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A short linear object of Iength \(l\) lies on the axis of a spherical mirror of focal length \(f\), at a distance \(x\) from the mirror. Then the length of the image \((P)\) so obtained will be : (a) \(\frac{l f}{(x-f)}\) (b) \(\frac{l f^{2}}{(x-f)^{2}}\) (c) \(\frac{l f}{x}\) (d) \(\frac{l(x-f)}{x}\)

Short Answer

Expert verified
The answer is (a) \(\frac{l f}{x-f}\).

Step by step solution

01

Understanding Image Formation

When an object is placed along the axis of a spherical mirror, the image characteristics (size, orientation) can be described using the mirror formula: \(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\), where \(f\) is the focal length, \(v\) is the image distance and \(u\) is the object distance.
02

Apply Mirror Formula

We need to calculate the image distance \(v\). Rearranging the mirror formula gives \(\frac{1}{v} = \frac{1}{f} - \frac{1}{x}\). Solving this, we find \(v = \frac{fx}{x-f}\).
03

Calculate Magnification

The magnification \(m\) for a mirror is given by the ratio of the image distance to the object distance: \(m = \frac{v}{x}\). Substituting \(v = \frac{fx}{x-f}\), we get \(m = \frac{f}{x-f}\).
04

Determine Image Length

The length of the image \(P = \text{magnification} \times \text{object length}\). Hence, \(P = m \times l = \frac{f}{x-f} \times l\). Simplifying gives \(P = \frac{lf}{x-f}\).
05

Verify with Options

Compare the derived expression \(\frac{lf}{x-f}\) with the given options. This matches option (a) \(\frac{lf}{x-f}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mirror Formula
The mirror formula is a fundamental equation used to describe the relationship between the various distances involved when dealing with spherical mirrors. The formula is expressed as \( \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \). Here, \( f \) represents the focal length, \( v \) is the image distance, and \( u \) is the object distance.
  • Focal length (\( f \)): The distance between the mirror's pole and its focal point.
  • Image distance (\( v \)): The distance from the mirror to the location where the image is formed.
  • Object distance (\( u \)): The distance from the mirror to the object.
This formula is critical because it allows us to compute unknown values if the other two are provided. It's applicable for both concave and convex mirrors. Always remember the sign conventions when using this formula. In mirror problems, object distances are usually taken negative (by convention), while focal length can be positive or negative depending on the type of mirror (positive for concave, negative for convex).
Image Formation
Image formation by spherical mirrors involves determining the characteristics of the image, such as its size, location, and orientation. Using the mirror formula, you can locate where the image will be formed for a given object distance.
  • Image distance (\( v \)): You can find the image distance using the rearranged mirror formula: \( \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \).
  • Size & orientation: The size and orientation are determined by the type of mirror and the object's position relative to the mirror.
The nature of the image (whether it's real or virtual, inverted or upright) depends on the object distance in relation to the focal point. Understanding the rules of image formation will help you predict the characteristics of the image.
Magnification
Magnification is the process of enlarging the appearance of an image formed by a spherical mirror. It's quantified by the magnification factor \( m \), which describes how much larger or smaller the image is compared to the object.The formula for magnification is given by:\[m = \frac{v}{u}\]Here, \( v \) is the image distance, and \( u \) is the object distance.In situations involving spherical mirrors:
  • When \( m > 1 \), the image is larger than the object.
  • When \( m < 1 \), the image is smaller.
  • When \( m = 1 \), image size equals object size.
  • The sign of \( m \) also indicates orientation: a negative magnification means the image is inverted, while a positive magnification means the image is upright.
In the exercise, calculating magnification allows us to determine the length of the image, given by \( P = m \times l \). This results in the expression \( P = \frac{lf}{x-f} \) based on the calculated magnification \( m = \frac{f}{x-f} \).
Focal Length
The focal length is an intrinsic property of mirrors that describes the distance from the mirror's pole to its focal point. It plays a critical role in determining how light converges (in concave mirrors) or appears to diverge (in convex mirrors) after hitting the mirror's surface. Understanding the focal length encompasses:
  • Positive for concave mirrors: In concave mirrors, the focus is real and located on the same side as the incoming light, hence a positive focal length.
  • Negative for convex mirrors: In convex mirrors, the focus is virtual and located behind the mirror, assigning it a negative focal length.
By employing the knowledge of focal length, we gain insights into how image characteristics such as size and orientation change based on the positioning of the object in relation to the focal point.

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Most popular questions from this chapter

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