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A sample of the radioactive nuclide \({ }^{199} \mathrm{Pt}\) is prepared that has an initial activity of \(7.56 \times 10^{11}\) Bq. (a) 92.4 min after the sample is prepared, the activity has fallen to \(9.45 \times 10^{10} \mathrm{~Bq} .\) What is the half-life of this nuclide? (b) How many radioactive nuclei were initially present in the sample?

Short Answer

Expert verified
(a) Half-life is 25.0 minutes. (b) Initial nuclei count is \(2.73 \times 10^{13}\).

Step by step solution

01

Understanding Radioactive Decay

Radioactive decay follows a first-order kinetics pattern. The number of radioactive nuclei left after time \(t\) can be expressed by the equation \(A = A_0 e^{-\lambda t}\), where \(A\) is the activity at time \(t\), \(A_0\) is the initial activity, and \(\lambda\) is the decay constant.
02

Solving for Decay Constant (λ)

Using the given values after 92.4 minutes, we set up the equation \( 9.45 \times 10^{10} = 7.56 \times 10^{11} e^{-\lambda \cdot 92.4} \) and solve for \(\lambda\). Dividing both sides by \(7.56 \times 10^{11}\) gives \( e^{-\lambda \cdot 92.4} = \frac{9.45}{75.6} \). Solving gives \( \lambda = \frac{-\ln\left(\frac{9.45}{75.6}\right)}{92.4} \approx 0.0277 \text{ min}^{-1} \).
03

Calculating the Half-life

The half-life \(t_{1/2}\) is related to the decay constant by the formula \( t_{1/2} = \frac{\ln(2)}{\lambda} \). Substituting \( \lambda = 0.0277 \text{ min}^{-1} \), we have \( t_{1/2} = \frac{0.693}{0.0277} \approx 25.0 \text{ minutes} \).
04

Calculating Initial Number of Nuclei

The initial activity \(A_0\) is \(7.56 \times 10^{11}\) Bq. Activity is related to the number of nuclei \(N_0\) by the equation \( A_0 = \lambda N_0 \). Rearranging gives \( N_0 = \frac{A_0}{\lambda} \). Substituting \(A_0 = 7.56 \times 10^{11} \text{ Bq}\) and \(\lambda = 0.0277 \text{ min}^{-1}\), we find \( N_0 = \frac{7.56 \times 10^{11}}{0.0277} \approx 2.73 \times 10^{13} \text{ nuclei} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
When we discuss radioactive decay, we're mainly talking about a process where unstable atomic nuclei lose energy by emitting radiation. This can involve the release of particles like alpha particles, beta particles, or even electromagnetic radiation like gamma rays. The process happens naturally and results in the transformation of one element into another over time.
A key feature of radioactive decay is that it's a random process, but it follows a statistical pattern called first-order kinetics. This means that the rate at which the decay occurs is proportional to the number of undecayed nuclei still present. For this reason, even though it's unpredictable which nucleus will decay next, we can predict the overall behavior of a large sample using equations.
One important equation to know is:
  • \( A = A_0 e^{-\lambda t} \)
Here, \( A \) represents the activity at any time \( t \), \( A_0 \) is the initial activity, and \( \lambda \) is the decay constant. This equation helps us understand how the activity of a radioactive sample decreases over time.
Decay Constant
The decay constant, \( \lambda \), is a crucial part of understanding radioactive decay. It represents the probability per unit time that a given nucleus will decay. Essentially, the decay constant tells us how quickly a nuclear species decays.
To find the decay constant, we use an equation derived from the basic radioactive decay formula. If we know the initial activity and the activity after a certain time, we can use these values in the equation
  • \( A = A_0 e^{-\lambda t} \)
By rearranging, we solve for \( \lambda \):
  • \( \lambda = \frac{-\ln\left(\frac{A}{A_0}\right)}{t} \)
This tells us the rate of decay for a specific sample. Once we have \( \lambda \), we can also determine the half-life of the nuclei, which gives us more insight into the lifespan of the radioactive element.
Initial Activity
Initial activity, denoted as \( A_0 \), is the activity level of a radioactive sample at the moment we first measure it. Activity is expressed in becquerels (Bq), which measure the number of decay events per second.
Understanding initial activity helps us set the baseline for how we expect the radioactive material to behave over time. In our example, the initial activity was found to be \(7.56 \times 10^{11} \text{ Bq}\).
This is significant because initial activity is directly linked to the number of radioactive nuclei present initially. Moreover, knowing \( A_0 \) allows us to predict how activity will decrease, assuming a constant decay constant \( \lambda \). This relationship can be explored through the formula:
  • \( A = A_0 e^{-\lambda t} \)
This showcases the exponential decay nature of radioactive substances and highlights how initial activity sets the stage for measuring decay over time.
Radioactive Nuclei
Radioactive nuclei are the individual atoms that are prone to decay, releasing radiation in the process. Each nucleus contains protons and neutrons, and it's the balance of these particles that often determines stability. In unstable nuclei, this balance is off, leading to decay over time.
To understand how many radioactive nuclei are present in a given sample initially, we use initial activity and the decay constant. Specifically, this relationship is given by:
  • \( A_0 = \lambda N_0 \)
By rearranging to solve for \( N_0 \):
  • \( N_0 = \frac{A_0}{\lambda} \)
This equation links the measurable quantity of activity to the unseen quantity of nuclei. For example, when the initial activity is \(7.56 \times 10^{11}\) Bq and the decay constant is determined, this lets us calculate the number of nuclei, \( N_0 \).
This shows us that although we can’t see individual nuclei, their collective activity gives us enough information to understand the sample's behavior and predicts its decay over time.

