Chapter 27: Problem 42
Two thin long parallel wires separated by a distance \(b\) are carrying a current \(I\) amp each. The magnitude of the force per unit length exerted by one wire on the other is : (a) \(\frac{\mu_{0} I^{2}}{b^{2}}\) (b) \(\frac{\mu_{0} l^{2}}{2 \pi b}\) (c) \(\frac{\mu_{0} I}{2 \pi b}\) (d) \(\frac{\mu_{0} l}{2 \pi b^{2}}\)
Short Answer
Step by step solution
Formula for Magnetic Force between Two Parallel Currents
Substitute Given Values
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Biot-Savart Law
- \( \mu_0 \) is the permeability of free space.
- \( \mathbf{r} \) is the position vector from the current element to the point of interest.
- \( \times \) indicates the cross product.
Ampère's Circuital Law
Electromagnetic Interaction
Force between Parallel Conductors
- \( F \) is the magnetic force.
- \( L \) is the length of the wires considered for the force calculation.
- \( \mu_0 \) is the permeability of free space.
- \( b \) is the distance between the wires.