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Chapter 15: Problem 113

The value of mass \(m\) is (A) \(2 \mathrm{~kg}\) (B) \(0.5 \mathrm{~kg}\) (C) \(1 \mathrm{~kg}\) (D) \(1.5 \mathrm{~kg}\)

Short Answer

Expert verified
As there is no context or additional information provided, it is not possible to determine the value of mass (m) from the given options. Mass is a fundamental property of objects and plays an essential role in various problems involving gravitational force, acceleration, energy, and momentum. In typical problems, mass can be found based on the context and provided information, such as weight or volume and density. Understanding the concept of mass is crucial for solving real-life problems.

Step by step solution

01

Understand Mass

Mass is a measure of the amount of matter in an object, typically measured in units like kilograms (kg). It is a fundamental property of all objects, and it is an essential parameter in many physics and engineering problems. Examples of these problems include calculating the gravitational force, energy, and momentum of objects.
02

Importance for Various Problems

Knowing the mass of an object is essential for solving problems as it determines the gravitational force between objects, as given by Newton's law of universal gravitation: \(F=G\frac{m_1m_2}{r^2}\), where G is the gravitational constant, and m1 and m2 are the masses of the objects, and r is the distance between them. It also impacts the acceleration of an object according to Newton's second law, \(F = ma\), where F is the net force acting on an object of mass m, resulting in acceleration a. Additionally, mass affects the calculation of an object's energy (E=mc^2) and momentum (p=mv).
03

Finding Mass in Typical Problems

In many physics and engineering problems, the mass of an object can be found based on the given information and context. For example, one might be asked to find the mass of an object based on its weight, as weight is a result of the gravitational force acting on an object with mass, and is given by W = mg, where m is the mass, and g is the acceleration due to gravity. Similarly, the mass of an object could be found based on its volume and density using the formula m = 蟻V, where 蟻 is the density, and V is the volume of the object.
04

Conclusion

As there is no context or relevant information provided in this particular exercise, it is not possible to find the value of mass (m) from the given options. Understanding the concepts of mass, its importance in various problems, and how to find it in different contexts will help in solving real-life problems, which might be useful in the context of the missing problem statement.

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Most popular questions from this chapter

Relative permittivity and permeability of a material \(\varepsilon_{r}\) and \(\mu_{r}\) respectively. Which of the following value of these quantities are allowed for a diamagnetic material? (A) \(\varepsilon_{r}=0.5, \mu_{r}=1.5\) (B) \(\varepsilon_{r}=1.5, \mu_{r}=0.5\) (C) \(\varepsilon_{r}=0.5, \mu_{r}=0.5\) (D) \(\varepsilon_{r}=1.5, \mu_{r}=1.5\)

Velocity and acceleration vector of a charged particle moving in a magnetic field at some instant are \(\vec{v}=3 \hat{i}+4 \hat{j}\) and \(\vec{a}=2 \hat{i}+x \hat{j}\). Select the correct alternative (s) (A) \(x=-1.5\) (B) \(x=3\) (C) Magnetic field is along \(z\)-direction (D) Kinetic energy of the particle is constant

If a magnet is suspended at an angle of \(30^{\circ}\) to the magnetic meridian, the dip needle makes an angle of \(45^{\circ}\) with the horizontal. The real dip is (A) \(\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)\) (B) \(\tan ^{-1}(\sqrt{3})\) (C) \(\tan ^{-1}\left(\sqrt{\frac{3}{2}}\right)\) (D) \(\tan ^{-1} \frac{2}{\sqrt{3}}\)

A coil in the shape of an equilateral triangle of side \(0.02 \mathrm{~m}\) is suspended from vertex such that it is hanging in a vertical plane between the pole-pieces of a permanent magnet producing a horizontal magnetic field of \(5 \times 10^{-2} \mathrm{~T}\). Current in loop is \(0.1 \mathrm{~A}\). Then (A) magnetic moment of the loop is \(\sqrt{3} \times 10^{-5} \mathrm{~A} / \mathrm{m}^{2}\). (B) magnetic moment of the loop is \(1 \times 10^{-6} \mathrm{~A} / \mathrm{m}^{2}\). (C) couple acting on the coil is \(5 \sqrt{3} \times 10^{-7} \mathrm{~N} / \mathrm{m}\). (D) couple acting on the coil is \(\sqrt{3} \times 10^{-7} \mathrm{~N} / \mathrm{m}\).

A metal disc of radius \(R=6 \mathrm{~cm}\) is mounted on a frictionless axle. The current can flow through the axle out along the disc to a sliding contact of rim of the disc. A uniform magnetic field \(B=2 \mathrm{~T}\) is parallel to the axis of the disc. When the current is \(3 \mathrm{~A}\), the disc rotates with constant angular velocity. The frictional force at the rim between the stationary electrical contact and the rotating rim is \(9 x \times 10^{-2} \mathrm{~N}\). Find the value of \(x\).
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