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The unit of power is (A) Kilowatt (B) Kilowatt-hour (C) Dyne (D) Joule

Short Answer

Expert verified
The correct unit of power is (A) Kilowatt.

Step by step solution

01

Understanding the basic concepts

Power is the rate at which work is done or the rate at which energy is transferred. The formula for Power (P) is given by: P = Work/ Time = Energy/ Time Now, we will analyze each option to see if it matches the formula and represents power's unit.
02

Analyzing Option A: Kilowatt

Kilowatt (kW) is a unit of power in the International System of Units (SI). One kilowatt is defined as one thousand watts, where watt (W) is a derived unit of power and is equal to joule per second (J/s). 1 kW = 1000 W = 1000 J/s
03

Analyzing Option B: Kilowatt-hour

Kilowatt-hour (kWh) is a unit of energy. It is commonly used to measure the energy consumption of electrical appliances. One kilowatt-hour represents the amount of energy consumed by a 1000-watt appliance running for one hour. 1 kWh = 1 kW * 1 hr = 1000 W * 3600 s = 3,600,000 J
04

Analyzing Option C: Dyne

Dyne is a unit of force in the centimeter-gram-second (CGS) system of units. It is not a relevant unit for power measurement as it is related to force and not energy or work.
05

Analyzing Option D: Joule

Joule (J) is a unit of energy or work in the International System of Units (SI). It is used to represent the energy transferred to an object when a force of one newton acts upon it to move it one meter. 1 J = 1 N * 1 m
06

Identifying the correct answer

After analyzing all the options, it is clear that Option A: Kilowatt (kW) is the correct unit of power, as it matches the formula and concept of power - the rate of energy transfer or work done. So, the correct answer is: (A) Kilowatt

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit of Power
Power in the realm of physics is a fundamental concept that corresponds to the rate at which work is performed or energy is transferred over time. Quite simply, if you imagine doing a certain amount of work or transferring a certain amount of energy in less time, you'll require more power; conversely, doing the same amount of work or energy transfer but at a slower pace requires less power.

The standardized measure for power is the watt (W), with one watt amounting to one joule of work done or energy transferred per second. For tasks that demand a larger scale, the kilowatt (kW), which is equivalent to 1,000 watts, is frequently used. This could apply to anything from household appliances to industrial machinery. Therefore, the unit of power that is in line with these definitions and is endorsed by the International System of Units is the kilowatt.
Work-Energy Principle
The work-energy principle is a cornerstone of classical mechanics, and it is elegantly simple yet powerful: the work done on an object is equal to the change in its kinetic energy. To put it into context, when you apply a force to an object and cause it to move, you are doing work on that object. This work is calculated simply by the force multiplied by the distance over which it is applied in the direction of the force.

Work (W) = Force (F) * Distance (d)

In practice, this principle helps explain phenomena like why a speeding bullet has a significant impact when it hits an object: the bullet's kinetic energy is a result of the work done on it. It’s also a useful concept in numerous real-world applications, such as determining the power required by machinery to lift objects against gravitational force.
International System of Units
The International System of Units, abbreviated as SI from its French name, Système International d'Unités, is the modern form of the metric system and represents the universally accepted standard for measurements. The SI system is essential in ensuring consistency and uniformity in the communication of scientific data and technical information.

Within the SI system, there are seven base units that describe fundamental physical quantities, such as meters for length, kilograms for mass, and seconds for time. All other units are derived from these base units. For instance, the derived unit for power, watt (W), is a combination of the base units for mass, length, and time, and is defined as one joule per second. The broad adoption of the SI system facilitates collaboration and comprehension across different fields and international borders.
Energy Consumption Measurement
When we talk about energy consumption, we refer to the total amount of energy used by an appliance or device during its operation. This is usually measured in terms of kilowatt-hours (kWh). The concept is simple: one kilowatt-hour is equivalent to a power consumption of one kilowatt sustained for one hour.

Understanding energy consumption is particularly important for managing energy resources and for the calculation of electrical costs for households and businesses. For example, an electric heater rated at 1 kW running for 3 hours will consume 3 kWh of energy. By knowing that the local energy rate is a certain amount per kWh, one could easily calculate the cost of running that heater for the desired period. Energy consumption measurements not only help in budgeting electricity costs but also play a vital role in energy conservation efforts and monitoring the efficiency of electrical devices.

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Most popular questions from this chapter

A person trying to lose weight, lifts a \(10 \mathrm{~kg}\) mass \(0.5 \mathrm{~m}\), 1000 times daily. Fat supplies \(4 \times 10^{7} \mathrm{~J}\) of energy per kilogram which is converted into potential energy to raise the weight with \(20 \%\) efficiency rate. The potential energy lost each time the person lowers the mass is dissipated \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\) How much fat will the person use up in 10 days? (A) \(6.25 \times 10^{-2} \mathrm{~kg}\) (B) \(12.5 \times 10^{-2} \mathrm{~kg}\) (C) \(25 \times 10^{-2} \mathrm{~kg}\) (D) \(3.125 \times 10^{-2} \mathrm{~kg}\)

A block of mass \(2 \mathrm{~kg}\) is held over a vertical spring with spring unstretched. Suddenly, if block is left free, maximum compression of spring is [spring constant \(K=200 \mathrm{~N} / \mathrm{m}]:\) (A) \(0.2 \mathrm{~m}\) (B) \(0.1 \mathrm{~m}\) (C) \(0.4 \mathrm{~m}\) (D) \(0.05 \mathrm{~m}\)

A car comes to a skidding stop in \(15 \mathrm{~m}\). The force on the car due to the road is \(1000 \mathrm{~N}\). The work done by road on the car and car on the road, respectively, is (A) \(-15 \mathrm{~kJ}\), zero (B) zero, \(15 \mathrm{~kJ}\) (C) \(15 \mathrm{~kJ}\), zero (D) \(-15 \mathrm{~kJ}, 15 \mathrm{~kJ}\)

A block of mass \(m\) is slowly bulled up on inclined plane of neight \(h\) and inclination \(\theta\) with he top of a string parallel to the ncline. Which of the following statement is correct for the block when it moves up from the bottom to the top of the incline? A) Work done by the normal reaction force is zero. B) Work done by the string on block is \(m g h\). C) Work done by the gravity is \(m g h .\) D) Work done by the block is \(-m g h / 2\).

Two blocks \(A\) and \(B\) of equal mass \(m=1 \mathrm{~kg}\) are lying on a smooth horizontal surface as shown in Fig. \(4.27\). A spring of force constant \(K=200 \mathrm{~N} / \mathrm{m}\) is fixed at one end of block \(A\). Block \(B\) collides with another end of the spring with velocity \(v_{0}=2 \mathrm{~m} / \mathrm{s}\). What will be the maximum compression of the spring? [in decimeter]

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