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A wood stove is used to heat a single room. The stove is cylindrical in shape, with a diameter of \(40.0 \mathrm{~cm}\) and a length of \(50.0 \mathrm{~cm}\), and operates at a temperature of \(400^{\circ} \mathrm{F}\). (a) If the temperature of the room is \(70.0^{\circ} \mathrm{F}\), determine the amount of radiant energy delivered to the room by the stove each second if the emissivity is \(0.920\). (b) If the room is a square with walls that are \(8.00 \mathrm{ft}\) high and \(25.0 \mathrm{ft}\) wide, determine the \(R\)-value needed in the walls and ceiling to maintain the inside temperature at \(70.0^{\circ} \mathrm{F}\) if the outside temperature is \(32.0^{\circ} \mathrm{F}\). Note that we are ignoring any heat conveyed by the stove via convection and any energy lost through the walls (and windows!) via convection or radiation.

Short Answer

Expert verified
The radiant energy delivered by stove is approximately 6865J/s and the R-value necessary to maintain an inside temperature of 70掳F is around 0.323 ft虏.掳F.hr/W.

Step by step solution

01

Conversion of units

First, transform the units of temperature to absolute scale. i.e. Kelvin. The conversion is given as \( K = (F-32)\times(5/9) + 273.15 \) \( T_{stove} = (400-32)\times(5/9) + 273.15 = 477.593K \) \( T_{room} = (70-32)\times(5/9) + 273.15 = 294.261K \)
02

Calculation of energy radiated by stove

To solve for radiant energy delivered by the stove, use Stefan-Boltzmann law that relates the power radiated from a black body in terms of temperature. This assumes the wood stove is a perfect cylinder so this calculation will be the maximum possible. This law is given as \(P= 蔚蟽AT^4 \), where 蟽 is the Stefan-Boltzmann constant \(5.67 \times 10^{-8} W/m虏.K鈦碶), and \(A\) is the surface area of the stove given by the formula for the surface area of a cylinder \(A = 2蟺r虏 + 2蟺rh\) where \(h\) is the height. Calculate the area \(A = 2\pi \times(0.40/2)^2 + 2\pi \times(0.40/2) \times0.50 = 0.94 m虏\). Now calculate the power \( P = 蔚蟽AT_{stove}^4 = 0.92 \times5.67\times10^{-8} \times0.94 \times477.593^4 = 6864.77 W \) or 6864.77 J/s.
03

Calculation of the required R-value

To find the required R-value, recall that the rate of thermal energy via the walls and the ceiling is given by \(P = \Delta T / R \times A\), where \(螖T\) is the difference in temperature. To keep the room at room temperature, the loss of thermal energy should be equal to the amount of thermal energy being provided by the stove. That gives us the equation \( 6864.77 = (70 - 32) * A / R \). Here, the area A is the surface area of all the walls and the ceiling, which is \(A = 4 * 25 * 8 + 25 * 25 = 850 ft虏 = 78.9685 m虏\). Now, solve for R. \( R = (70 - 32) * 78.9868 / 6864.77 = 0.323 ft虏.掳F.hr/W \).
04

Final Answer

So, the wood stove delivers approximately 6865 J/s of energy to the room, and the necessary R-value for the insulation is approximately 0.323 ft虏.掳F.hr/W to maintain an inside temperature of 70掳 F.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stefan-Boltzmann Law
The Stefan-Boltzmann law is a fundamental principle in the study of heat transfer, particularly radiative heat transfer. It relates the power radiated by an object to its temperature. More precisely, it helps to determine how much energy an object emits in the form of thermal radiation due to its temperature. The equation for this law is given by:
  • \( P = \epsilon \sigma A T^4 \)
Where:
  • \( P \) is the power emitted, in watts.
  • \( \epsilon \) is the emissivity of the material, indicating how efficiently a surface emits thermal radiation compared to a perfect black body.
  • \( \sigma \) is the Stefan-Boltzmann constant \((5.67 \times 10^{-8} \, \text{W/m}^2\text{K}^4)\).
  • \( A \) is the surface area of the object.
  • \( T \) is the absolute temperature in Kelvin.
In the exercise, the wood stove's temperature in Kelvin was used along with its surface area and emissivity to calculate the energy radiated each second. This law shows us the dependence of radiated energy on the fourth power of temperature, making it clear that even small variations in temperature can drastically change the emitted energy.
Thermal Insulation
Thermal insulation plays a crucial role in managing heat transfer in buildings and environments. It prevents heat from entering or leaving a space, ensuring temperature stability and energy efficiency. Improved insulation can help reduce energy loss, thereby conserving energy and lowering heating or cooling costs. In the context of the problem, insulation is key to maintaining a warm room by preventing the heat generated by the stove from escaping through the walls and ceiling. Thermal insulation can be made more effective by selecting materials with low thermal conductivity, which slows down the transfer of heat. This is crucial in keeping indoor spaces comfortable irrespective of outside conditions. In a well-insulated room, less energy is required to maintain a comfortable temperature, translating to cost savings and increased comfort.
R-value
The R-value is a measure of how well a material resists the conduction of heat. It is a crucial concept when considering insulation and energy efficiency in buildings. The higher the R-value, the better the material insulates. The units for R-value are typically \( \text{ft}^2 \cdot 掳\text{F} \cdot \text{hr/W} \), which indicate the material's resistance to heat flow over a specified area.In the problem example, the R-value needed was calculated to ensure the room maintained a set temperature despite differences between the inside and outside conditions. This is important because a proper R-value can help determine the thickness and type of insulation material required to achieve the desired thermal performance, especially in extreme weather conditions. Understanding and calculating R-value helps builders and homeowners select the best materials for efficient thermal management, contributing to overall energy savings and comfort.

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Most popular questions from this chapter

A thermopane window consists of two glass panes, each \(0.50 \mathrm{~cm}\) thick, with a \(1.0-\mathrm{cm}\)-thick sealed layer of air in between. (a) If the inside surface temperature is \(23^{\circ} \mathrm{C}\) and the outside surface temperature is \(0.0^{\circ} \mathrm{C}\), determine the rate of energy transfer through \(1.0 \mathrm{~m}^{2}\) of the window. (b) Compare your answer to (a) with the rate of energy transfer through \(1.0 \mathrm{~m}^{2}\) of a single \(1.0-\mathrm{cm}\) thick pane of glass. Disregard surface air layers.

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The highest recorded waterfall in the world is found at Angel Falls in Venezuela. Its longest single waterfall has a height of \(807 \mathrm{~m}\). If water at the top of the falls is at \(15.0^{\circ} \mathrm{C}\), what is the maximum temperature of the water at the bottom of the falls? Assume all the kinetic energy of the water as it reaches the bottom goes into raising the water's temperature.

A steam pipe is covered with \(1.50-\mathrm{cm}\)-thick insulating material of thermal conductivity \(0.200 \mathrm{cal} / \mathrm{cm} \cdot{ }^{\circ} \mathrm{C} \cdot \mathrm{s}\). How much energy is lost every second when the steam is at \(200^{\circ} \mathrm{C}\) and the surrounding air is at \(20.0^{\circ} \mathrm{C}\) ? The pipe has a circumference of \(800 \mathrm{~cm}\) and a length of \(50.0 \mathrm{~m}\). Neglect losses through the ends of the pipe.

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