/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 (a) Calculate the momentum of a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Calculate the momentum of a 2000 -kg elephant charging a hunter at a speed of \(7.50 \mathrm{m} / \mathrm{s} .\) (b) Compare the elephant's momentum with the momentum of a \(0.0400-\mathrm{kg}\) tranquilizer dart fired at a speed of \(600 \mathrm{m} / \mathrm{s}\). (c) What is the momentum of the 90.0 -kg hunter running at \(7.40 \mathrm{m} / \mathrm{s}\) after missing the elephant?

Short Answer

Expert verified
The elephant's momentum is \(15000 \, \text{kg} \cdot \text{m/s}\), the tranquilizer dart's momentum is \(24 \, \text{kg} \cdot \text{m/s}\), and the hunter's momentum is \(666 \, \text{kg} \cdot \text{m/s}\).

Step by step solution

01

Calculate the momentum of the elephant

Momentum is calculated using the formula momentum (p) equals mass (m) times velocity (v), or in equation form: \( p = m \times v \). For the elephant, mass \( m = 2000 \, \text{kg} \) and velocity \( v = 7.50 \, \text{m/s} \), thus the momentum \( p \) of the elephant can be calculated as \( p = 2000 \times 7.50 \).
02

Calculate the momentum of the tranquilizer dart

Using the same momentum formula \( p = m \times v \), the dart's mass \( m = 0.0400 \, \text{kg} \) and velocity \( v = 600 \, \text{m/s} \), the momentum \( p \) for the dart is \( p = 0.0400 \times 600 \).
03

Compare the elephant's and dart's momentum

Subtract the dart's momentum from the elephant's momentum to see the difference. This means calculating \( p_{\text{elephant}} - p_{\text{dart}} \) using the values obtained in Steps 1 and 2.
04

Calculate the momentum of the hunter

Again using the formula for momentum \( p = m \times v \), for the hunter, mass \( m = 90.0 \, \text{kg} \) and velocity \( v = 7.40 \, \text{m/s} \), the momentum \( p \) is \( p = 90.0 \times 7.40 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Momentum
Imagine an elephant charging towards a hunter—quite a daunting scenario, isn't it? To understand this dynamic situation from a physics perspective, we need to delve into the concept of linear momentum, defined as the product of an object's mass and its velocity. It's a vector quantity, meaning it has both magnitude and direction.

In our case, the elephant's linear momentum is calculated by multiplying its mass (\(2000\text{ kg}\)) by its velocity (\(7.50\text{ m/s}\)), leading to a significant amount of momentum due to the large mass even though the velocity isn't extreme. The resultant momentum explains why stopping an elephant in motion would be incredibly difficult—it's all about the mass and speed combined.

Understanding linear momentum is crucial not only in physics but also in understanding everyday phenomena. For example, when you catch a ball, you're actually changing its momentum to zero, and the force you feel is related to how rapidly you stop it—faster stops mean greater forces and vice versa.
Conservation of Momentum
The concept of the conservation of momentum is indispensable when analyzing collisions and interactions between objects. It states that in a closed system with no external forces, the total momentum before an event is equal to the total momentum after the event. This conservation law explains how different objects will interact momentum-wise.

For instance, if the hunter were to successfully hit the elephant with the tranquilizer dart, the total momentum of the system (elephant plus dart) before and after the collision would remain constant. In an ideal scenario with no external forces acting on the system, if you added the elephant's momentum to the dart's momentum before the collision, it would equal the combined momentum of the dart-elephant system after the collision. This principle allows us to predict the outcomes of interactions, like what happens in car crashes or billiard balls colliding on a pool table.
Momentum-Velocity Relation
The relationship between momentum and velocity is quite straightforward but profoundly important in understanding motion. Momentum is directly proportional to velocity, which means that as the velocity of an object increases, so does its momentum, provided the mass remains constant.

Now, compare the relatively slow-moving elephant to the swift tranquilizer dart. Even though the dart's mass (\(0.0400\text{ kg}\)) is minuscule compared to the elephant, its high velocity (\(600\text{ m/s}\)) gives it a substantial momentum. This illustrates the momentum-velocity relation perfectly. In contrast, the hunter, with a mass of \(90.0\text{ kg}\) and velocity of \(7.40\text{ m/s}\), also has momentum but significantly less than the elephant due to his lower mass and velocity. This concept helps explain why high-speed objects, even if they are light, like bullets or darts, can have significant effects when they collide with other objects.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two football players collide head-on in midair while trying to catch a thrown football. The first player is \(95.0 \mathrm{kg}\) and has an initial velocity of \(6.00 \mathrm{m} / \mathrm{s},\) while the second player is \(115 \mathrm{kg}\) and has an initial velocity of \(-3.50 \mathrm{m} / \mathrm{s}\). What is their velocity just after impact if they cling together?

A 0.0250-kg bullet is accelerated from rest to a speed of \(550 \mathrm{m} / \mathrm{s}\) in a 3.00 -kg rifle. The pain of the rifle's kick is much worse if you hold the gun loosely a few centimeters from your shoulder rather than holding it tightly against your shoulder. (a) Calculate the recoil velocity of the rifle if it is held loosely away from the shoulder. (b) How much kinetic energy does the rifle gain? (c) What is the recoil velocity if the rifle is held tightly against the shoulder, making the effective mass 28.0 kg? (d) How much kinetic energy is transferred to the rifleshoulder combination? The pain is related to the amount of kinetic energy, which is significantly less in this latter situation. (e) Calculate the momentum of a 110 -kg football player running at \(8.00 \mathrm{m} / \mathrm{s}\). Compare the player's momentum with the momentum of a hard-thrown 0.410 -kg football that has a speed of \(25.0 \mathrm{m} / \mathrm{s}\). Discuss its relationship to this problem.

Water from a fire hose is directed horizontally against a wall at a rate of \(50.0 \mathrm{kg} / \mathrm{s}\) and a speed of \(42.0 \mathrm{m} / \mathrm{s}\). Calculate the magnitude of the force exerted on the wall, assuming the water's horizontal momentum is reduced to zero.

What is the strength of the electric field between two parallel conducting plates separated by \(1.00 \mathrm{~cm}\) and having a potential difference (voltage) between them of \(1.50 \times 10^{4} \mathrm{~V}\) ?

Find the maximum potential difference between two parallel conducting plates separated by \(0.500 \mathrm{~cm}\) of air, given the maximum sustainable electric field strength in air to be \(3.0 \times 10^{6} \mathrm{~V} / \mathrm{m}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.