the current in a straight, horizontal wire \(75 \mathrm{~cm}\) long. If the wire carries a current of \(15 \mathrm{~A}\), (a) what is the magnitude of the force on the wire? (b) What angle(s) would be required for the force to be half the value found in part (a), assuming nothing else is changed?

In a physics lab, a student discovers that the magnitude of the magnetic field at a certain distance from a long wire is \(4.0 \mu \mathrm{T}\). If the wire carries a current of \(5.0 \mathrm{~A}\), what is the distance of the magnetic field from the wire?

1 lies on the \(x\) -axis and its north end is at \(x=+1.0 \mathrm{~cm},\) while its south end is at… # Two bar very narrow magnets are located in the \(x\) -y \(y\) plane. Magnet #1 lies on the \(x\) -axis and its north end is at \(x=+1.0 \mathrm{~cm},\) while its south end is at \(x=+5.0 \mathrm{~cm}\) Magnet \(\\# 2\) lies on the \(y\) -axis and its north end is at \(y=+1.0 \mathrm{~cm},\) while its south end is at \(y=+5.0 \mathrm{~cm}\) Magnet #2 produces a magnetic field that is only onehalf the magnitude of magnet #1. (a) In what direction would a compass point if it were located at the origin? (b) Repeat part (a) for the situation where magnet #1 is reversed in polarity.

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