/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 103 A block of mass \(m\) is placed ... [FREE SOLUTION] | 91Ó°ÊÓ

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A block of mass \(m\) is placed on a rough horizontal surface. The coefficient of friction between them is \(\mu\). An external horizontal force is applied to the block and its magnitude is gradually increased. The force exerted by the block on the surface is \(R\), then which of the following statement/s is/are correct. (A) The magnitude of \(R\) will gradually increase. (B) \(R \leq m g \sqrt{\mu^{2}+1}\). (C) The angle made by \(R\) with the vertical will gradually increase. (D) The angle made by \(R\) with the vertical \(\leq \tan ^{-1} \mu\).

Short Answer

Expert verified
The short answer is: All the given statements A, B, C, and D are correct.

Step by step solution

01

Identify the forces acting on the block

First, let's list the forces acting on the block: 1. Gravitational force (weight) acting downwards: W = mg 2. Normal force acting from the surface on the block, perpendicular to the surface: N 3. Frictional force acting on the block, parallel to the surface and opposite to the direction of motion: f = μN 4. The external horizontal force acting on the block: F
02

Write the equations for net force

We can write the equations for the net force acting on the block in the horizontal (x) and vertical (y) directions. Forces in the x-direction: \(F_{net_x} = F - f\) Forces in the y-direction: \(F_{net_y} = N - W\)
03

Analyze the force exerted by the block R

The force exerted by the block on the surface (R) is the net force experienced by the block due to all the forces acting on it. The magnitude of R can be found using the Pythagorean theorem: \(R = \sqrt{F_{net_x}^2 + F_{net_y}^2} = \sqrt{(F - f)^2 + (N - W)^2}\) Also, the angle θ that R makes with the vertical can be found using trigonometry: \(\tan(\theta) = \frac{F_{net_x}}{F_{net_y}} = \frac{F - f}{N - W}\)
04

Evaluate the given statements

(A) The magnitude of R will gradually increase. - As the external force F is gradually increased, the frictional force f will increase until it reaches its maximum value (μN). After that, it remains constant, so the net horizontal force (F - f) will increase, which will also lead to an increase in the magnitude of R. Therefore, statement A is correct. (B) \(R \leq mg\sqrt{\mu^2 + 1}\). - We can rewrite the inequality as: \(\sqrt{(F - f)^2 + (N - W)^2} \leq mg\sqrt{\mu^2 + 1}\) This inequality holds true in general, so statement B is also correct. (C) The angle made by R with the vertical will gradually increase. - As the external force F increases, the net horizontal force (F - f) will increase, causing the angle between R and the vertical to increase. Therefore, statement C is correct. (D) The angle made by R with the vertical \(\leq \tan^{-1} \mu\). - For small values of F, the angle between R and the vertical will be less than the maximum angle \(\tan^{-1} \mu\). However, as F increases, the net horizontal force (F - f) will increase, causing the angle between R and the vertical to increase and reach a value equal to \(\tan^{-1} \mu\) for the limiting case. So, statement D is also correct. In conclusion, all the given statements A, B, C, and D are correct.

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