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Use the result of the previous problem and the approximate values of a and b to find the value of Tc, Pc, Vc/N for N2, H2O and He.

Short Answer

Expert verified

N2
H2O
He
VC/N (m3)
18×10-29

18×10-29

role="math" localid="1647074922910" 3×10-29
PC (Pa)
4.11×106
1.64×107

3.7×107
TC(K)
14357221.5

Step by step solution

01

Given information

We know from problem 5.48

Vc=3NbPc=127ab2Tc=38akb

Values of a and b are given as


N2
H2O
He
a (J-m3)4×10-49
1.6×10-48
1×10-50
brole="math" localid="1647074059853" (m3)6×10-29
6×10-29
1×10-29
02

substituting the data 


N2
H2O
He
Vc/N(m3)
18×10-29
18×10-29
3×10-29
Pc (Pa)
4.11×106
1.64×107
3.7×107
Tc(K)
14357221.5

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