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Sketch a graph of (a) the nonrelativistic Newtonian kinetic energy as a function of speed \(v,\) (b) the relativistic kinetic energy as a function of speed \(v .\) In both cases, start from \(v=0\) and include the region where \(v \rightarrow c .\) Does either of these graphs extend beyond \(v=c ?\)

Short Answer

Expert verified
Neither graph extends beyond \( v = c \); nonrelativistic is invalid at \( v = c \), and relativistic approaches infinity.

Step by step solution

01

Understand Nonrelativistic Kinetic Energy

The nonrelativistic Newtonian kinetic energy is given by the equation \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the speed. This formula is only applicable when speeds are much less than the speed of light \( c \).
02

Understand Relativistic Kinetic Energy

In relativistic physics, kinetic energy is calculated using \( KE = \gamma mc^2 - mc^2 \), where \( \gamma = \frac{1}{\sqrt{1-(v^2/c^2)}} \). This takes into account the effects of relativity as speed approaches \( c \).
03

Sketch Nonrelativistic Kinetic Energy Graph

Draw the graph of \( KE = \frac{1}{2}mv^2 \) starting from \( v = 0 \). The graph is a parabola opening upwards, extending infinitely as \( v \) increases. It does not make sense to plot this beyond \( v = c \) because the formula isn't valid in this regime.
04

Sketch Relativistic Kinetic Energy Graph

Plot the function \( KE = \gamma mc^2 - mc^2 \) starting from \( v = 0 \). As \( v \) approaches \( c \), \( \gamma \) becomes very large, causing kinetic energy to approach infinity. Hence, the graph steeply rises and theoretically never reaches \( v = c \).
05

Conclusion About Graph Boundaries

Neither the nonrelativistic nor the relativistic kinetic energy graph should be extended beyond \( v = c \). Nonrelativistic kinetic energy doesn't apply at such high speeds, and relativistic kinetic energy becomes extremely large without actually reaching \( v = c \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonrelativistic Kinetic Energy
In the realm of Newtonian physics, nonrelativistic kinetic energy is calculated using a simple formula: \( KE = \frac{1}{2}mv^2 \). Here, \( m \) represents mass, and \( v \) is speed. This straightforward formula assumes that velocities are much smaller than the speed of light, \( c \).
Since Newtonian physics doesn't account for relativistic effects, this equation provides an excellent approximation when dealing with everyday speeds, like those of a car or a baseball. However, it falls short as speeds approach a significant fraction of \( c \), around 299,792,458 meters per second.
  • Pros: Simple and easy to use for slow speeds.
  • Cons: Inaccurate when speeds approach the speed of light.
When sketching a graph of this relationship, it forms a parabola that grows infinitely as speed increases. However, plotting beyond \( v = c \) is irrelevant because the underlying assumptions break down.
Relativistic Kinetic Energy
As objects move closer to the speed of light, relativistic effects become significant, requiring a different approach to calculating kinetic energy. In relativity, we use the equation \( KE = \gamma mc^2 - mc^2 \), where \( \gamma = \frac{1}{\sqrt{1-(v^2/c^2)}} \). This modifies energy calculations, acknowledging that energy grows immensely as speeds approach \( c \).
Relativistic kinetic energy captures the "increasing resistance" to acceleration experienced by objects nearing light speed. In a graph, this effect appears as a steep curve rising towards infinity as \( v \) approaches \( c \). It's important to note that although its theoretical value heads towards infinity, \( v = c \) is never actually reached.
  • Accounts for high-speed motion accurately.
  • Predicts kinetic energy near light speed much better than nonrelativistic calculations.
Speed of Light
The speed of light \( c \), approximately 299,792,458 meters per second, serves as a universal speed limit according to the laws of physics. It is the ultimate velocity any particle can theoretically achieve in a vacuum and underpins much of modern physical theory, especially relativity.
One key aspect of understanding motion and energy is realizing that no amount of force can accelerate an object with mass to reach or exceed this speed. Thus, in kinetic energy graphs, whether Newtonian or relativistic, plotting anything beyond \( c \) isn’t just impractical; it's physically meaningless.
  • Defines "boundary behavior" for kinetic energy graphs in relativity.
  • Is a critical factor in transitions from Newtonian to relativistic physics.
Relativity
Relativity is a foundational theory formulated by Albert Einstein, which reshaped our understanding of motion, space, and time. It shines especially when dealing with speeds nearing the speed of light, where traditional Newtonian physics ceases to be useful.
The core ideas of relativity, both special and general, involve:
  • Time dilation: Time moves slower for an object in motion compared to one at rest.
  • Length contraction: An object in motion appears shorter along the direction of motion.
  • Equivalence of mass and energy: Expressed in the famous equation \( E=mc^2 \).
Relativity alters our kinetic energy calculations by emphasizing that as speed increases, the effects of relativity grow exponentially, making precise calculations with Newtonian formulas impossible.
Newtonian Physics
Newtonian physics, also known as classical mechanics, was developed by Sir Isaac Newton in the 17th century. It laid out foundational principles describing the motion of objects and their interactions. This framework works exceptionally well for slow speeds and everyday conditions on Earth.
The main laws include:
  • Newton’s First Law (Inertia): Objects remain in uniform motion unless acted on by a force.
  • Newton’s Second Law (F=ma): Force equals mass times acceleration.
  • Newton’s Third Law (Action and Reaction): Every action has an equal and opposite reaction.
While it serves well on Earth, issues arise with high-speed and high-gravity situations, where relativity becomes necessary, leading to different interpretations of phenomena like time passage and energy distribution.

