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A thermopane window consists of two glass panes, each \(0.50 \mathrm{~cm}\) thick, with a \(1.0-\mathrm{cm}\)-thick sealed layer of air in between. (a) If the inside surface temperature is \(23^{\circ} \mathrm{C}\) and the outside surface temperature is \(0.0^{\circ} \mathrm{C}\), determine the rate of energy transfer through \(1.0 \mathrm{~m}^{2}\) of the window. (b) Compare your answer to (a) with the rate of energy transfer through \(1.0 \mathrm{~m}^{2}\) of a single \(1.0-\mathrm{cm}\) thick pane of glass. Disregard surface air layers.

Short Answer

Expert verified
The rate of energy transfer through a thermopane window is less than that of a single pane window. This shows the insulating effect of the air layer in the thermopane window, reducing the energy loss as compared to a single pane glass.

Step by step solution

01

Compute the Rate of Energy Transfer through Thermopane Window

To calculate the rate of heat flow (\(Q/t\)), we use the formula for heat conduction: \(Q/t = K A (T2-T1)/d\), where \(K\) is thermal conductivity, \(A\) is area, \(T2\) and \(T1\) are the temperatures, and \(d\) is the thickness. For glass, the thermal conductivity (\(K\)) is \(0.8 \ W/(m \cdot K)\) and for air it is \(\approx 0.024 \ W/(m \cdot K)\). Convert all thicknesses to meters for consistency. The total thickness of the window is \(2*0.005m + 0.01m = 0.02m\). The total thermal conductivity will be considered in parallel conduction where there are two glass windows separated by air. So, use the formula for parallel conduction and calculate the rate of transfer.
02

Compute the Rate of Energy Transfer through Single Pane of Glass

Now, let's use the same formula for heat conduction to find the rate for a single pane of glass. We know that the thickness of a single pane is \(0.01 m\) and we disregard the effect of air layers. Thermal conductivity for glass (\(K\)) is \(0.8 \ W/(m \cdot K)\).
03

Compare the rates of energy transfer

Compare the two rates of energy transfer calculated in previous steps to understand the difference in energy loss due to single pane glass vs. thermopane window.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermopane Window
A thermopane window is a specialized type of window designed to improve insulation. It consists of two glass panes separated by a space filled with air, sometimes also an inert gas like argon. In our exercise, we are looking at a window with a 1 cm-thick layer of air sandwiched between two 0.5 cm-thick glass panes. Thermopane windows are excellent at reducing heat loss because of the insulating air layer between the glass panes. This layer acts as a barrier to heat conduction, where heat must pass through multiple layers with different thermal properties. By design, these windows offer much better insulation than single-glazed windows. This contributes to their popularity in areas where energy efficiency and maintaining indoor temperature are necessary considerations.
Thermal Conductivity
Thermal conductivity is a material's ability to conduct heat. It is denoted by the symbol \(K\) and has units of \(W/(m \cdot K)\). The higher the thermal conductivity, the more effective a material is at conducting heat.In the context of thermopane windows, both glass and air play different roles:
  • Glass: With a thermal conductivity of \(0.8 \ W/(m \cdot K)\), glass conducts heat better but also allows it to escape more readily compared to other materials.
  • Air: The air layer has a much lower thermal conductivity, \(\approx 0.024 \ W/(m \cdot K)\), making it an excellent insulator by slowing down the transfer of heat between the two panes of glass.
Understanding thermal conductivity is essential for designing windows that reduce heating and cooling costs by minimizing unwanted heat flow.
Energy Transfer Rate
The energy transfer rate, also known as the rate of heat flow, tells us how quickly heat passes through a material. We use the formula for heat conduction \(Q/t = K A (T2-T1)/d\), where:
  • \(Q/t\): rate of heat transfer
  • \(K\): thermal conductivity
  • \(A\): area through which heat is being transferred
  • \(T2-T1\): temperature difference across the material
  • \(d\): thickness of the material
For the thermopane window, heat flow involves both glass and air components. This setup requires using a parallel conduction approach because the window consists of layers instead of a single type of material. The total rate of energy transfer will emphasize the air's insulating properties, leading to significantly less heat loss compared to a single pane of glass.
Temperature Difference
Temperature difference plays a critical role in calculating the rate of energy transfer. It represents the driving force for heat flow from the warmer side to the cooler side.In our exercise, we are considering an indoor temperature of \(23^{\circ} \mathrm{C}\) and an outdoor temperature of \(0.0^{\circ} \mathrm{C}\). This results in a temperature difference of \(23^{\circ} \mathrm{C}\), which greatly impacts how much heat is being transferred through the window.A larger temperature difference will generally increase the rate of energy transfer, while a smaller difference will reduce heat flow. Therefore, managing temperature difference across windows is a key factor in achieving better energy efficiency in buildings.

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Most popular questions from this chapter

A \(75-\mathrm{g}\) ice cube at \(0^{\circ} \mathrm{C}\) is placed in \(825 \mathrm{~g}\) of water at \(25^{\circ} \mathrm{C}\). What is the final temperature of the mixture?

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