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Chapter 20: Problem 37

The phase difference between input and output voltages of a \(C E\) circuit is (A) \(0^{\circ}\) (B) \(90^{\circ}\) (C) \(180^{\circ}\) (D) \(270^{\circ}\)

Short Answer

Expert verified
The phase difference between input and output voltages of a common emitter (CE) circuit is \(180^{\circ}\) (option C). This is because the output voltage (across the collector-emitter junction) is 180 degrees out of phase with the input voltage (base-emitter junction).

Step by step solution

01

Recall characteristics of a CE circuit

In a common emitter (CE) circuit, the input is applied to the base-emitter junction, and the output is taken across the collector-emitter junction. The main characteristics of a CE circuit are that it provides voltage amplification and has a phase shift between the input and output signals.
02

Determine the phase difference

For a common emitter circuit, the output voltage (across the collector-emitter junction) is 180 degrees out of phase with the input voltage (base-emitter junction). This means that when the input voltage increases, the output voltage decreases, and vice versa. Therefore, the phase difference between the input and output voltages is \(180^{\circ}\). The correct option is (C) \(180^{\circ}\).

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