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A large cylindrical tank contains \(0.750 \mathrm{~m}^{3}\) of nitrogen gas at \(27^{\circ} \mathrm{C}\) and \(1.50 \times 10^{5} \mathrm{~Pa}\) (absolute pressure). The tank has a tight-fitting piston that allows the volume to be changed. What will be the pressure if the volume is decreased to \(0.480 \mathrm{~m}^{3}\) and the temperature is increased to \(157^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
The final pressure is approximately \( 3.39 \times 10^5 \, \text{Pa} \).

Step by step solution

01

Identify the known values

We are given the initial volume, temperature, and pressure of the nitrogen gas. Let \( V_1 = 0.750 \, \text{m}^3 \), \( T_1 = 27\, ^\circ \text{C} = 300 \text{ K} \), and \( P_1 = 1.50 \times 10^5 \, \text{Pa} \). The final conditions are: volume \( V_2 = 0.480 \, \text{m}^3 \), temperature \( T_2 = 157\, ^\circ \text{C} = 430 \, \text{K} \), and pressure \( P_2 \) which needs to be found.
02

Use the Ideal Gas Law

The Ideal Gas Law is \( PV = nRT \).From this, we derive: \( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \)since the number of moles \( n \) and \( R \) are constants when changing state. This relationship between the two states of the gas will help us find the final pressure \( P_2 \).
03

Rearrange to solve for \( P_2 \)

Rearrange the equation from Step 2:\[ P_2 = \frac{P_1 V_1 T_2}{T_1 V_2} \]
04

Substitute known values into the equation

Substitute the known values:\[ P_2 = \frac{(1.50 \times 10^5 \, \text{Pa}) \times (0.750 \, \text{m}^3) \times (430 \, \text{K})}{(300 \, \text{K}) \times (0.480 \, \text{m}^3)} \]
05

Calculate \( P_2 \)

Calculate the numerical value:\[ P_2 = \frac{1.5 \times 0.75 \times 430}{300 \times 0.48} \times 10^5 \, \text{Pa} \]Simplifying the numbers:\[ P_2 = \frac{0.4875 \times 10^5}{0.144} \, \text{Pa} \]\[ P_2 \approx 3.3865 \times 10^5 \, \text{Pa} \]
06

Conclusion

The final pressure \( P_2 \) in the tank, after changing the volume and temperature, is approximately \( 3.39 \times 10^5 \, \text{Pa} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure and Volume Relationship
In the realm of physics, understanding how pressure and volume relate is crucial for grasping the behavior of gases. This relationship is described by Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature is kept constant. In simple terms, if you compress a gas into a smaller volume, the pressure goes up. Conversely, if you allow the gas to expand, the pressure drops. The mathematical expression of Boyle's Law is given by:\[ P_1 V_1 = P_2 V_2 \]This equation helps us predict changes in pressure or volume in a gas when the other factor is altered, assuming temperature remains unchanged. Boyle's Law is particularly useful in understanding phenomena like breathing, where lungs expand and contract, affecting the pressure of the air inside them.
Gas Laws in Physics
Gas laws are fundamental in physics because they explain the properties and behavior of gases. These laws include Boyle's Law, Charles's Law, and the Ideal Gas Law, each addressing different aspects of gas behavior. The Ideal Gas Law, in particular, provides a comprehensive formula that relates pressure (\(P\)), volume (\(V\)), temperature (\(T\)), and the number of moles (\(n\)) of a gas:\[ PV = nRT \]Here, \(R\) is the universal gas constant. This law is especially powerful because it can predict the state of a gas when changes occur in any of its properties. For example, in a cylindrical tank, when pressure and heat are altered, the Ideal Gas Law helps us calculate the new pressure or volume. It assumes that gases behave ideally, which is valid under many conditions, especially at high temperatures and low pressures.
Thermodynamics
Thermodynamics, the study of heat and energy transfers, provides the foundational principles that govern the behavior of gases. Through the concepts of thermodynamics, we can understand how energy in the form of heat leads to changes in temperature, pressure, and volume. One of the central ideas in thermodynamics is the First Law, which states that energy cannot be created or destroyed, only transferred or changed in form. In the context of gases, when a gas is heated, it absorbs energy, which may result in an increase in temperature and pressure if the volume remains constant, or an increase in volume if pressure is constant. Thermodynamics also introduces the concept of entropy, a measure of disorder, providing insights into why certain processes, such as expansion and compression, occur spontaneously. By analyzing these principles, we can predict how gases will respond to various changes in their environment.

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Most popular questions from this chapter

Helium gas with a volume of \(2.60 \mathrm{~L}\) under a pressure of 1.30 atm and at a temperature of \(41.0^{\circ} \mathrm{C}\) is warmed until both the pressure and volume of the gas are doubled. (a) What is the final temperature? (b) How many grams of helium are there? The molar mass of helium is \(4.00 \mathrm{~g} / \mathrm{mol}\).

Two moles of an ideal gas are heated at constant pressure from \(T=27^{\circ} \mathrm{C}\) to \(T=107^{\circ} \mathrm{C}\). (a) Draw a \(p V\) diagram for this process. (b) Calculate the work done by the gas.

The water pressure at the bottom of the Mariana Trench, which is one of the deepest parts of the Pacific Ocean, is about 1000 atm. How many grams of helium gas would you have to put into a 1 liter volume at room temperature \((300 \mathrm{~K})\) in order to achieve this pressure?

The surface of the sun. The surface of the sun has a temperature of about \(5800 \mathrm{~K}\) and consists largely of hydrogen atoms. (a) Find the rms speed of a hydrogen atom at this temperature. (The mass of a single hydrogen atom is \(1.67 \times 10^{-27} \mathrm{~kg} .\) ) (b) What would be the mass of an atom that had half the rms speed of hydrogen?

The gas inside a balloon will always have a pressure nearly equal to atmospheric pressure, since that is the pressure applied to the outside of the balloon. You fill a balloon with helium (a nearly ideal gas) to a volume of \(0.600 \mathrm{~L}\) at a temperature of \(19.0^{\circ} \mathrm{C}\). What is the volume of the balloon if you cool it to the boiling point of liquid nitrogen \((77.3 \mathrm{~K}) ?\)

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