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A tow truck pulls a car \(5.00 \mathrm{~km}\) along a horizontal roadway using a cable having a tension of \(850 \mathrm{~N}\). (a) How much work does the cable do on the car if it pulls horizontally? If it pulls at \(35.0^{\circ}\) above the horizontal? (b) How much work does the cable do on the tow truck in both cases of part (a)? (c) How much work does gravity do on the car in part (a)?

Short Answer

Expert verified
(a) 4.25脳10鈦 J and 3.48脳10鈦 J; (b) same as (a); (c) 0 J.

Step by step solution

01

Understanding Work

Work done by a force is computed using the formula: \( W = Fd\cos\theta \). Here, \(F\) is the tension in the cable, \(d\) is the distance the car is moved, and \(\theta\) is the angle between the force and the direction of motion.
02

Calculating Work When Force is Horizontal

For part (a), when the force is horizontal, the angle \(\theta\) is \(0^{\circ}\). Therefore, the work done is calculated as follows: \[W = 850\, \text{N} \times 5.00\, \text{km} \times \cos(0^{\circ}) = 850 \times 5000 \times 1 = 4.25\times 10^6\, \text{J}\]
03

Calculating Work with Force at 35掳

Still part (a), if the force is at \(35^{\circ}\) above horizontal, we use \(\theta = 35^{\circ}\):\[W = 850\, \text{N} \times 5000\, \text{m} \times \cos(35^{\circ}) \]Calculating \(\cos(35^{\circ}) \approx 0.819\):\[W = 850 \times 5000 \times 0.819 = 3.48 \times 10^6\, \text{J}\]
04

Work Done on Tow Truck (Part b)

In both cases of part (a), the work done on the tow truck is equal in magnitude but opposite in direction because of Newton's Third Law. Thus for horizontal: \[ W = 4.25\times 10^6\, \text{J} \]And for the 35掳 angle:\[ W = 3.48\times 10^6\, \text{J} \]
05

Work Done by Gravity on Car (Part c)

The work done by gravity is zero in both cases of part (a) because gravity acts vertically downward and movement is horizontal. The angle between the direction of force (gravity) and displacement is \(90^{\circ}\), making \[W = mgd\cos(90^{\circ}) = 0\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension in Cables
Tension is the force exerted along a cable or rope when it is pulled tight by forces acting from opposite ends. In the scenario of a tow truck pulling a car, the tension in the cable is what helps transmit the force from the truck to the vehicle. This force is crucial for calculating how much work is done by the cable on an object.

In physics, tension can be felt as pulling forces transmitted axially by means of a cable. The tension in the cable here is given as 850 N, indicating that the cable is being pulled with a force of 850 Newtons. When considering calculations involving tension, it's essential to consider:
  • Magnitude of the force, which in this case is 850 N.
  • Direction of the force, which could change depending on whether the cable is horizontal or at an angle.
  • Length of the cable does not typically affect the tension but influences where the force will be applied.
Understanding tension in cables allows us to properly apply physics principles when calculating work done in various situations.
Angle of Force
The angle of force refers to the orientation of the force in relation to the direction of motion. It plays a significant roles in determining the work done by a force. When the force is exerted at an angle, the effective force contributing to the movement is the component of the force that is aligned with the direction of motion.

The formula for work is given by: \[ W = Fd\cos\theta \]Where:
  • \(F\) is the force applied, which is 850 N in this scenario.
  • \(d\) is the distance traveled, converted to 5,000 meters in our examples.
  • \(\theta\) is the angle between the force and the direction of motion.

Considering a force angle can change the amount of work done since only the component of the force in the direction of the movement contributes to work. For instance, maximum work occurs when the force is directly along the direction of movement (\(\theta = 0^{\circ}\)), and no work is done when the force is perpendicular (\(\theta = 90^{\circ}\)). The angle of force is pivotal for calculations in real-world applications, ensuring we compute the correct work.
Newton's Third Law
Newton's Third Law states, "for every action, there is an equal and opposite reaction." In the context of this exercise, the work done on the car by the tow truck is offset by the work done on the tow truck by the car. This is because the tension in the cable exerts equal forces in opposite directions.

In practical terms:
  • The tow truck pulls the car with a certain force, here 850 N.
  • The car, via the cable, exerts an equal and opposing force on the tow truck.

When considering work done, the magnitude of work on both objects (car and tow truck) remains the same, yet the direction of energy transfer is opposite. This principle illustrates the balance of forces acting in interacting bodies and is crucial in understanding many mechanical scenarios where force applications occur through intermediate objects like cables or ropes.
Work Done by Gravity
The work done by gravity is a concept describing how much energy gravity contributes to the movement of an object. In this particular case, gravity acts vertically downwards while the car moves horizontally. Because the force of gravity is perpendicular to the horizontal movement of the car, it does no work on the car.

This is derived from the work formula:\[ W = mgd\cos\theta \]Where:
  • \(m\) is the mass of the object.
  • \(g\) is the acceleration due to gravity.
  • \(d\) is the displacement.
  • \(\theta\) is the angle between the force and the direction of movement, \(90^{\circ}\) in this case.

The cosine of 90 degrees is zero, thus the entire expression for work done by gravity (\( W = 0 \)) results in zero. It is crucial to consider the angle between forces and motion directions when determining the impact of forces such as gravity.

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