Chapter 19: Problem 62
A short linear object of Iength \(l\) lies on the axis of a spherical mirror of focal length \(f\), at a distance \(x\) from the mirror. Then the length of the image \((P)\) so obtained will be : (a) \(\frac{l f}{(x-f)}\) (b) \(\frac{l f^{2}}{(x-f)^{2}}\) (c) \(\frac{l f}{x}\) (d) \(\frac{l(x-f)}{x}\)
Short Answer
Step by step solution
Understanding Image Formation
Apply Mirror Formula
Calculate Magnification
Determine Image Length
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mirror Formula
- Focal length (\( f \)): The distance between the mirror's pole and its focal point.
- Image distance (\( v \)): The distance from the mirror to the location where the image is formed.
- Object distance (\( u \)): The distance from the mirror to the object.
Image Formation
- Image distance (\( v \)): You can find the image distance using the rearranged mirror formula: \( \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \).
- Size & orientation: The size and orientation are determined by the type of mirror and the object's position relative to the mirror.
Magnification
- When \( m > 1 \), the image is larger than the object.
- When \( m < 1 \), the image is smaller.
- When \( m = 1 \), image size equals object size.
- The sign of \( m \) also indicates orientation: a negative magnification means the image is inverted, while a positive magnification means the image is upright.
Focal Length
- Positive for concave mirrors: In concave mirrors, the focus is real and located on the same side as the incoming light, hence a positive focal length.
- Negative for convex mirrors: In convex mirrors, the focus is virtual and located behind the mirror, assigning it a negative focal length.