Chapter 3: Problem 48
The motion of a body falling from rest in a resisting medium is described by the equation \(\frac{d v}{d t}=a-b v\), where \(a\) and \(b\) are constant. The velocity at any time \(t\) is: (a) \(a\left(1-b^{2 t}\right)\) (b) \(\frac{a}{b}\left(1-e^{-b t}\right)\) (c) \(a b e^{-t}\) (d) \(a b^{2}(1-t)\)
Short Answer
Step by step solution
Identify the Differential Equation
Rearrange the Differential Equation
Integrate both Sides
Solve the Left-hand Side Integral
Solve the Right-hand Side Integral
Combine and Solve for Velocity
Isolate Velocity
Apply Initial Conditions
Simplify to Obtain the Final Velocity Equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Velocity
- The differential equation \( \frac{d v}{d t} = a - b v \) shows the relationship between the rate of change of velocity \( v \) and constants \( a \) and \( b \).
- Constant \( a \) represents the initial driving force acting on the body, pushing it to accelerate.
- Constant \( b \) is a damping factor that slows the velocity due to resistance from the medium.
Integration
- We rearrange the differential equation \( \frac{d v}{d t} = a - b v \) into an integrable form: \( \frac{d v}{a-b v} = d t \).
- The purpose is to separate variables, making it possible to apply the integration process and find a function for velocity \( v \).
Integration Steps
Performing the integration gives us:- The left-hand side integral becomes \(-\frac{1}{b} \ln|a-b v| + C_1\), where \( C_1 \) is a constant of integration.
- The right-hand side integral resolves to \( t + C_2 \), another constant \( C_2 \).
Initial Conditions
- In this exercise, the initial condition is given by noting that the velocity \( v = 0 \) when \( t = 0 \).
- This condition is crucial for finding the constant \( C \) in our integrated equation: \(|a-bv| = Ce^{-bt} \).
Using the Initial Condition
Applying \( v = 0 \) at \( t = 0 \) gives us:- \(0 = \frac{a}{b} - \frac{C}{b}\)
- This simplifies to \( C = a \)
Exponential Function
- In our solution, \( e^{-bt} \) represents the exponential decay of velocity as time progresses.
- The term demonstrates how the initial velocity's effect diminishes, tending towards zero as \( t \) increases.
Role of Exponential Function
The exponential function is significant in forming the final velocity expression:- Final velocity: \( v = \frac{a}{b}(1-e^{-bt}) \)
- This indicates that initially, the exponential term influences the velocity heavily, but decreases over time towards stabilization (terminal velocity).