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Statement-1: Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement-2: Principle of conservation of momentum holds true for all kinds of collisions. (A) Statement-1 is true, Statement- 2 is true; Statement- 2 is the correct explanation of Statement- 1 (B) Statement-1 is true, Statement- 2 is true; Statement- 2 is not the correct explanation of Statement-1 (C) Statement- 1 is false, Statement- 2 is true. (D) Statement- 1 is true, Statement- 2 is false.

Short Answer

Expert verified
(B) Statement-1 is true, Statement- 2 is true; Statement- 2 is not the correct explanation of Statement-1

Step by step solution

01

Understanding Collisions

A collision occurs when two objects (particles) come into contact with each other. Collisions can be classified as elastic and inelastic. In an elastic collision, both momentum and kinetic energy are conserved, while in an inelastic collision, only momentum is conserved and kinetic energy is not. A completely inelastic collision is a special type of inelastic collision where the two particles stick together after the collision.
02

Analyzing Statement-1

In this statement, it is mentioned that "Two particles moving in the same direction do not lose all their energy in a completely inelastic collision." Let's see if this statement is true or false. In a completely inelastic collision, the particles stick together after the collision, thus forming a single mass. In such a case, the final kinetic energy would be lesser than the initial kinetic energy, but not zero. Therefore, it is correct to say that the particles do not lose all their energy in a completely inelastic collision.
03

Analyzing Statement-2

In this statement, it is mentioned that "Principle of conservation of momentum holds true for all kinds of collisions." According to the principle of conservation of momentum, the total momentum before the collision should be equal to the total momentum after the collision. This principle holds true in all types of collisions, i.e., elastic, inelastic, and completely inelastic. Hence, the statement is true. Now, let's move on to identifying the relationship between the two statements.
04

Relationship between Statement-1 and Statement-2

From our analysis, both Statement-1 and Statement-2 are true. However, the principle of conservation of momentum (Statement-2) does not offer a correct explanation for Statement-1. The reason why particles don't lose all their energy in completely inelastic collisions is due to the conservation of kinetic energy and the nature of the collision, not because of the conservation of momentum. Therefore, our answer is: (B) Statement-1 is true, Statement- 2 is true; Statement- 2 is not the correct explanation of Statement-1

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principle of Conservation of Momentum
The principle of conservation of momentum is a fundamental concept in physics. It states that the total momentum of a closed system remains constant if no external forces are acting on it. Momentum, which is the product of mass and velocity, is a vector quantity, meaning it has both magnitude and direction.

In the context of a collision, this principle implies that the sum of the momenta of the colliding particles before the collision is equal to the sum of their momenta after the collision. This holds true regardless of whether the collision is elastic, inelastic, or completely inelastic. Here are some key points to consider:
  • Momentum is conserved in all collisions because internal forces during a collision are equal and opposite, according to Newton’s third law.
  • For a closed system, where no external interference occurs, momentum conservation applies to each axis. Total momentum in the x-direction, y-direction, and z-direction will each be conserved.
  • The principle helps determine the final velocities of objects after a collision when masses and initial velocities are known.
Understanding this principle is essential when analyzing the behavior of particles before and after interactions.
Completely Inelastic Collision
In a completely inelastic collision, the colliding particles stick together after impact, moving as a single entity. This type of collision is a specific category of inelastic collision widely studied for its unique properties.

When two objects collide and move together post-collision, it signifies that they have reached a maximum energy loss due to the transformation of kinetic energy into other forms, like heat or sound. Here are the main points:
  • The final momentum of the combined mass is equal to the initial total momentum of the individual masses, consistent with the conservation of momentum.
  • While some mechanical energy is transformed into other energy forms, not all the kinetic energy is lost. The final kinetic energy is simply less than the initial total kinetic energy.
  • Given momentum conservation, this can be expressed mathematically as: \( m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \), where \(v_f\) is the final velocity of the combined object.
This collision type demonstrates an extreme where objects maximize kinetic energy loss but conserve momentum.
Kinetic Energy Conservation
The concept of kinetic energy conservation depends on the nature of the collision. In an ideal setting with no energy loss, we would have a perfectly elastic collision, which conserves both momentum and kinetic energy. However, this is not the case for inelastic collisions.

During an inelastic collision, kinetic energy is not conserved. Instead, some of this energy is transformed into different forms, such as thermal energy, sound, or internal potential energy, due to deformation of the bodies involved. Let's look at the details:
  • In completely elastic collisions, kinetic energy before and after the collision remains constant: \( \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 = \frac{1}{2}m_1v_1'^2 + \frac{1}{2}m_2v_2'^2 \).
  • For completely inelastic collisions, the aforementioned energy equation does not hold since the energy transforms into other forms.
  • The energy conversion indicates a more realistic interaction where not all kinetic energy is retained as kinetic.
Understanding these distinctions helps clarify why kinetic energy is not conserved in most real-world collisions, reinforcing the need to look beyond just mechanical viewpoints to account for all forms of energy.

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Most popular questions from this chapter

Which of the following statements is/are correct? (A) In head on elastic collision of two bodies of equal masses, velocities of colliding bodies interchange. (B) In case of elastic collision kinetic energy remains conserved before collision and during collision. (C) In case of elastic collision momentum is conserved before and during the collision (assuming that no other force acts on the bodies). (D) In case of oblique elastic collision of two bodies of equal masses the velocities of colliding bodies interchange.

A small ball thrown at an initial velocity \(u\) directed at an angle \(\theta=37^{\circ}\) above the horizontal collides inelastically \((e=1 / 4)\) with a vertical massive wall moving with a uniform horizontal velocity \(u / 5\) towards ball. After collision with the wall, the ball returns to the point from where it was thrown. Neglect friction between ball and wall. The time \(t\) from beginning of motion of the ball till the moment of its impact with the wall is \(\left(\tan 37^{\circ}=3 / 4\right)\) (A) \(\frac{3 u}{5 g}\) (B) \(\frac{18 u}{25 g}\) (C) \(\frac{54 u}{125 g}\) (D) \(\frac{54 u}{25 g}\)

A trolley containing water has total mass \(4000 \mathrm{~kg}\) and is moving at a speed of \(40 \mathrm{~m} / \mathrm{s}\). Now water start coming out of a hole at the bottom of the trolley at the rate of \(8 \mathrm{~kg} / \mathrm{s}\). Speed of trolley after \(50 \mathrm{~s}\) is (A) \(44.44 \mathrm{~m} / \mathrm{s}\) (B) \(40 \mathrm{~m} / \mathrm{s}\) (C) \(44 \mathrm{~m} / \mathrm{s}\) (D) \(54.44 \mathrm{~m} / \mathrm{s}\)

A block of mass \(m\) is placed on a rough horizontal surface. The coefficient of friction between them is \(\mu\). An external horizontal force is applied to the block and its magnitude is gradually increased. The force exerted by the block on the surface is \(R\), then which of the following statement/s is/are correct. (A) The magnitude of \(R\) will gradually increase. (B) \(R \leq m g \sqrt{\mu^{2}+1}\). (C) The angle made by \(R\) with the vertical will gradually increase. (D) The angle made by \(R\) with the vertical \(\leq \tan ^{-1} \mu\).

A projectile of mass \(m\) is thrown with velocity \(v\) making an angle of \(30^{\circ}\) with vertical. Neglecting air resistance the magnitude of change in momentum between the starting point and at the maximum height is (A) \(\frac{m v}{2}\) (B) \(\frac{\sqrt{3} m v}{2}\) (C) \(m v\) (D) \(\frac{\sqrt{7} m v}{2}\)

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