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Bernoulli's equation is applicable to points : (a) in a steadily flowing liquid (b) in a stream line (c) in a straight line perpendicular to a stream line (d) in any non-viscous liquid

Short Answer

Expert verified
(a) in a steadily flowing liquid; (b) in a stream line.

Step by step solution

01

Understand Bernoulli's Equation

Bernoulli's equation states that for an incompressible, non-viscous fluid undergoing steady flow, the sum of its pressure energy, kinetic energy per unit volume, and potential energy per unit volume remains constant along a streamline.
02

Identify the Key Conditions

Bernoulli's equation is specifically applicable to points within a streamline of a fluid that is flowing steadily, meaning that the speed of flow is constant at any given point along the streamline.
03

Evaluate Each Option

Review each option: (a) is correct because Bernoulli’s equation applies when the flow is steady. (b) is correct because it applies along a streamline. (c) is incorrect because it must be applied along, not perpendicular to, a streamline. (d) is incorrect because 'any' non-viscous liquid also requires a streamline and steady flow condition.
04

Select the Correct Options

Based on the evaluation, the correct choices are (a) and (b). These options satisfy the conditions for the applicability of Bernoulli's equation: steady flow and points along a streamline.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Streamline Flow
Streamline flow is a fundamental concept when discussing fluid dynamics, particularly with Bernoulli's equation. It refers to the smooth layer of flow in a fluid where each particle follows a path called a streamline.
A streamline is essentially an imaginary line drawn tangentially along the flow direction, showing the trajectory of fluid particles.
Key characteristics of streamline flow include:
  • Each point on a streamline represents a path followed by the fluid particle.

  • The velocity of the fluid remains constant along a given streamline at steady flow conditions.

  • Streamlines never intersect, meaning the flow pattern is stable and consistent.

Understanding streamline flow is crucial for applying Bernoulli's equation because the equation requires analysis of points along these precise paths. It ensures that energy conservation can be appropriately calculated since each fluid particle on a streamline maintains uniform behavior.
Incompressible Fluid
An incompressible fluid is one of the main conditions under which Bernoulli's equation applies. It is a fluid whose density remains constant regardless of changes in pressure or flow.
In simpler terms, no matter how you squeeze or pressurize the fluid, its volume doesn't change. This assumption simplifies calculations related to fluid flow.
Characteristics of incompressible fluids include:
  • Density is constant throughout flow conditions.

  • Highly applicable to liquids, as opposed to gases which can often be compressed easily.

  • Allows the conservation of mass principle to always hold true with any given volume of the fluid.

In the context of Bernoulli's equation, assuming that a fluid is incompressible is key since it helps in establishing that speed, pressure, and elevation can change, but the density of the fluid remains unchanged throughout these conditions.
Steady Flow
In the realm of fluid dynamics, steady flow denotes a flow where the velocity of the fluid at a particular point does not change with time. It's like the fluid has settled into a stable, predictable pattern.
This concept is essential for applying Bernoulli's equation, as it stipulates a consistent flow behavior.
Features of steady flow include:
  • Flow characteristics (such as velocity and pressure) at any point remain constant over time.

  • There's no turbulence; hence the variables don't fluctuate.

  • Each particle of the fluid follows the same path as the previous fluid particle that passed that point.

By ensuring the flow is steady, Bernoulli's equation keeps the underlying assumptions intact, thereby allowing for accurate calculations of fluid properties along the streamlines.
Non-viscous Fluid
When considering Bernoulli's equation, a non-viscous fluid means the fluid has no internal friction or viscosity. It's an idealization often used in theoretical calculations to simplify the complex nature of real fluids.
Viscosity refers to the internal resistance of a fluid to flow, with higher viscosity implying more resistance to flow.
Understanding non-viscous fluids involves:
  • The assumption of zero viscosity, which means there’s no energy loss in the fluid.

  • Simplifies calculations, since viscosity introduces complexity due to internal friction causing energy dissipation.

  • Ideal fluids are considered non-viscous; however, most real fluids have some level of viscosity.

While actual fluids have viscosity, assuming a fluid is non-viscous in problems applying Bernoulli's equation is useful for focusing on other factors affecting flow, like pressure and speed changes along the streamline.

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Most popular questions from this chapter

There is a wide tank of cross-section area \(A\) contain a liquid to a height \(H\) has a small orifice at its base of area \(' a^{\prime}(a<1)\) (a) \(t=\left(\frac{A}{a}\right)\left[\sqrt{\frac{1}{g}}\left(\sqrt{H}-\sqrt{\frac{H}{\eta}}\right)\right]\) (b) \(t=\left(\frac{a}{A}\right)\left[\sqrt{\frac{2}{g}}\left(\sqrt{H}-\sqrt{\frac{H}{\eta}}\right)\right]\) (c) \(t=\left(\frac{a}{A}\right)\left[\sqrt{\frac{1}{g}}\left(\sqrt{H}-\sqrt{\frac{H}{\eta}}\right)\right]\) (d) \(t=\left(\frac{A}{a}\right)\left[\frac{1}{\sqrt{2 g}}\left(\sqrt{H}-\sqrt{\frac{H}{\eta}}\right)\right]\)

A solid is completely immersed in a liquid. The force exerted by the liquid on the solid will : (a) increase if it pushed deeper inside the liquid (b) change if its orientation is changed (c) decrease if it is taken partially out of the liquid (d) none of the above

A liquid of density \(\rho_{0}\) is filled in a wide tank to a height \(h\). A solid rod of length \(L\), corss-section area \(A\) and density \(\rho\) is suspended freely in the tank. The lower end of the rod touches the base of the tank and \(h=\frac{L}{\eta}\) (where \(\eta>1\) ). Then what should be angle of inclination of the rod with the horizontal in the equilibrium position (a) \(\theta=\sin ^{-1}\left(\frac{1}{\eta} \sqrt{\left(\frac{\rho_{0}}{\rho}\right)}\right)\) (b) \(\theta=\sin ^{-1}\left(\frac{1}{\eta} \sqrt{\left(\frac{\rho}{\rho}\right)}\right)\) (c) \(\theta=\sin ^{-1}\left(\eta \sqrt{\left(\frac{\rho_{0}}{\rho}\right)}\right)\) (d) \(\theta=\sin ^{-1}\left(\sqrt{\left(\frac{\rho_{0}}{\rho}\right)}\right)\)

A liquid is contained in a vertical U-tube. The total length of the liquid column inside the tube is \(l\). When the liquid is in equilibrium, the liquid is just pushed down slightly. If one of the arms of U-tube are released, the entire liquid column will start a periodic motion. Then: (a) the motion is not S.H.M. (b) the motion is S.H.M. (c) if it undergoes S.H.M., the time period will be \(2 \pi \sqrt{\left(\begin{array}{l}l \\ g\end{array}\right)}\) (d) if it undergoes S.H.M., the time period will be \(2 \pi \sqrt{\left(\frac{l}{2 g}\right)}\)

The horizontal flow of fluid depends upon (a) pressure difference (b) amount of fluid (c) density of fluid (d) all the above

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