/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 A car moving at \(10 \mathrm{m} ... [FREE SOLUTION] | 91Ó°ÊÓ

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A car moving at \(10 \mathrm{m} / \mathrm{s}\) crashes into a tree and stops in 0.26 s. Calculate the force the seat belt exerts on a passenger in the car to bring him to a halt. The mass of the passenger is \(70 \mathrm{kg}\).

Short Answer

Expert verified
The seat belt exerts a force of approximately -2692.2 N on the passenger to bring him to a halt.

Step by step solution

01

Calculate the deceleration

First, find the deceleration using the formula for acceleration, which is the change in velocity divided by the time taken. Since the final velocity is 0 m/s (because the passenger comes to a halt) and the initial velocity is 10 m/s (the speed of the car before the crash), the change in velocity is -10 m/s (0 m/s - 10 m/s = -10 m/s). The time taken is 0.26 seconds. The deceleration (a) is calculated as: \( a = \frac{\Delta v}{t} = \frac{-10 \mathrm{m/s}}{0.26 \mathrm{s}} \).
02

Compute the deceleration value

Plugging the values into the deceleration formula we get: \( a = \frac{-10 \mathrm{m/s}}{0.26 \mathrm{s}} = -38.46 \mathrm{m/s^2} \). This is the deceleration experienced by the passenger.
03

Apply Newton's second law

Use Newton's second law of motion which states that Force equals mass times acceleration (F = ma) to calculate the force. Here, the mass (m) is the mass of the passenger, 70 kg, and the acceleration (a) is the deceleration calculated in the previous step.
04

Calculate the force exerted by the seat belt

Finally, calculate the force exerted by the seat belt using the mass of the passenger and the deceleration: \( F = ma = 70 \mathrm{kg} \times -38.46 \mathrm{m/s^2} = -2692.2 \mathrm{N} \). The negative sign indicates that the force is acting in the opposite direction of the initial movement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Deceleration Calculation
The concept of deceleration is crucial when analyzing situations where an object is slowing down, as in the case of a car crash. Deceleration, which can be understood as negative acceleration, is the rate at which the velocity of an object decreases. To calculate deceleration, the change in velocity \( \Delta v \) is divided by the time \( t \) in which this change occurs. Specifically, for our exercise where a car halts from an initial velocity of \(10 \text{ m/s}\) to a standstill, the formula is:
\[ a = \frac{\Delta v}{t} \]
To compute the deceleration value, we must acknowledge that the change in velocity is \( -10 \text{ m/s} \) as the car goes from \(10 \text{ m/s}\) to \(0 \text{ m/s}\), and the time taken to stop is \(0.26 \text{ s}\). Therefore, the deceleration calculation yields a magnitude of \( -38.46 \text{ m/s}^2 \) showing a quick and significant decrease in speed in a very short time.
Newton's Second Law of Motion
Newton's second law of motion serves as a foundation for understanding the forces involved when an object's motion changes, as seen with the decelerating passenger in a car crash. This law states that the force applied on an object is equal to the mass of the object multiplied by its acceleration \( F = ma \).
In our problem, 'acceleration' refers to the deceleration since it's the type of acceleration experienced by the passenger when the car stops abruptly. To find out the amount of force exerted, it's essential to use the mass of the passenger and their calculated deceleration. Remember, force is a vector quantity, which means it has both a magnitude and a direction. The direction of the force is opposite to the direction of deceleration indicating that it acts to stop the passenger, adhering to Newton's principle for the force equation applied in real-world scenarios.
Force Exertion
The final step in our physics problem involves calculating the force exertion. When a seat belt halts a passenger abruptly, it exerts a force to counteract the motion due to the car crash. By multiplying the mass of the passenger \(70 \text{ kg}\) by the deceleration \( -38.46 \text{ m/s}^2 \), you attain the force exerted by the seat belt. It is worth noting here that the negative sign indicates the direction of the force.
In the real world, the seat belt's force is in the opposite direction to the passenger’s inertia (the tendency of the passenger to maintain its uniform motion), thereby ensuring their safety by bringing them to a stop. A thorough understanding of force exertion through the lens of Newton's laws allows us to design safer vehicles and develop better safety mechanisms that protect passengers during collisions.

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