/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 The magnitude of vector \(\overr... [FREE SOLUTION] | 91Ó°ÊÓ

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The magnitude of vector \(\overrightarrow{\mathbf{A}}\) is \(35.0\) units and points in the direction \(325^{\circ}\) counterclockwise from the positive \(x\)-axis. Calculate the \(x\)-and \(y\)-components of this vector.

Short Answer

Expert verified
The x-component of the vector is \(Ax = 35\cos{325^\circ}\) and the y-component of the vector is \(Ay = 35\sin{325^\circ}\). Please use a calculator to find the values of \(Ax\) and \(Ay\).

Step by step solution

01

Identify the given information

The magnitude of vector A is given as 35.0 units. The direction of vector A is given as 325 degrees counterclockwise from the positive x-axis.
02

Find the x-component of the vector

The x-component (Ax) of a vector is given by the formula \(Ax = A\cos{\Theta}\), where A is the magnitude of the vector and \(\Theta\) is the angle it makes with the positive x-axis. Here, A = 35.0 units and \(\Theta = 325^{\circ}\). Plugging these values into the formula, we have \(Ax = 35\cos{325^\circ}\). Use a calculator to find the value of \(Ax\).
03

Find the y-component of the vector

The y-component (Ay) of a vector is given by the formula \(Ay = A\sin{\Theta}\), where A is the magnitude of the vector and \(\Theta\) is the angle it makes with the positive x-axis. Continuing from step 2, we have \(Ay = 35\sin{325^\circ}\). Use a calculator to find the value of \(Ay\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnitude of Vector
The magnitude of a vector is a crucial concept in understanding vectors. It refers to the length or size of the vector, which is always a positive value. You can imagine it as the amount of force, displacement, or any vector quantity present. In physics, this is often represented as the distance from the beginning to the endpoint of the vector, not considering the direction.
To calculate the magnitude, you typically use the formula for the distance between two points in space, although in many cases, it is given directly as in our example of 35.0 units for vector \(\overrightarrow{\mathbf{A}}\).
Understanding the magnitude helps in determining how strong or prominent the vector is in comparison to others. It provides context on the scale of the forces or movements involved.
Vector Components
Vector components are parts of a vector that break it down into mutually perpendicular directions, commonly along the x and y axes in two-dimensional space. Analyzing a vector in terms of its components makes it easier to understand and manipulate, especially in physics where calculations need precise directions.
The vector \(\overrightarrow{\mathbf{A}}\)'s components are derived using trigonometric functions. The x-component (Ax) represents how much of the vector lies along the x-axis, and the y-component (Ay) shows the vector's contribution along the y-axis.
For instance, for vector \(\overrightarrow{\mathbf{A}}\) with a magnitude of 35.0 units and direction at 325° from the positive x-axis, the components are derived as:
  • \(A_x = A\cos{\Theta} = 35\cos{325^\circ}\)
  • \(A_y = A\sin{\Theta} = 35\sin{325^\circ}\)
Understanding these components helps in solving complex problems involving motion and forces by focusing on one direction at a time.
Trigonometry in Physics
Trigonometry is a fundamental mathematical tool used extensively in physics to solve problems related to angles and lengths. It plays a pivotal role when dealing with vectors, as vectors inherently involve directions and magnitudes.
By applying trigonometric functions like sine, cosine, and tangent, you can break down a vector into its components, analyze forces, and determine angles. In the context of our vector \(\overrightarrow{\mathbf{A}}\), trigonometry helps determine how much of the vector points in the specified direction using its angle from the x-axis.
Let's say you have a vector at an angle \(\Theta\) from the positive x-axis:
  • The cosine function (\(\cos\Theta\)) is used to find the x-component: \(A_x = A\cos\Theta\)
  • The sine function (\(\sin\Theta\)) is used for the y-component: \(A_y = A\sin\Theta\)
Grasping these concepts with trigonometry allows you to solve physics problems related to vectors efficiently, especially where directions and magnitudes are crucial.

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