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A solid copper disk has a radius of \(0.2 \mathrm{~m},\) a thickness of \(0.015 \mathrm{~m}\), and a mass of \(17 \mathrm{~kg}\). (a) What is the moment of inertia of the disk about a perpendicular axis through its center? (b) If the copper disk were melted down and re-formed into a solid sphere, what would its moment of inertia be?

Short Answer

Expert verified
The disk's moment of inertia is \(0.34 \, \mathrm{kg \cdot m^2}\). The sphere's moment of inertia is \(0.208 \, \mathrm{kg \cdot m^2}\).

Step by step solution

01

Calculate the volume of the copper disk

The volume of a cylinder (disk) can be calculated using the formula \( V = \pi r^2 h \), where \( r \) is the radius and \( h \) is the height or thickness. Substituting the given values: \( V = \pi (0.2)^2 (0.015) \).
02

Calculate the density of copper

Density is mass divided by volume. Using the disk's mass and volume calculated in Step 1, density \( \rho \) is \( \rho = \frac{17}{V} \).
03

Calculate the moment of inertia for the disk

For a solid disk, the moment of inertia \( I \) about a perpendicular axis through its center is given by the formula \( I = \frac{1}{2} m r^2 \). Substitute \( m = 17 \, \mathrm{kg} \) and \( r = 0.2 \, \mathrm{m} \).
04

Calculate the radius of the sphere formed from the melted copper

The volume of the sphere should match the volume of the disk. The formula for the volume of a sphere is \( V = \frac{4}{3} \pi R^3 \). Solve for the radius \( R \) using the disk's volume: \( R = \left(\frac{3V}{4\pi}\right)^{1/3} \).
05

Calculate the moment of inertia for the sphere

The moment of inertia \( I \) for a uniform solid sphere about an axis through its center is \( I = \frac{2}{5} m R^2 \). Substitute \( m = 17 \, \mathrm{kg} \) and the calculated radius \( R \) from Step 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solid Disk
A solid disk is essentially a three-dimensional object shaped like a circular cylinder. In this context, understanding how to calculate its moment of inertia is crucial. The moment of inertia of a solid disk gives us an idea of how resistant it is to being rotated about a specific axis, in this case, an axis perpendicular to its center. This quantity is important when we are dealing with rotational dynamics.

The formula to calculate the moment of inertia for a disk about a perpendicular axis through its center is \( I = \frac{1}{2} m r^2 \), where \( m \) is the disk's mass and \( r \) is its radius. This formula illustrates how mass distribution and radius influence the rotational characteristics of the disk.
  • \( I \) increases as the radius increases, due to the mass being distributed further from the axis.
  • In this scenario, substituting \( m = 17 \) kg and \( r = 0.2 \) m into the formula gives the moment of inertia for this particular copper disk.
Copper Properties
Copper is a widely used metal known for its excellent electrical conductivity, high thermal conductivity, and malleability. These properties make it suitable for many industrial applications. When considering the moment of inertia for a copper object, its density is of key concern.

Understanding material density is fundamental when modeling physical objects and predicting their behavior in different contexts. The density of copper is generally accepted to be around 8.92 g/cm³ (or 8920 kg/m³ in SI units). This high density contributes to the significant mass even for relatively small volumes.
  • In exercises like the one presented, the density calculation aids in confirming the correctness of derived quantities.
  • Accurate mass and volume measurements are crucial for precise density computation, impacting resultant calculations such as the moment of inertia.
Solid Sphere
A solid sphere, like a solid disk, can be analyzed to calculate its moment of inertia, but the approach and formulas differ slightly. When the copper disk is melted and reshaped into a sphere, its volume remains constant. However, understanding the new shape’s moment of inertia involves a new calculation.

The formula for the moment of inertia of a solid sphere about an internal axis is \( I = \frac{2}{5} m R^2 \). Here, \( m \) is the mass, and \( R \) is the sphere's radius. This formula reflects a different mass distribution compared to a disk.
  • In this example, determining the new radius \( R \) requires equating the sphere's volume to the original disk volume.
  • Once \( R \) is found using the relationship \( V = \frac{4}{3} \pi R^3 \), one can substitute it into the moment of inertia formula to find \( I \) for the sphere.
Density Calculation
Calculating an object's density is essential for understanding its physical properties and behavior in various applications. Density, represented by the symbol \( \rho \), is defined as mass per unit volume and is calculated using the formula \( \rho = \frac{m}{V} \).

In our particular example, we calculate the density of a copper disk. Starting with the known mass of 17 kg and using the volume calculated from \( V = \pi r^2 h \) for the disk, you can determine the disk's density.
  • Accurate density values are necessary for further computations, such as determining whether the volume calculations are consistent with known physical properties of the material.
  • This reaffirms the suitability of the object's material for specific applications or further transformations, like forming into a sphere.
In summary, understanding how to accurately calculate and apply density allows for more reliable physics calculations and predictions.

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