/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Marbles of mass \(m\) are thrown... [FREE SOLUTION] | 91Ó°ÊÓ

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Marbles of mass \(m\) are thrown from the edge of a vertical cliff of height \(h\) at speed \(v_{0} .\) Neglecting air resistance, how fast (in terms of \(m, h,\) and \(v_{0}\) ) will these marbles be moving when they reach the bottom of the cliff if they are thrown (a) straight up, (b) straight down, or (c) horizontally away from the cliff? Will the final velocity vectors of the marbles be the same or different for each case?

Short Answer

Expert verified
The final speed is \( v = \sqrt{v_0^2 + 2gh} \) for all cases; it's the same regardless of the direction.

Step by step solution

01

Understanding the Problem

The marbles are thrown from a cliff of height \( h \) with initial speed \( v_0 \). The goal is to find the final speed when the marbles reach the bottom, considering three directions: (a) straight up, (b) straight down, and (c) horizontally.
02

Using Conservation of Energy

The principle of conservation of energy states that the total mechanical energy will remain constant if only gravitational forces are acting. Mathematically, this can be expressed as:\[ \frac{1}{2} m v_0^2 + mgh = \frac{1}{2} m v^2 \]where \( v \) is the final speed at the bottom of the cliff.
03

Solve for Final Speed in All Cases

Rearrange the equation to solve for \( v \):\[ \frac{1}{2} m v^2 = \frac{1}{2} m v_0^2 + mgh \]\[ v^2 = v_0^2 + 2gh \]\[ v = \sqrt{v_0^2 + 2gh} \]Thus, the final speed \( v \) is the same for all scenarios since it is independent of the direction of the initial velocity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that describes how objects move. It focuses on the motion itself without considering the forces that cause the motion. In simple terms, it answers questions like "how fast?" and "how far?" Using kinematics, we can predict the position, velocity, and acceleration of objects over time.When we talk about marbles thrown from a cliff, kinematics helps us calculate their speed and direction at any given point in time. The beauty of kinematics is that it allows us to use mathematical equations to model real-world scenarios, making it easier to understand the dynamics of motion.In the example of the marbles, the kinematic equation involves variables like initial velocity (\( v_0 \)), acceleration due to gravity (\( g \)), and height (\( h \)). These variables are not limited by the direction of initial motion, which means solving for speed at the bottom of the cliff gives us a prediction that is consistent regardless of whether the marble was thrown up, down, or horizontally.
Projectile Motion
Projectile motion describes the path an object follows under the influence of gravity alone. In our scenario of marbles thrown from a cliff, despite the initial direction, each marble experiences projectile motion.Two main components affect projectile motion:- **Horizontal and vertical motions**: These can be considered separately. Horizontal motion at constant velocity and vertical motion with acceleration due to gravity.- **Gravity**: It acts downward at a constant rate of approximately \( 9.8 \, \text{m/s}^2 \), affecting the vertical component of motion.When a marble is thrown,
  • the vertical component (\( v \)) changes due to gravity, and
  • the horizontal component remains constant if air resistance is ignored.
By calculating these components, you can find out their combined effect as the marble falls. Regardless of the direction initially taken by the marble, the total mechanical energy remains constant when only gravity acts on it.This principle of projectile motion helps illustrate why the final velocity is identical in magnitude but may differ in direction, based on the path of motion.
Gravitational Potential Energy
Gravitational potential energy (GPE) is the energy an object possesses because of its position in a gravitational field. This energy is relative to a reference point, typically considered at the ground level or lowest point along the object's path.In the case of the falling marbles, GPE at the cliff's edge depends on the height (\( h \)) and mass (\( m \)) of the marble:\[ \text{GPE} = mgh \]This energy transforms into kinetic energy as the marble descends. Kinetic energy is given by:\[ KE = \frac{1}{2} mv^2 \]At the start, the total energy is a combination of GPE at the height of the cliff and the marble's initial kinetic energy:\[ \frac{1}{2} mv_0^2 + mgh \]Upon reaching the bottom, all GPE converts into kinetic energy. The conservation of energy states:\[ \text{Initial Energy} = \text{Final Energy} \] This explains why initially different throwing directions result in the same final speed. Energy conversion principles show how GPE lost in the fall contributes to the marble’s motion, maintaining the total mechanical energy despite the path taken.

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Most popular questions from this chapter

Fleas are agile, wingless insects that feed on the blood of their hosts. Although they are typically \(2-3 \mathrm{~mm}\) long with a mass of \(4.5 \times 10^{-4} \mathrm{~kg},\) they have an astonishing ability to jump when threatened. Their propulsion, which can briefly produce accelerations more than 100 times that of gravity, comes not from muscles but, in fact, from an elastomeric protein called resilin, which acts as a spring. Given that the typical launch velocity of a flea is about \(1 \mathrm{~m} / \mathrm{s},\) what total energy must be stored in the resilin just before the flea jumps?

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A wooden rod of negligible mass and length \(80.0 \mathrm{~cm}\) is pivoted about a horizontal axis through its center. A white rat with mass \(0.500 \mathrm{~kg}\) clings to one end of the stick, and a mouse with mass \(0.200 \mathrm{~kg}\) clings to the other end. The system is released from rest with the rod horizontal. If the animals can manage to hold on, what are their speeds as the rod swings through a vertical position?

A \(250 \mathrm{~g}\) object on a frictionless, horizontal lab table is pushed against a spring of force constant \(35 \mathrm{~N} / \mathrm{cm}\) and then released. Just before the object is released, the spring is compressed \(12.0 \mathrm{~cm} .\) How fast is the object moving when it has gained half of the spring's original stored energy?

For its size, the common flea is one of the most accomplished jumpers in the animal world. A 2.0 -mm-long, \(0.50 \mathrm{mg}\) critter can reach a height of \(20 \mathrm{~cm}\) in a single leap. (a) Neglecting air drag, what is the takeoff speed of such a flea? (b) Calculate the kinetic energy of this flea at takeoff and its kinetic energy per kilogram of mass. (c) If a \(65 \mathrm{~kg}, 2.0-\mathrm{m}\) -tall human could jump to the same height compared with his length as the flea jumps compared with its length, how high could he jump, and what takeoff speed would he need? (d) In fact, most humans can jump no more than \(60 \mathrm{~cm}\) from a crouched start. What is the kinetic energy per kilogram of mass at takeoff for such a \(65 \mathrm{~kg}\) person? (e) Where does the flea store the energy that allows it to make such a sudden leap?

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