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The nucleus \({ }_{8}^{15} \mathrm{O}\) has a half-life of \(2.0 \mathrm{~min} .{ }^{19}_{8} \mathrm{O}\) has a half-life of about 0.5 min. (a) If, at some time, a sample contains equal amounts of \({ }_{8}^{15} \mathrm{O}\) and \({ }_{8}^{19} \mathrm{O},\) what is the ratio of \({ }_{8}^{15} \mathrm{O}\) to \({ }_{8}^{19} \mathrm{O}\) after 2.0 \(\min ?\) (b) After \(10.0 \mathrm{~min} ?\)

Short Answer

Expert verified
(a) 8, (b) 32

Step by step solution

01

Define Half-Life Formula

The half-life formula for radioactive decay is given by:\[N(t) = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}}\]where \(N(t)\) is the remaining quantity of a substance after time \(t\), \(N_0\) is the initial quantity, and \(T_{1/2}\) is the half-life of the substance.
02

Calculate Remaining Amount of \({_8^{15} \mathrm{O}}\) after 2 Minutes

For \({_8^{15} \mathrm{O}}\), which has a half-life of 2 minutes, the remaining amount after 2 minutes is calculated as:\[N_{15}(t=2) = N_{15,0} \left( \frac{1}{2} \right)^{\frac{2}{2}} = \frac{N_{15,0}}{2}\]where \(N_{15,0}\) is the initial amount of \({_8^{15} \mathrm{O}}\).
03

Calculate Remaining Amount of \({_8^{19} \mathrm{O}}\) after 2 Minutes

For \({_8^{19} \mathrm{O}}\), which has a half-life of 0.5 minutes, the remaining amount after 2 minutes is:\[N_{19}(t=2) = N_{19,0} \left( \frac{1}{2} \right)^{\frac{2}{0.5}} = \frac{N_{19,0}}{16}\]where \(N_{19,0}\) is the initial amount of \({_8^{19} \mathrm{O}}\).
04

Determine Ratio after 2 Minutes

Initially, we have equal amounts, \(N_{15,0} = N_{19,0}\). So, the ratio of \({_8^{15} \mathrm{O}}\) to \({_8^{19} \mathrm{O}}\) after 2 minutes is:\[\text{Ratio} = \frac{N_{15}(t=2)}{N_{19}(t=2)} = \frac{\frac{N_{15,0}}{2}}{\frac{N_{19,0}}{16}} = \frac{16}{2} = 8\]
05

Calculate Remaining Amount after 10 Minutes for Both Isotopes

For \({_8^{15} \mathrm{O}}\), after 10 minutes:\[N_{15}(t=10) = N_{15,0} \left( \frac{1}{2} \right)^{\frac{10}{2}} = \frac{N_{15,0}}{32}\]For \({_8^{19} \mathrm{O}}\), after 10 minutes:\[N_{19}(t=10) = N_{19,0} \left( \frac{1}{2} \right)^{\frac{10}{0.5}} = \frac{N_{19,0}}{1024}\]
06

Determine Ratio after 10 Minutes

The ratio of \({_8^{15} \mathrm{O}}\) to \({_8^{19} \mathrm{O}}\) after 10 minutes is:\[\text{Ratio} = \frac{N_{15}(t=10)}{N_{19}(t=10)} = \frac{\frac{N_{15,0}}{32}}{\frac{N_{19,0}}{1024}} = \frac{1024}{32} = 32\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life
In the world of nuclear physics, half-life is a key concept in understanding how radioactive substances decay over time. Half-life refers to the time it takes for half of a sample of a radioactive isotope to decay into a more stable form. This concept is crucial as it helps us predict how long a radioactive isotope will remain active, whether in a medical setting, archaeological dating, or nuclear power plants.

The formula for calculating the remaining quantity of a substance after a given time is given by:
  • \[ N(t) = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \]
Here, \(N(t)\) represents the remaining quantity of the substance after time \(t\), \(N_0\) is the initial quantity at time zero, and \(T_{1/2}\) is the half-life of the substance.

By knowing the half-life, one can easily determine how much of a substance will be left after a certain period, simply by noting how many half-lives pass.
For instance, if a substance has a half-life of one year, then after one year only half of the original sample will remain. After two years, only a quarter remains, and so forth.
Isotopes
Isotopes are variants of the same chemical element that have identical chemical properties but different atomic masses. This difference in atomic mass arises because isotopes of an element have the same number of protons but a different number of neutrons in their nuclei.

