/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 A man is running towards a plane... [FREE SOLUTION] | 91Ó°ÊÓ

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A man is running towards a plane mirror with some velocity. If the relative velocity of his image with respect to him is \(4 \mathrm{~m} / \mathrm{s}\), then the velocity of a man is : (a) \(2 \mathrm{~m} / \mathrm{s}\) (b) \(4 \mathrm{~m} / \mathrm{s}\) (c) \(8 \mathrm{~m} / \mathrm{s}\) (d) \(16 \mathrm{~m} / \mathrm{s}\)

Short Answer

Expert verified
The velocity of the man is \( 2 \mathrm{~m/s} \).

Step by step solution

01

Understanding Image Velocity

When a man runs towards a plane mirror, his image appears to move towards him with the same speed. If the man moves with velocity \( v \), his image will also move with velocity \( v \) with respect to the mirror, but in the opposite direction.
02

Calculate Relative Velocity

The relative velocity of the image with respect to the man is given by the sum of their velocities, because they move towards each other. So, the relative velocity is \( v + v = 2v \).
03

Set Equation with Given Relative Velocity

We are given that the relative velocity of the image with respect to the man is \( 4 \mathrm{~m/s} \). So we have \( 2v = 4 \).
04

Solve for Velocity of Man

To find \( v \), divide both sides of the equation by 2: \( v = \frac{4}{2} = 2 \mathrm{~m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plane Mirror
A plane mirror is a flat reflective surface. When you look into a plane mirror, the image you see is essentially a reflection of yourself. This image maintains characteristics such as size and orientation, appearing as a virtual, upright image located behind the mirror.
When objects move toward or away from a plane mirror, their images in the mirror move too. Interestingly, the image seems to move in the opposite direction of the actual object. This happens because the reflected light follows specific paths dictated by the angles of incidence and reflection. The angles ensure that the path of light arriving from the object and then leaving towards your eye creates a virtual reflection: the object is perceived as being inside the mirror, just as far away as the actual object is outside.
Image Velocity
In kinematics, 'image velocity' refers to the speed at which the image of an object appears to move in a mirror. This is due to the motion of the object itself. If you run towards a plane mirror at a certain speed, your image will seem to run towards you at the same speed.
  • The velocity of the image is the same as the velocity of the object.
  • If an object moves towards the mirror, the image moves equally fast towards it.

For our example, if a man moves at speed \( v \), the image will seem to move with the same velocity \( v \) but towards the mirror. Hence, the image and the object approach each other with a combined or relative velocity of \( 2v \).
Kinematics
Kinematics is a branch of physics dealing with motion, explaining the movement of objects without addressing forces. It uses quantities such as velocity, acceleration, displacement, and time to describe how objects move.
When understanding the relative velocity in our mirror problem, kinematics helps us calculate how fast things move towards or away from each other. Since the observed image moves towards the object, the relative velocity is a key parameter to solve the problem.
In a mirror scenario:
  • If the relative speed of the image with respect to the moving object is known, it provides clues to the speed of the object itself.
  • For the man running towards the plane mirror, the basic kinematic equation \( 2v = \) relative velocity can be applied to determine his speed.
Optics
Optics is the study of light behavior and propagation. In the context of plane mirrors and image formation, optics explores how light reflects and how images are perceived by the eyes.
The rule that light reflects off a surface following specific angles of incidence and reflection underlies how plane mirrors create images. When light rays bounce off the reflective surface, they project an image that looks like it's behind the mirror. This projection allows us to understand not just where the image is but also how it appears to move when the object moves.
A significant principle in optics pertaining to plane mirrors:
  • The image is always virtual, appearing to be located behind the mirror.
  • The size and velocity of the image mirror that of the object, maintaining a one-to-one relationship in velocity measurement.
By understanding these principles, you can predict image behavior in scenarios involving motion, just as in the problem provided.

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Most popular questions from this chapter

The position of \(1 \mathrm{~cm}\) tall object which is placed \(8 \mathrm{~cm}\) infront of a concave mirror of radius of curvature \(24 \mathrm{~cm}\) is: (a) \(24 \mathrm{~cm}\) (b) \(25 \mathrm{~cm}\) (c) \(26 \mathrm{~cm}\) (d) \(27 \mathrm{~cm}\)

A short linear object of Iength \(l\) lies on the axis of a spherical mirror of focal length \(f\), at a distance \(x\) from the mirror. Then the length of the image \((P)\) so obtained will be : (a) \(\frac{l f}{(x-f)}\) (b) \(\frac{l f^{2}}{(x-f)^{2}}\) (c) \(\frac{l f}{x}\) (d) \(\frac{l(x-f)}{x}\)

In the measurement of the focal length \(f\) of a concave mirror, the object distance \(u=40 \pm 0.1 \mathrm{~cm}\) and image distance \(v=20 \pm 0.2 \mathrm{~cm}\). The maximum \(\%\) error in the measure of \(f\) is : (a) \(1.75\) (b) \(0.75\) (c) \(0.3\) (d) \(2.25\)

Two objects ' \(A^{\prime}\) and ' \(B\) ' when placed in turns infront of a concave mirror, give images of equal size. The focal length of the concave mirror is \(7.5 \mathrm{~cm}\) and size of object \(A\) is three times the size of object \(B\). The distance of \(B\) from the mirror, if \(A\) is placed \(30 \mathrm{~cm}\) from the mirror, is : (a) \(18 \mathrm{~cm}\) (b) \(15 \mathrm{~cm}\) (c) \(20 \mathrm{~cm}\) (d) \(25 \mathrm{~cm}\)

Mark correct option : (a) The laws of reflection of light hold only for plane surfaces (b) The size of virtual image can be measured by receiving it on screen (c) Plane mirror alongs form an erect image (d) Plane mirror may form inverted image

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