/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 1.2 The Rankine temperature scale(ab... [FREE SOLUTION] | 91影视

91影视

The Rankine temperature scale(abbreviated R) uses the same scale size degrees as Fahrenheit, but measured up from absolute zero like Kelvin(so Rankine is to Fahrenheit as Kelvin is to Celsius). Find the conversion formula between Rankine and Fahrenheit and also between Rankine and Kelvin. What is the room temperature on the Rankine scale?

Short Answer

Expert verified

R = 95K and R = 536.67R

Step by step solution

01

Writing the conversion equations of Kelvin to Celsius and Rankine to Fahrenheit.

The conversion equation for Kelvin to Celsius is,

K = C + 273.15 -----------(1)

and similarly conversion equation for Rankine to Fahrenheit is,

R = F + 459.67 -----------(2)

02

Comparison of Kelvin and Rankine scales at absolute zero,

But we know that, F = 95C+32

substituting this in equation (2),

R = 95C+491.67

substituting C from equation (1), we get,

R =95K

03

Standard room temperature in Celsius scale usually refers to 25°C and using the conversion formula to write in Rankine scale.

The room temperature in Kelvin scale will be 25 + 273.15 = 298.15K

Applying the conversion formula of Kelvin to Rankine scale, we get,

R = 95(298.15)

R = 536.67R

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cup containing 200g of water is sitting on your dining room table. After carefully measuring its temperature to be 20oC, you leave the room. Returning ten minutes later, you measure its temperature again and find that it is now 25oC. What can you conclude about the amount of heat added to the water? (Hint: This is a trick question.)

During a hailstorm, hailstones with an average mass of 2g and a speed of 15 m/s strike a window pane at a 45o angle. The area of the window is 0.5 m2 and the hailstones hit it at a rate of 30 per second. What average pressure do they exert on the window? How does this compare to the pressure of the atmosphere?


An ideal diatomic gas, in a cylinder with a movable piston, undergoes the rectangular cyclic process shown in Figure 1.10(b). Assume that the temperature is always such that rotational degrees of freedom are active, but vibrational modes are 鈥渇rozen out.鈥 Also, assume that the only type of work done on the gas is quasistatic compression-expansion work.

  1. For each of the four steps A through D, compute the work done on the gas, the heat added to the gas, and the change in the energy content of the gas. Express all answers in terms of P1, P2, V1, and V2. (Hint: Compute role="math" localid="1651641251162" Ubefore Q, using the ideal gas law and the equipartition theorem.)
  2. Describe in words what is physically being done during each of the four steps; for example, during step A, heat is added to the gas (from an external flame or something) while the piston is held fixed.
  3. Compute the net work done on the gas, the net heat added to the gas, and the net change in the energy of the gas during the entire cycle. Are the results as you expected? Explain briefly.

Consider a narrow pipe filled with fluid, where the concentration of a specific type of molecule varies only along its length (in the x direction). Fick's second law is derived by considering the flux of these particles from both directions into a short segmentx

nt=D2nx2

Does it ever make sense to say that one object is "twice as hot" as another? Does it matter whether one is referring to Celsius or Kelvin temperatures? Explain.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.