/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 A bimetallic strip is made of al... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A bimetallic strip is made of aluminium and steel \(\left(\alpha_{A l}>\alpha_{\text {steel }}\right)\). On heating, the strip will (A) remain straight. (B) get twisted. (C) bend with aluminium on concave side. (D) bend with steel on concave side.

Short Answer

Expert verified
The bimetallic strip made of aluminum and steel will bend when heated, with the steel forming the concave side. This is because the aluminum has a higher coefficient of linear expansion and will expand more than the steel, causing the strip to bend. Therefore, the correct option is (D) bend with steel on the concave side.

Step by step solution

01

Observe the expansion of each metal when heated

When the bimetallic strip is heated, both metals (aluminum and steel) will expand. However, due to the different coefficients of linear expansion, the aluminum will expand more than the steel.
02

Analyze the bending of the bimetallic strip

As the aluminum expands more than the steel, the bimetallic strip cannot remain straight and will bend to accommodate the difference in expansion.
03

Determine which side will be concave

Since the aluminum expands more than the steel, the strip will bend in such a way that the aluminum forms the convex side, and the steel forms the concave side. This is because the larger expansion of the aluminum will "push" the steel to form the concave side.
04

Choose the correct option

From our analysis, we can conclude that the bimetallic strip will bend with the steel forming the concave side. The correct option is (D) bend with steel on the concave side.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An aluminium sphere of \(20 \mathrm{~cm}\) diameter is heated from \(0^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C}\). Its volume changes by (given that the coefficient of linear expansion for aluminium \(\left.\alpha_{A l}=23 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right)\) (A) \(28.9 \mathrm{cc}\) (B) \(2.89 \mathrm{cc}\) (C) \(9.28 \mathrm{cc}\) (D) \(49.8 \mathrm{cc}\)

Cooking gas containers are loaded on to a truck moving with uniform speed. The temperature of the gas molecules inside the containers will (A) increase. (B) decrease. (C) remain same. (D) decrease for some, whereas increase for others.

\(100 \mathrm{~g}\) of ice at \(0^{\circ} \mathrm{C}\) is mixed with \(100 \mathrm{~g}\) of water at \(100^{\circ} \mathrm{C}\). What will be the final temperature of the mixture? (Latent of fusion for ice \(=80 \mathrm{cal} / \mathrm{gm}\) and specific heat of water is \(1 \mathrm{cal} / \mathrm{gm}^{\circ} \mathrm{C}\) ) (A) \(10^{\circ} \mathrm{C}\) (B) \(20^{\circ} \mathrm{C}\) (C) \(30^{\circ} \mathrm{C}\) (D) \(0^{\circ} \mathrm{C}\)

A wire suspended vertically from one of its ends is stretched by attaching a weight of \(200 \mathrm{~N}\) to the lower end. The weight stretches the wire by \(1 \mathrm{~mm}\). The elastic energy stored in the wire is (A) \(0.2 \mathrm{~J}\) (B) \(10 \mathrm{~J}\) (C) \(20 \mathrm{~J}\) (D) \(0.1 \mathrm{~J}\)

Find the angular frequency of oscillation. If process is isothermal. Length of gas column at equilibrium position is \(l_{1}\) and gas pressure is \(P_{1}\) at equilibrium position. (A) \(\sqrt{\frac{P_{1} S_{0}}{4 m l_{1}}}\) (B) \(\sqrt{\frac{2 P_{1} S_{0}}{m l_{1}}}\) (C) \(\sqrt{\frac{P_{1} S_{0}}{m l_{1}}}\) (D) \(\sqrt{\frac{P_{1} S_{0}}{2 m l_{1}}}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.