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Chapter 9: Problem 50

In a common base mode of a transistor, the collector current is \(5.488 \mathrm{~mA}\) for an emitter current of \(5.60 \mathrm{~mA}\). The value of the base current amplification factor \((\beta)\) will be (A) 48 (B) 49 (C) 50 (D) 51

Short Answer

Expert verified
The base current amplification factor (尾) can be calculated using the formula 尾 = Ic/Ib. First, find the base current (Ib) using the given emitter current (Ie) and collector current (Ic) values: Ib = Ie - Ic = 5.60 mA - 5.488 mA = 0.112 mA. Next, calculate 尾: 尾 鈮� (5.488 mA)/(0.112 mA) 鈮� 49. Therefore, the base current amplification factor (尾) is approximately 49, which corresponds to option (B).

Step by step solution

01

Find the base current (Ib)

First, we need to find the base current (Ib) using the relation between emitter, collector, and base currents: Ie = Ic + Ib We are given Ie = 5.60 mA, and Ic = 5.488 mA. We can solve for Ib: Ib = Ie - Ic = 5.60 mA - 5.488 mA
02

Calculate the base current (Ib)

Now, calculate the value of Ib: Ib = 5.60 mA - 5.488 mA = 0.112 mA
03

Calculate the base current amplification factor (尾)

Next, we'll calculate the base current amplification factor (尾) using the formula: 尾 = Ic/Ib Where Ic = 5.488 mA and Ib = 0.112 mA.
04

Compute 尾

Now, compute the value of 尾: 尾 = (5.488 mA)/(0.112 mA)
05

Determine the final answer

Calculate the final value of 尾: 尾 鈮� 49 Thus, the base current amplification factor (尾) is approximately 49, which corresponds to option (B).

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