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Velocity and acceleration vector of a charged particle moving in a magnetic field at some instant are \(\vec{v}=3 \hat{i}+4 \hat{j}\) and \(\vec{a}=2 \hat{i}+x \hat{j}\). Select the correct alternative (s) (A) \(x=-1.5\) (B) \(x=3\) (C) Magnetic field is along \(z\)-direction (D) Kinetic energy of the particle is constant

Short Answer

Expert verified
The correct alternatives are (C) and (D). (C) states that the magnetic field is along the z-direction, and (D) states that the kinetic energy of the particle remains constant.

Step by step solution

01

Understanding Lorentz force

Lorentz force is the force experienced by a charged particle moving in an electric and magnetic field. For this exercise, we are only considering the magnetic field. The magnetic force, F, acting on the charged particle can be written as: \[\vec{F} = q (\vec{v} \times \vec{B})\] where q is the charge of the particle, \(\vec{v}\) is its velocity vector, and \(\vec{B}\) is the magnetic field vector. Since magnetic force is perpendicular to the velocity vector, it does not affect the particle's speed, but modifies its direction of motion. Now, the acceleration vector, \(\vec{a}\), of the particle can be obtained as: \[\vec{a} = \frac{\vec{F}}{m} = \frac{q(\vec{v} \times \vec{B})}{m}\] where m is the mass of the particle.
02

Solution for x-component of the acceleration vector

Given the velocity vector: \(\vec{v}=3\hat{i}+4\hat{j}\), let's calculate the cross product of the velocity and magnetic field vectors: \[\vec{v} \times \vec{B} = \begin{vmatrix} \hat{i}&\hat{j}&\hat{k}\\ 3&4&0\\ B_x&B_y&B_z \end{vmatrix} = (4B_z)\hat{i} - (3B_z)\hat{j}\] Where \(B_x\), \(B_y\) and \(B_z\) are the components of the magnetic field vector. Now, we know the given acceleration vector: \(\vec{a}=2\hat{i}+x\hat{j}\), so comparing its x-component with the x-component of \(\frac{q(\vec{v} \times \vec{B})}{m}\), we get: \[2 = \frac{q(4B_z)}{m}\] We cannot find the value of x from this information, but we can understand that \(B_z\) cannot be zero, as it would make the x-component of acceleration zero, which contradicts the given information.
03

Solution for y-component of the acceleration vector

Comparing the y-component of the acceleration vector with the y-component of \(\frac{q(\vec{v} \times \vec{B})}{m}\), we get: \[x = -\frac{3qB_z}{m}\] This equation shows that the value of x depends on the values of q, m, and \(B_z\).
04

Checking the alternatives

(A) \(x=-1.5\): Since the sign of x depends on the product of q and \(B_z\), we cannot confirm that \(x=-1.5\) without knowing the values of q and \(B_z\). (A) may or may not be correct. (B) \(x=3\): Similarly, we cannot confirm that \(x=3\) without knowing the values of q and \(B_z\). (B) may or may not be correct. (C) Magnetic field is along z-direction: Since \(B_z\) cannot be zero, as discussed earlier, it implies that the magnetic field is indeed along the z-direction. So, alternative (C) is correct. (D) Kinetic energy of the particle is constant: As the magnetic force is perpendicular to the velocity of the charged particle, it doesn't do any work on the particle, and hence, the particle's kinetic energy remains constant. So, alternative (D) is also correct. From our analysis, the correct alternatives are (C) and (D).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz Force
The Lorentz force is a fundamental concept that describes the force exerted on a charged particle moving through a magnetic field. It's essential to understanding the behavior of particles in electromagnetic fields and is given by the equation:
\begin{align*}\vec{F} = q (\vec{v} \times \vec{B})\end{align*}
where \(q\) represents the charge of the particle, \(\vec{v}\) is the velocity vector, and \(\vec{B}\) is the magnetic field vector. The cross product indicates that the direction of the magnetic force is perpendicular to the plane defined by the velocity and magnetic field vectors. It is this force that can cause changes in the direction of a particle's velocity without affecting its speed, as magnetic force does no work and therefore the kinetic energy remains constant.
Velocity and Acceleration Vectors in Magnetic Field
The direction and magnitude of a charged particle's velocity and acceleration vectors are crucial factors that determine its path through a magnetic field. When a particle moves in such a field, its velocity vector \(\vec{v}\) and acceleration vector \(\vec{a}\) are governed by the forces applied to it. This physical scenario is expressed via the equation:
\begin{align*}\vec{a} = \frac{\vec{F}}{m} = \frac{q(\vec{v} \times \vec{B})}{m}\end{align*}
The acceleration vector is the rate of change of the velocity vector with respect to time. The direction of acceleration, according to this equation, is always perpendicular to both the velocity vector and the magnetic field line. This means that although the particle may change direction (accelerate), its speed (the magnitude of its velocity) remains unaffected because the magnetic force only influences the direction, not the speed.
Cross Product in Magnetic Fields
Understanding the cross product in the context of magnetic fields is essential for grasping how the Lorentz force dictates the motion of a charged particle. The cross product, symbolized by \(\times\), calculates a vector that is perpendicular to both input vectors—in this case, the velocity \(\vec{v}\) and magnetic field \(\vec{B}\) vectors. As an illustration:
\begin{align*}\vec{v} \times \vec{B} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \3 & 4 & 0 \B_x & B_y & B_z\end{vmatrix} = (4B_z)\hat{i} - (3B_z)\hat{j}\end{align*}
This operation reveals that the resulting force vector due to the magnetic field will not have a \(\hat{k}\) component because the velocity vector does not have a \(\hat{k}\) component. As the calculation of the cross product defines the direction of the force, it is also responsible for the circular or helical paths observed for charged particles in magnetic fields. This result guides us in analyzing and understanding the forces acting on the charged particle and is foundational for further study of magnetic phenomena and their applications in technology such as particle accelerators, cyclotrons, and magnetic storage devices.

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