/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 You blow up a spherical balloon ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You blow up a spherical balloon to a diameter of \(50.0 \mathrm{~cm}\) until the absolute pressure inside is 1.25 atm and the temperature is \(22.0^{\circ} \mathrm{C}\). Assume that all the gas is \(\mathrm{N}_{2},\) of molar mass \(28.0 \mathrm{~g} / \mathrm{mol}\). (a) Find the mass of a single \(\mathrm{N}_{2}\) molecule. (b) How much translational kinetic energy does an average \(\mathrm{N}_{2}\) molecule have? (c) How many \(\mathrm{N}_{2}\) molecules are in this balloon? (d) What is the total translational kinetic energy of all the molecules in the balloon?

Short Answer

Expert verified
(a) \(4.65 \times 10^{-26} \text{ kg}\). (b) \(6.10 \times 10^{-21} \text{ J}\). (c) \(2.05 \times 10^{24}\) molecules. (d) \(12.5 \text{ kJ}\).

Step by step solution

01

Calculate Volume of the Balloon

The diameter of the balloon is given as \(50.0\, \text{cm}\). First, find the radius \(r\) by dividing the diameter by 2: \(r = \frac{50.0}{2} = 25.0\, \text{cm} = 0.25\, \text{m}\). The volume \(V\) of a sphere is \(\frac{4}{3}\pi r^3\). Substitute the radius into the formula: \[V = \frac{4}{3}\pi (0.25)^3\approx 0.0654\, \text{m}^3.\]
02

Convert Temperature to Kelvin

Convert the temperature from Celsius to Kelvin using the formula \(T(K) = T(°C) + 273.15\). Thus, \(T = 22.0 + 273.15 = 295.15\, \text{K}.\)
03

Calculate Mass of a Single Nitrogen Molecule

The mass of a single molecule \(m\) is calculated using the molar mass \(M = 28.0\, \text{g/mol}\).\(M\) is in grams, converted to kilograms by dividing by 1000 (\(M = 0.028\, \text{kg/mol}\)). Use Avogadro’s number \(N_A = 6.022 \times 10^{23}\, \text{mol}^{-1}\). The mass then is: \[m = \frac{M}{N_A} = \frac{0.028}{6.022 \times 10^{23}} \approx 4.65 \times 10^{-26}\, \text{kg}.\]
04

Calculate Translational Kinetic Energy of an Average Molecule

The average translational kinetic energy \(KE\) of a molecule is given by the formula \(KE = \frac{3}{2}kT\), where \(k = 1.38 \times 10^{-23} \text{J/K}\) is the Boltzmann constant. Substituting the temperature \(T\) from step 2: \[KE = \frac{3}{2} \times 1.38 \times 10^{-23} \times 295.15 \approx 6.10 \times 10^{-21} \text{J}.\]
05

Calculate Number of Molecules in the Balloon

Use the ideal gas law \(PV = nRT\) with \(n\) as the number of moles. Rearrange to find \(n\): \(n = \frac{PV}{RT}\). Use \(R = 8.314\, \text{J/(mol K)}\), \(P = 1.25 \times 1.013 \times 10^5\, \text{Pa}\), and substitute \(V\) and \(T\) from steps 1 and 2: \[n \approx \frac{1.25 \times 1.013 \times 10^5 \times 0.0654}{8.314 \times 295.15} \approx 3.41\, \text{mol}.\] Multiply by Avogadro’s number to find the number of molecules: \(N = nN_A = 3.41 \times 6.022 \times 10^{23} \approx 2.05 \times 10^{24}\, \text{molecules}.\)
06

Calculate Total Translational Kinetic Energy of All Molecules

Multiply the average kinetic energy per molecule found in Step 4 by the total number of molecules from Step 5: \[\text{Total KE} = 6.10 \times 10^{-21} \times 2.05 \times 10^{24} \approx 12.5\, \text{kJ}.\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is one of the cornerstone equations in thermodynamics that relates the pressure, volume, and temperature of a gas to the amount of gas present. It's expressed as \(PV = nRT\), where:
  • \(P\) is the pressure of the gas
  • \(V\) is the volume the gas occupies
  • \(n\) is the number of moles of the gas
  • \(R\) is the ideal gas constant (approximately \(8.314\, \text{J/(mol K)}\))
  • \(T\) is the temperature in Kelvin
This equation helps us understand how gases behave under different conditions. For instance, as the volume of a gas decreases while temperature remains constant, the pressure increases, illustrating Boyle's Law, a derivative of the ideal gas law.
In the context of the balloon, by using the ideal gas law, we can determine how many moles of nitrogen are required to fill the balloon under given conditions. Once we have the number of moles, multiplying it by Avogadro’s number gives us the total number of molecules, bringing us closer to understanding the molecular dynamics within the balloon.
Kinetic Theory of Gases
The Kinetic Theory of Gases provides a molecular understanding of gases, describing them as many small particles in constant, random motion. This theory connects the macroscopic properties of gases—such as temperature and pressure—with the microscopic actions of individual gas molecules.
  • Gas pressure arises from the collisions of molecules with the walls of a container.
  • The average kinetic energy of gas molecules is proportional to the gas's absolute temperature.

