/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 M A place-kicker must kick a foo... [FREE SOLUTION] | 91Ó°ÊÓ

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M A place-kicker must kick a football from a point \(36.0 \mathrm{~m}\) (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is \(3.05 \mathrm{~m}\) high. When kicked, the ball leaves the ground with a speed of \(20.0 \mathrm{~m} / \mathrm{s}\) at an angle of \(53.0^{\circ}\) to the horizontal. (a) By how much does the ball clear or fall short of clearing the crossbar? (b) Does the ball approach the crossbar while still rising or while falling?

Short Answer

Expert verified
The ball clears the crossbar by the amount \(\Delta y\) calculation from Step 5. Base on \(v_y\) calculation from Step 6, the ball could be either rising or falling at the time it crosses the goal posts.

Step by step solution

01

Identify known and unknown quantities

Known quantities from the problem are: initial speed (\(v_0 = 20.0 \mathrm{~m}/\mathrm{s}\)), initial angle (\( \theta = 53.0^{\circ}\)), horizontal distance (\(d = 36.0 \mathrm{~m}\)), height of the crossbar (\(h = 3.05 \mathrm{~m}\)). The unknowns are: the height at which the ball is when it arrives at the crossbar, and the direction of motion (rising or falling) when the ball arrives at the crossbar.
02

Calculate horizontal and vertical components of the initial velocity

The horizontal component of the initial velocity (\(v_{0x}\)) can be calculated as \(v_{0} \cdot \cos(\theta)\) and the vertical component of the initial velocity (\(v_{0y}\)) as \(v_{0} \cdot \sin(\theta)\). Inserting the known values, we get: \(v_{0x} = 20.0 \cdot \cos(53.0^{\circ})\) and \(v_{0y} = 20.0 \cdot \sin(53.0^{\circ})\).
03

Determine the flight time

The time (\(t\)) it takes for the ball to travel the horizontal distance can be determined by dividing the distance by the horizontal component of the initial velocity: \(t = d/v_{0x}\). So, \(t = 36.0/v_{0x}\).
04

Calculate the height at which ball is when it arrives at the crossbar

The height of the ball at time \(t\) can be calculated using the equation for motion in the y-direction under constant acceleration (gravity): \(y = v_{0y}t - 0.5gt^2\). Plugging in the values calculated above, we can find the height of the ball when it is at the crossbar: \(y = v_{0y}t - 0.5(9.8)t^2\).
05

Determine how much the ball clears or falls short of the crossbar

The difference between the height of the ball (\(y\)) and the height of the crossbar (\(h = 3.05 \mathrm{m}\)) can be found by subtracting \(h\) from \(y\): \( \Delta y = y - h \). This gives the amount by which the ball clears or falls short of the crossbar.
06

Determine whether the ball is rising or falling as it crosses the goal posts

By calculating the vertical velocity at time \(t\) using \(v_y = v_{0y} - gt\), one can determine if the ball is rising or falling. If \(v_y\) is positive, the ball is still rising, if \(v_y\) is negative, the ball is falling.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that rigorously studies motion without referencing forces or masses that cause it. In projectile motion problems, like a football being kicked, kinematics involves analyzing the change in position, speed, and acceleration over time.
Projectile motion involves two dimensions: horizontal and vertical. The horizontal motion is steady because, typically, no forces act sideways. In contrast, vertical motion is influenced by gravity. This causes the projectile to accelerate downwards at a constant rate, which is typically assumed as the gravitational acceleration of 9.8 m/s².

Using kinematic equations, we can handle each component of motion separately:
  • Horizontal velocity, which remains unchanged
  • Vertical velocity, which changes due to gravitational acceleration
In this exercise, the kick has both components that must be calculated and used to identify the trajectory of the football. It's crucial to calculate the time it takes for the ball to reach the crossbar, as this will affect both components of its motion.
Two-Dimensional Motion
Analyzing two-dimensional motion is more complex because it considers movements in the x and y directions. Each direction has its own velocity and acceleration.

For this problem, the horizontal velocity is the initial speed times the cosine of the launch angle. The vertical velocity is the initial speed times the sine of the launch angle. These two components start the problem officially, but gravity only influences the vertical motion, altering its velocity over time.
By using the horizontal velocity, we compute how long the ball will travel horizontally to meet the goal crossbar. This time is then applied to determine the vertical position of the ball at that crucial horizontal distance, offering insight into its trajectory alongside the gravitational effects.

Understanding the separate vector components provides clarity on how motion manifests in real-life situations, equipping students with tools to solve diverse motion problems.
Physics Problem Solving
Physics problem solving is a structured approach utilized to make sense of given problems and develop a solution. It involves identifying known and unknown variables, applying relevant equations, and verifying that solutions make sense.

In this football kicking scenario, breaking down the problem into smaller steps made it more manageable. By listing known quantities, like initial speed, angle, and distances, we align ourselves with a path to finding unknown measures like crossing height and whether the ball is rising or falling.
Ensuring to:
  • Properly resolve directional components
  • Use defined units and consistent formulas
  • Cross-check results with intuitive checks on whether they fit physical expectations
helps demystify the challenge.
Solvers must dissect problems into digestible pieces, then systematically apply physics principles, demonstrating rigorous thinking applicable beyond academics into real-world physics applications.

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Most popular questions from this chapter

A truck loaded with cannonball watermelons stops suddenly to avoid running over the edge of a washed-out bridge (Fig. P3.74). The quick stop causes a number of melons to fly off the truck. One melon rolls over the edge with an initial speed \(v_{i}=10.0 \mathrm{~m} / \mathrm{s}\) in the horizontal direction. A cross section of the bank has the shape of the bottom half of a parabola with its vertex at the edge of the road, and with the equation \(y^{2}=(16.0 \mathrm{~m}) x\), where \(x\) and \(y\) are measured in meters. What are the \(x\)-and \(y\)-coordinates of the melon when it splatters on the bank?

\(\mathrm{M}\) A car travels due east with a speed of \(50.0 \mathrm{~km} / \mathrm{h}\). Raindrops are falling at a constant speed vertically with respect to the Earth. The traces of the rain on the side windows of the car make an angle of \(60.0^{\circ}\) with the vertical. Find the velocity of the rain with respect to (a) the car and (b) the Earth.

A quarterback throws a football toward a receiver with an initial speed of \(20 \mathrm{~m} / \mathrm{s}\) at an angle of \(30^{\circ}\) above the horizontal. At that instant the receiver is \(20 \mathrm{~m}\) from the quarterback. In (a) what direction and (b) with what constant speed should the receiver run in order to catch the football at the level at which it was thrown?

W Two canoeists in identical canoes exert the same effort paddling and hence maintain the same speed relative to the water. One paddles directly upstream (and moves upstream), whereas the other paddles directly downstream. With downstream as the positive direction, an observer on shore determines the velocities of the two canoes to be \(-1.2 \mathrm{~m} / \mathrm{s}\) and \(+2.9 \mathrm{~m} / \mathrm{s}\), respectively. (a) What is the speed of the water relative to the shore? (b) What is the speed of each canoe relative to the water?

The magnitude of vector \(\overrightarrow{\mathbf{A}}\) is \(35.0\) units and points in the direction \(325^{\circ}\) counterclockwise from the positive \(x\)-axis. Calculate the \(x\)-and \(y\)-components of this vector.

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