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We can roughly model a gymnastic tumbler as a uniform solid cylinder of mass \(75 \mathrm{~kg}\) and diameter \(1.0 \mathrm{~m}\). If this tumbler rolls forward at 0.50 rev \(/ \mathrm{s}\), (a) how much total kinetic energy does he have and (b) what percent of his total kinetic energy is rotational?

Short Answer

Expert verified
Total kinetic energy is 138.76 J; 33.39% is rotational.

Step by step solution

01

Calculate Angular Velocity

The angular velocity \( \omega \) in radians per second can be calculated by converting revolutions per second to radians per second. \( \omega = 0.5 \times 2\pi = \pi \) rad/s.
02

Calculate Rotational Inertia

The formula for the moment of inertia \( I \) of a solid cylinder is \( I = \frac{1}{2} m r^2 \). Given the mass \( m = 75 \) kg and radius \( r = 0.5 \) m, \( I = \frac{1}{2} \times 75 \times (0.5)^2 = 9.375 \) kg·m².
03

Calculate Rotational Kinetic Energy

The rotational kinetic energy \( KE_{rot} \) is given by \( KE_{rot} = \frac{1}{2} I \omega^2 \). Substituting the values, \( KE_{rot} = \frac{1}{2} \times 9.375 \times (\pi)^2 = 46.32 \) J.
04

Calculate Translational Kinetic Energy

First, find the linear velocity \( v = \omega \times r = \pi \times 0.5 = 1.57 \) m/s. The translational kinetic energy \( KE_{trans} \) is \( \frac{1}{2} m v^2 = \frac{1}{2} \times 75 \times (1.57)^2 = 92.44 \) J.
05

Calculate Total Kinetic Energy

Add the rotational and translational kinetic energies: \( KE_{total} = 46.32 + 92.44 = 138.76 \) J.
06

Calculate the Percentage of Rotational Kinetic Energy

The percentage of total kinetic energy that is rotational is given by \( \left( \frac{KE_{rot}}{KE_{total}} \right) \times 100\% = \frac{46.32}{138.76} \times 100\% \approx 33.39\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The moment of inertia is a measure of an object's resistance to changes in its rotation. It's similar to how mass measures resistance to changes in linear motion. For a rotating object, the distribution of mass matters. The further the mass is from the axis of rotation, the greater the moment of inertia.

The moment of inertia for different shapes is calculated using specific formulas. For a solid cylinder, like a gymnast spinner, the formula is:
  • \( I = \frac{1}{2} m r^2 \)
where \( I \) represents the moment of inertia, \( m \) is the mass, and \( r \) is the radius.
This tells us that increasing the mass or radius will increase the moment of inertia. In our example, the mass is 75 kg and the radius is 0.5 m, leading to a moment of inertia of 9.375 kg·m².
Solid Cylinder
A solid cylinder is a three-dimensional object with uniform mass distribution. Its characteristics are crucial in understanding its rotational motion.

Here's why the solid cylinder is important:
  • The uniform mass makes calculations for inertia simpler.
  • The fixed shape allows for a standard formula for rotational inertia.
A tumbler modeled as a solid cylinder has dimensions that influence how energy is divided between rotational and translational movements. In the given exercise, the cylinder is used to approximate the gymnast's body, where its uniform structure allows us to apply the formula for calculating moment of inertia and further kinetic energies.
Angular Velocity
Angular velocity describes how fast an object rotates around an axis. It's a vector quantity, typically measured in radians per second (rad/s).

  • To convert from revolutions per second to rad/s, multiply by \( 2\pi \) (since there are \( 2\pi \) radians in a full circle).
  • In our exercise, 0.5 revolutions per second equates to \( \pi \) rad/s.
Understanding angular velocity is crucial for computing rotational kinetic energy, as it's a part of the formula: \( KE_{rot} = \frac{1}{2} I \omega^2 \).
This tells us that the faster something spins, given a constant moment of inertia, the more rotational kinetic energy it possesses.
Translational Kinetic Energy
Translational kinetic energy is associated with the linear motion of an object, as opposed to rotational kinetic energy which relates to spinning or circular motion.

For translational kinetic energy, the formula used is:
  • \( KE_{trans} = \frac{1}{2} m v^2 \)
Where \( m \) is the mass and \( v \) is the linear velocity of the object. In our example:
  • The linear velocity \( v \) is found by multiplying the angular velocity by the radius (\( v = \omega \times r \)).
  • With \( \omega = \pi \) rad/s and \( r = 0.5 \) m, \( v \) equals 1.57 m/s.
Using these values, the gymnast's translational kinetic energy is calculated to be 92.44 J. This energy represents the motion as the body moves forward, in contrast to the energy of spinning.

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Most popular questions from this chapter

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