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A \(60 \mathrm{~kg}\) circus performer is climbing up a rope (of negligible mass) with an acceleration of \(1.2 \mathrm{~m} / \mathrm{s}^{2}\). (a) Draw a free-body diagram for the performer. (b) What is the tension in the rope?

Short Answer

Expert verified
The tension in the rope is 660 N.

Step by step solution

01

Identify the Forces

To begin, determine the forces acting on the performer. The main forces are the gravitational force (weight) pulling the performer down and the tension in the rope pulling the performer up. The gravitational force can be calculated using the formula \( F_g = m \cdot g \), where \( m = 60 \text{ kg} \) and \( g = 9.8 \text{ m/s}^2 \). Hence, \( F_g = 60 \cdot 9.8 = 588 \text{ N} \).
02

Draw the Free-Body Diagram

In the free-body diagram, show the performer as a point. Draw one arrow pointing downwards representing the gravitational force, labeled \( F_g = 588 \text{ N} \). Draw another arrow pointing upwards representing the tension in the rope, labeled \( T \). The direction of motion is upwards, meaning the tension force is greater than the gravitational force.
03

Apply Newton's Second Law

According to Newton's Second Law, the net force acting on the performer is equal to the mass times the acceleration: \( F_{net} = m \cdot a \). The net force is also the difference between the tension in the rope and the gravitational force: \( T - F_g = m \cdot a \). Substitute the known values: \( T - 588 = 60 \cdot 1.2 \).
04

Solve for Tension

Calculate the net force due to the acceleration: \( 60 \cdot 1.2 = 72 \text{ N} \). Hence, the equation becomes \( T - 588 = 72 \). Solve for tension: \( T = 72 + 588 = 660 \text{ N} \). This is the tension in the rope.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free-body Diagram
A free-body diagram is a crucial step in understanding the forces acting on an object. It helps to visually represent all the forces acting upon an object in a given scenario.
For instance, when considering the circus performer climbing a rope, imagine the performer as a single point.
Now, let’s think about the forces:
  • The gravitational force pulling downwards. This acts due to the performer’s mass being pulled by Earth’s gravity.
  • The tension force in the rope acting upwards. This represents the rope’s pull against gravity to lift the performer.
In the diagram, you’ll see these forces represented with arrows. The downward arrow (gravitational force) is often labeled with the weight (\( F_g \)). The upward arrow (tension) is typically labeled with \( T \).
This setup gives you a clear picture of the forces at play, setting you up to solve for unknowns like tension.
Tension in a Rope
Tension refers to the force conducted along the rope when a force is applied. In this scenario, the rope has tension because it is pulling the performer upwards against gravity.
This force is vital because it counteracts the weight of the performer, allowing them to ascend the rope.
To find the tension, you need to take into account both the gravitational force and the added force required for any acceleration of the performer. Since the performer is climbing up, tension must not only counteract gravity but also provide an extra force to move upwards.
Thus, the tension in the rope needs to equal the gravitational force plus the force from the upward acceleration resulting in the required total tension \( T \).
Gravitational Force Calculation
Gravitational force is a fundamental concept we encounter in physics, and calculating it is crucial in problems involving mass and gravity.
The force due to gravity acting on the performer is calculated using the formula:
  • \( F_g = m \times g \)
where:
  • \( m \) is the mass of the object (60 kg in this problem)
  • \( g \) is the acceleration due to gravity (approximately 9.8 m/s²).
Calculating this gives you:\( F_g = 60 \times 9.8 = 588 \, \text{N} \).
This represents the weight of the performer, which the tension in the rope needs to counteract, along with providing extra force for climbing motion.
Net Force Analysis
Understanding net force is key to applying Newton's Second Law properly. Net force is essentially the sum of all forces acting on an object.
In this case, the net force on the performer can be analyzed as the force leftover after subtracting gravitational force from tension in the rope.
Here's how you analyze it:
  • According to Newton’s Second Law: \( F_{\text{net}} = m \times a \), where \( a \) is the acceleration.
  • Apply this to find the net force—here, it comes from acceleration needed to climb: \( F_{\text{net}} = 60 \times 1.2 = 72 \, \text{N} \).
  • The formula becomes: \( T = F_{g} + F_{\text{net}} \) giving you \( T = 588 + 72 = 660 \, \text{N} \).
So, by calculating it this way, you understand that tension is overcoming gravitational pull and offering additional push for upward movement.

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