Chapter 11: Problem 35
A block of wood floats with \(1 / 4\) of its volume under water. What is the density of the wood? (Density of water \(=1000 \mathrm{~kg} / \mathrm{m}^{3}\) ) (a) \(750 \mathrm{~kg} / \mathrm{m}^{3}\) (b) \(250 \mathrm{~kg} / \mathrm{m}^{3}\) (c) \(300 \mathrm{~kg} / \mathrm{m}^{3}\) (d) \(260 \mathrm{~kg} / \mathrm{m}^{3}\) \(\mathbf{A 4}\)
Short Answer
Step by step solution
Understand the Problem
Apply Archimedes' Principle
Set Up the Equation
Solve for Density of Wood
Select the Correct Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Buoyant Force
- When an object is placed in a fluid, it pushes the fluid out of the way. This displaced fluid has weight.
- The fluid "pushes back" with a force equal to this weight, which is the buoyant force.
Density Calculation
- When comparing the density of an object to the fluid it is in, we can predict whether the object will float or sink.
- If the object is less dense than the fluid, it will float. If more dense, it will sink.
Volume Displacement
- More submerged volume leads to more displaced fluid, which in turn means a greater buoyant force.
- The idea of displacement is key to applying Archimedes' Principle, as it ties the fluid's weight to the buoyant force.