For example, the element oxygen has isotopes such as \(\text{O}^{15}_{8}\) and \(\text{O}^{19}_{8}\). These numbers indicate the atomic number of 8, aligning with oxygen's number of protons, while the numbers 15 and 19 denote differing numbers of neutrons.

Isotopes can be stable or radioactive. Radioactive isotopes are those that decay into other elements over time, impacting their applications in healthcare, carbon dating, and nuclear energy. Their different stability levels make understanding isotopes important, especially in nuclear physics applications. Knowing the type and behavior of isotopes helps in employing them for practical uses, such as tracing chemical pathways or dating ancient materials.
Nuclear Physics
Nuclear Physics is a branch of physics that deals with the components and behavior of atomic nuclei. This includes the complex study of particles like protons and neutrons, their interactions, and the forces that hold them together in the nucleus. Radioactive decay, which involves the transformation of an unstable nucleus into a more stable form, is a pivotal concept in nuclear physics.

The field covers several critical areas:
  • Understanding of nuclear reactions, which includes fission (splitting nuclei) and fusion (combining nuclei)
  • Exploration of nuclear forces, particularly the strong force that binds protons and neutrons
  • Study of radioactive decay processes, including alpha, beta, and gamma decay
Nuclear physics has profound implications, from providing insights into the universe's fundamental laws to developing technologies used in medicine (such as cancer treatment) and energy innovation. It's a field that combines theoretical frameworks with experimental data, bringing various applications that leverage nuclear stability and transformations.
Decay Formula
The decay formula, central to understanding radioactive decay, predicts how a radioactive substance decreases over time. This mathematical expression helps us calculate the remaining amount of a radioactive material at any given time, provided its half-life is known.

The fundamental form of the decay formula is:
  • \[ N(t) = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \]
Where:
  • \(N(t)\) is the quantity remaining at time \(t\)
  • \(N_0\) is the initial quantity
  • \(T_{1/2}\) represents the half-life
Understanding this formula is essential for calculating both current and future states of radioactive decay. This is why it's frequently used in fields as diverse as environmental science, medicine, and archaeology.

By applying this formula, we can solve problems like finding the amount of a radioactive isotope remaining after a certain time or determining how many half-lives will occur for a specific decay duration. The decay formula provides a precise way to model and predict the behavior of radioactive substances.

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Most popular questions from this chapter

In 1952, spectral lines of the element technetium-99 ( \(\left.{ }^{99} \mathrm{Tc}\right)\) were discovered in a red-giant star. Red giants are very old stars, often around 10 billion years old, and near the end of their lives. Technetium has no stable isotopes, and the half-life of \({ }^{99} \mathrm{Tc}\) is 200,000 years. (a) For how many half-lives has the \({ }^{99} \mathrm{Tc}\) been in the red-giant star if its age is 10 billion years? (b) What fraction of the original \({ }^{99} \mathrm{Tc}\) would be left at the end of that time?

A sample of the radioactive nuclide \({ }^{199} \mathrm{Pt}\) is prepared that has an initial activity of \(7.56 \times 10^{11}\) Bq. (a) 92.4 min after the sample is prepared, the activity has fallen to \(9.45 \times 10^{10} \mathrm{~Bq} .\) What is the half-life of this nuclide? (b) How many radioactive nuclei were initially present in the sample?

The common isotope of uranium, \({ }^{238} \mathrm{U},\) has a half-life of \(4.47 \times 10^{9}\) years, decaying to \({ }^{234} \mathrm{Th}\) by alpha emission. (a) \(\mathrm{What}\) is the decay constant? (b) What mass of uranium is required for an activity of 1.00 curie? (c) How many alpha particles are emitted per second by \(10.0 \mathrm{~g}\) of uranium?

Radioactive isotopes used in cancer therapy have a "shelf-life" simply because the active nuclei decay away. Just after it has been manufactured in a nuclear reactor, the activity of a sample of \({ }^{60} \mathrm{Co}\) is \(5000 \mathrm{Ci}\). When its activity falls below \(3500 \mathrm{Ci}\), it is considered too weak a source to use in treatment. You work in the radiology department of a large hospital. One of the \({ }^{60}\) Co sources in your inventory was manufactured on October 20,2012 . It is now October 20,2014 . Is the source still usable? Explain. (The half-life of \({ }^{60} \mathrm{Co}\) is 5.3 years.)

The unstable isotope \({ }^{40} \mathrm{~K}\) is used to date rock samples. Its half-life is \(1.28 \times 10^{8}\) years. (a) How many decays occur per second in a sample containing \(6.00 \times 10^{-6} \mathrm{~g}\) of \({ }^{40} \mathrm{~K} ?\) (b) What is the activity of the sample curies?

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