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Calculate the total thermal energy in a gram of lead at room temperature, assuming that none of the degrees of freedom are "frozen out" (this happens to be a good assumption in this case).

Short Answer

Expert verified

The total thermal energyU=35.3J.

Step by step solution

01

Step 1. Introduction.

Each atom in lead has six degrees of freedom in terms of vibration (3kinetic and 3potential). There are no transitional degrees of freedom, and there are no rotational degrees of freedom for a single atom because the atoms are fixed in their locations in the lattice.

02

Step 2. Explanation.

Given the molar mass of lead, the number of molecules in one gram of lead is,

Hereu=1.66×10kg27.

N=massmolar mass=1×103kg207.2×1.66×1027kg=2.91×1021

The thermal energy at T=293K

U=f2NkT=62×2.91×1021×1.38×1023×293=35.3J

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