/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A \(2 \mathrm{~kg}\) block sits ... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(2 \mathrm{~kg}\) block sits at rest on a frictionless horizontal table. A \(10 \mathrm{~N}\) horizontal force is suddenly applied to the block and maintained as the block begins moving. (a) What is the acceleration of the block after the force is applied? (b) What is the speed of the block after it has moved a distance of \(0.5 \mathrm{~m} ?\)

Short Answer

Expert verified
(a) The acceleration is 5 m/s². (b) The speed after moving 0.5 m is approximately 2.24 m/s.

Step by step solution

01

Identify the Given Values

We are given that the block has a mass \(m = 2 \, \text{kg}\), and a force \(F = 10 \, \text{N}\) is applied. The distance the block moves is \(d = 0.5 \, \text{m}\).
02

Apply Newton's Second Law to Find Acceleration

According to Newton's second law, \(F = ma\), where \(F\) is the force applied, \(m\) is the mass, and \(a\) is the acceleration. Solve for \(a\) using the formula: \[ a = \frac{F}{m} = \frac{10 \, \text{N}}{2 \, \text{kg}} = 5 \, \text{m/s}^2 \]
03

Use Kinematic Equation to Find Speed

To find the speed \(v\) of the block, use the kinematic equation: \[ v^2 = u^2 + 2ad \] where \(u = 0\) (initial speed), \(a = 5 \, \text{m/s}^2\), and \(d = 0.5 \, \text{m}\). Substitute the values: \[ v^2 = 0 + 2 \times 5 \, \text{m/s}^2 \times 0.5 \, \text{m} = 5 \] \[ v = \sqrt{5} \, \text{m/s} \approx 2.24 \, \text{m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that deals with the motion of objects without considering the forces that cause this motion. It mainly focuses on quantities like displacement, velocity, acceleration, and time. In this particular exercise, the question uses a kinematic equation to determine the speed of the block after it has moved a certain distance.

Kinematic equations are powerful tools in physics because they allow us to predict the future motion of objects based on their current states. For instance, given the acceleration and the distance covered, we use the formula:
  • \[ v^2 = u^2 + 2ad \]
Here, \( u \) represents the initial velocity, which is zero as the block starts from rest. By plugging the given values into this equation, we can find the speed quickly and accurately.

Understanding this process is essential because it provides a foundation for solving more complex physics problems that involve predicting motion.
Force and Motion
Force and motion are inherently linked concepts in physics. A force is any interaction that, when unopposed, changes the motion of an object. Newton's Second Law of Motion, which states that the force applied on an object equals the mass of the object times its acceleration (\( F = ma \)), is pivotal in understanding this relationship.

In our exercise, the force applied to the block leads to motion, showcasing this fundamental principle. As the block was initially at rest, the sudden application of a 10 N force causes it to accelerate. The frictionless surface implies that there are no opposing forces to this applied force, leading to a straightforward calculation of acceleration.

Force comes in various forms, such as gravitational, tension, and applied forces. Recognizing how each force affects an object's motion requires an understanding of both the magnitude and direction of the force.
  • For instance, if the table were not frictionless, the force of friction would oppose the applied force, altering the resulting motion.
Such scenarios require a more nuanced application of Newton's Second Law.
Acceleration
Acceleration is defined as the rate of change of velocity of an object. It is a vector quantity, meaning it has both a magnitude and a direction. In physics, understanding acceleration is crucial because it helps describe how the speed or direction of an object changes over time.

In the exercise, once the 10 N force is applied, the block starts to accelerate. We calculate this acceleration using the relationship from Newton's Second Law:
  • \[ a = \frac{F}{m} \]
With the force and mass of the block known, we find that the block accelerates at \( 5 \, \text{m/s}^2 \). This tells us how quickly the block's velocity increases as it moves across the table.

An understanding of acceleration not only helps in problem-solving but also in planning and predicting movement in both simple and complex systems. It connects deeply with both kinematics and force, as these concepts often work together to describe physical phenomena.

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Most popular questions from this chapter

At the surface of Jupiter's moon Io, the acceleration due to gravity is \(1.81 \mathrm{~m} / \mathrm{s}^{2} .\) If a piece of ice weighs \(44.0 \mathrm{~N}\) at the surface of the earth, (a) what is its mass on the earth's surface? (b) What are its mass and weight on the surface of Io?

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