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Most popular questions from this chapter

The common isotope of uranium, \({ }^{238} \mathrm{U},\) has a half-life of \(4.47 \times 10^{9}\) years, decaying to \({ }^{234} \mathrm{Th}\) by alpha emission. (a) \(\mathrm{What}\) is the decay constant? (b) What mass of uranium is required for an activity of 1.00 curie? (c) How many alpha particles are emitted per second by \(10.0 \mathrm{~g}\) of uranium?

An electron and a positron collide and annihilate, producing two photons. (a) Find the minimum energy of each of the photons. (b) What is the longest possible wavelength of photons produced by such a collision?

Radioactive isotopes are often introduced into the body through the bloodstream. Their spread through the body can then be monitored by detecting the appearance of radiation in different organs. \({ }^{131} \mathrm{I},\) a \(\beta^{-}\) emitter with a half-life of \(8.0 \mathrm{~d}\), is one such tracer. Suppose a scientist introduces a sample with an activity of \(375 \mathrm{~Bq}\) and watches it spread to the organs. (a) Assuming that the sample all went to the thyroid gland, what will be the decay rate in that gland \(24 \mathrm{~d}\) (about \(3 \frac{1}{2}\) weeks) later? (b) If the decay rate in the thyroid 24 d later is actually measured to be 17.0 Bq, what percent of the tracer went to that gland? (c) What isotope remains after the I-131 decays?

Given that each particle contains only combinations of \(u, d, s,\) \(\bar{u}, \bar{d},\) and \(\bar{s},\) deduce the quark content of (a) a particle with charge \(+e,\) baryon number \(0,\) and strangeness \(+1 ;\) (b) a particle with charge \(+e,\) baryon number \(-1,\) and strangeness \(+1 ;\) (c) a particle with charge \(0,\) baryon number \(+1,\) and strangeness -2.

The nucleus \({ }_{8}^{15} \mathrm{O}\) has a half-life of \(2.0 \mathrm{~min} .{ }^{19}_{8} \mathrm{O}\) has a half-life of about 0.5 min. (a) If, at some time, a sample contains equal amounts of \({ }_{8}^{15} \mathrm{O}\) and \({ }_{8}^{19} \mathrm{O},\) what is the ratio of \({ }_{8}^{15} \mathrm{O}\) to \({ }_{8}^{19} \mathrm{O}\) after 2.0 \(\min ?\) (b) After \(10.0 \mathrm{~min} ?\)

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