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How fast must a rocket travel relative to the earth so that time in the rocket "slows down" to half its rate as measured by earth-based observers? Do present-day jet planes approach such speeds?

Short Answer

Expert verified
The rocket must travel at about 0.87 times the speed of light, much faster than jet planes.

Step by step solution

01

Understanding Time Dilation

Time dilation in relativity is described by the Lorentz transformation, which shows how the time measured by observers in different inertial frames can differ. The formula for time dilation is given by: \\[ t' = \frac{t}{\sqrt{1 - \frac{v^2}{c^2}}} \] \where \( t' \) is the time interval observed in the rocket, \( t \) is the time interval as measured by an earth-based observer, \( v \) is the velocity of the rocket relative to Earth, and \( c \) is the speed of light.
02

Setting up the Time Dilation Condition

Since we want time in the rocket to "slow down" to half the rate of that measured by Earth-based observers, we set \( t' = 2t \). Substitute this into the time dilation formula: \\[ 2t = \frac{t}{\sqrt{1 - \frac{v^2}{c^2}}} \]
03

Solving for Velocity

Divide both sides by \( t \) to simplify the equation, which results in: \\[ 2 = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} \]. \Take the reciprocal: \\[ \sqrt{1 - \frac{v^2}{c^2}} = \frac{1}{2} \]
04

Squaring Both Sides

Square both sides to eliminate the square root: \\[ 1 - \frac{v^2}{c^2} = \frac{1}{4} \]
05

Isolating the Velocity Term

Subtract \( \frac{1}{4} \) from 1: \\[ \frac{v^2}{c^2} = \frac{3}{4} \]
06

Finding the Rocket's Velocity

Multiply both sides by \( c^2 \) to solve for \( v^2 \): \\[ v^2 = \frac{3}{4}c^2 \]. \Taking the square root of both sides gives: \\[ v = \frac{\sqrt{3}}{2}c \]. \Since \( c \) is the speed of light (approximately \( 3.00 \times 10^8 \) m/s), \( v \approx 0.87c \).
07

Comparing to Present-day Jet Planes

Present-day jet planes travel much slower, at speeds around 240 m/s (about 870 km/hr). This is nowhere near the speed needed to achieve significant time dilation as calculated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz Transformation
The Lorentz transformation is a set of equations in physics that are fundamental to Einstein's theory of special relativity. They describe how the measurements of time and space change for observers in different inertial reference frames moving relative to each other at constant velocities. This transformation is crucial for understanding phenomena like time dilation and length contraction.
  • Time dilation occurs because time intervals can appear different for observers in different frames of motion.
  • Length contraction is the phenomenon where the length of an object in motion appears shorter along the direction of motion from the perspective of a stationary observer.
The Lorentz transformation helps reconcile how two observers can measure different times or distances for the same event, maintaining the laws of physics.
Understanding this concept is vital as it provides the mathematical framework through which time dilation is calculated in scenarios such as our rocket problem.
Special Relativity
Special relativity, introduced by Albert Einstein in 1905, revolutionized our understanding of space and time. It is based on two fundamental postulates:
  • The laws of physics are the same for all observers in uniform motion relative to each other.
  • The speed of light in a vacuum is constant for all observers, regardless of their motion or the motion of the light source.
Incorporating the Lorentz transformation equations, special relativity predicts effects such as time dilation and length contraction, which seem counterintuitive at everyday speeds.
However, these effects become significant as speeds approach the speed of light. Special relativity fundamentally alters our understanding of time and space, emphasizing their interdependence in the space-time continuum.
In our exercise, special relativity allows us to calculate how fast a rocket must travel for time aboard to slow down to half of what is experienced by an observer on Earth.
Velocity of Rocket
The velocity of a rocket refers to how fast it moves relative to its start point, such as Earth. In our scenario, we're interested in finding the specific velocity required for significant time dilation to occur.
Using the time dilation formula derived from the Lorentz transformation, \( t' = \frac{t}{\sqrt{1 - \frac{v^2}{c^2}}} \), we can manipulate this equation to solve for the velocity \( v \).
  • We set the condition such that the time inside the rocket (\( t' \)) is twice that observed from Earth (\( t \)), leading to a simplified equation \( 2 = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} \).
  • Solving this, the velocity comes out to \( v \approx 0.87c \), or about 87% of the speed of light.
This speed is remarkably high, much beyond the capabilities of present-day human technology like jet planes, which only reach a fraction of this velocity.
Speed of Light
The speed of light, denoted as \( c \), is approximately \( 3.00 \times 10^8 \) meters per second. It is not only a crucial constant in physics but also serves as the ultimate speed limit according to special relativity.
The speed of light is invariant, meaning it does not change regardless of the observer's frame of reference or the motion of the light source. This invariance is one of the core principles underpinning Einstein’s theory.
  • Any object or information cannot travel faster than this speed, which has profound implications on causality and the structure of the universe.
  • The invariant nature of light's speed leads to significant relativistic effects, like time dilation, as speeds approach \( c \).
In our exercise, the speed of light serves as the benchmark to determine how fast the rocket needs to travel to achieve considerable time dilation, specifically \( v \approx 0.87c \).
This showcases the extraordinary abilities required to influence time perception through speed, making such velocities a challenge for current technology.

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Most popular questions from this chapter

Inside a spaceship flying past the earth at three-fourths the speed of light, a pendulum is swinging. (a) If each swing takes \(1.50 \mathrm{~s}\) as measured by an astronaut performing an experiment inside the spaceship, how long will the swing take as measured by a person at mission control on earth who is watching the experiment? (b) If each swing takes \(1.50 \mathrm{~s}\) as measured by a person at mission control on earth, how long will it take as measured by the astronaut in the spaceship?

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