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Most popular questions from this chapter

A spacecraft flies away from the earth with a speed of \(0.6 c\) relative to the earth and then returns at the same speed. The spacecraft carries an atomic clock that has been carefully synchronized with an identical clock that remains at rest on earth. The spacecraft returns to its starting point 365 days ( 1 year) later, as measured by the clock that remained on earth. (a) Which clock records the proper time between the two events that correspond to leaving earth and then arriving at earth? (b) What is the difference in the elapsed times on the two clocks, measured in days? (c) Which clock, the one in the spacecraft or the one on earth, shows the shorter elapsed time?

A rocket is moving to the right at half the speed of light relative to the earth. A lightbulb in the center of a room inside the rocket suddenly turns on. Call the light hitting the front end of the room event \(A\) and the light hitting the back of the room event \(B\). (See Figure 27.23.) Which event occurs first, \(A\) or \(B\), or are they simultaneous, as viewed by (a) an astronaut riding in the rocket and (b) a person at rest on earth?

How fast must a rocket travel relative to the earth so that time in the rocket "slows down" to half its rate as measured by earth-based observers? Do present-day jet planes approach such speeds?

A rocket ship flies past the earth at \(85.0 \%\) of the speed of light. Inside, an astronaut who is undergoing a physical examination is having his height measured while he is lying down parallel to the direction the rocket ship is moving. (a) If his height is measured to be \(2.00 \mathrm{~m}\) by his doctor inside the ship, what would a person watching this from earth measure for his height? (b) If the earth-based person had measured \(2.00 \mathrm{~m},\) what would the doctor in the spaceship have measured for the astronaut's height? Is this a reasonable height? (c) Suppose the astronaut in part (a) gets up after the examination and stands with his body perpendicular to the direction of motion. What would the doctor in the rocket and the observer on earth measure for his height now?

Neutron stars are the remains of exploded stars, and they rotate at very high rates of speed. Suppose a certain neutron star has a radius of \(10.0 \mathrm{~km}\) and rotates with a period of \(1.80 \mathrm{~ms}\). (a) Calculate the surface rotational speed at the equator of the star as a fraction of c. (b) Assuming the star's surface is an inertial frame of reference (which it isn't, because of its rotation), use the Lorentz velocity transformation to calculate the speed of a point on the equator with respect to a point directly opposite it on the star's surface.

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