According to this theory, the average translational kinetic energy of a single molecule is given by \(KE = \frac{3}{2}kT\), where \(k\) is the Boltzmann constant and \(T\) is the temperature in Kelvin. This relation tells us that as temperatures rise, so does the average kinetic energy of the molecules, leading to increased motion within the gas.
In our balloon scenario, this principle helps us determine how much energy each nitrogen molecule has and the sum total of energy in the entire balloon. Translating molecular movements into energy calculations allows for a deeper insight into thermal and kinetic behaviors in gases.
Molar Mass
Molar Mass is an essential concept for understanding substances at the molecular level, especially in contexts involving chemical reactions and gas calculations. It represents the mass of one mole of a given substance, expressed in grams per mole. For nitrogen gas \(\text{N}_2\), its molar mass is \(28.0 \text{ g/mol}\).
Knowing the molar mass allows us to convert between the mass of a substance and the number of moles, making it a crucial part of the stoichiometric interpretations in chemical reactions and thermodynamic calculations.
In the balloon exercise, we take advantage of nitrogen's molar mass to determine the mass of a single \(\text{N}_2\) molecule. Using Avogadro's number, which tells us how many particles comprise a mole, allows transformation from readable-scale molar masses to the minuscule mass of single molecules. This conversion is vital when dealing with gases and calculating their properties on a microscopic scale.
Boltzmann Constant
The Boltzmann constant \( k \) is a physical constant connecting the average kinetic energy of particles with the temperature of the system. Its value is approximately \(1.38 \times 10^{-23} \text{ J/K}\).
This constant plays a fundamental role in the kinetic theory of gases, relating temperature to energy. Specifically, it offers a bridge between macroscopic and microscopic physics, quantifying the energy level of individual particles in relation to thermal energy.
In practical terms, the Boltzmann constant is key to calculating the translational kinetic energy of gas molecules, which is done via \(KE = \frac{3}{2}kT\). Hence, in the balloon problem, \(k\) allows us to compute the average energy possessed by nitrogen molecules given a certain temperature. By understanding \(k\), students gain insight into how temperature at the macro level translates to energy within molecular movements, enriching their grasp of thermodynamic behaviors.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One way to improve insulation in windows is to fill a sealed space between two glass panes with a gas that has a lower thermal conductivity than that of air. The thermal conductivity \(k\) of a gas depends on its molar heat capacity \(C_{V},\) molar mass \(M,\) and molecular radius \(r\). The dependence on those quantities at a given temperature is approximately \(k \propto C_{V} / r^{2} \sqrt{M}\). The noble gases have properties that make them particularly good choices as insulating gases. Noble gases range from helium (molar mass \(4.0 \mathrm{~g} / \mathrm{mol}\), molecular radius \(0.13 \mathrm{nm}\) ) to xenon (molar mass \(131 \mathrm{~g} / \mathrm{mol}\), molecular radius \(0.22 \mathrm{nm}\) ). (The noble gas radon is heavier than xenon, but radon is radioactive and so is not suitable for this purpose.) Give one reason why the noble gases are preferable to air (which is mostly nitrogen and oxygen) as an insulating material. A. Noble gases are monatomic, so no rotational modes contribute to their molar heat capacity. B. Noble gases are monatomic, so they have lower molecular masses than do nitrogen and oxygen. C. The molecular radii in noble gases are much larger than those of gases that consist of diatomic molecules. D. Because noble gases are monatomic, they have many more degrees of freedom than do diatomic molecules, and their molar heat capacity is reduced by the number of degrees of freedom.

Find the mass of a single sulfur (S) atom and an ammonia ( \(\mathrm{NH}_{3}\) ) molecule. Use the periodic table in Appendix \(\mathrm{C}\) to find the molar masses.

Three moles of an ideal gas are in a rigid cubical box with sides of length \(0.200 \mathrm{~m}\). (a) What is the force that the gas exerts on each of the six sides of the box when the gas temperature is \(20.0^{\circ} \mathrm{C} ?\) (b) What is the force when the temperature of the gas is increased to \(100.0^{\circ} \mathrm{C} ?\)

A large cylindrical tank contains \(0.750 \mathrm{~m}^{3}\) of nitrogen gas at \(27^{\circ} \mathrm{C}\) and \(1.50 \times 10^{5} \mathrm{~Pa}\) (absolute pressure). The tank has a tight-fitting piston that allows the volume to be changed. What will be the pressure if the volume is decreased to \(0.480 \mathrm{~m}^{3}\) and the temperature is increased to \(157^{\circ} \mathrm{C} ?\)

Starting with \(2.50 \mathrm{~mol}\) of \(\mathrm{N}_{2}\) gas (assumed to be ideal) in a cylinder at 1.00 atm and \(20.0^{\circ} \mathrm{C}\), a chemist first heats the gas at constant volume, adding \(1.52 \times 10^{4} \mathrm{~J}\) of heat, then continues heating and allows the gas to expand at constant pressure to twice its original volume. (a) Calculate the final temperature of the gas. (b) Calculate the amount of work done by the gas. (c) Calculate the amount of heat added to the gas while it was expanding. (d) Calculate the change in internal energy of the gas for the whole process.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.