Chapter 4: Problem 33
A block of mass \(2 \mathrm{~kg}\) is held over a vertical spring with spring unstretched. Suddenly, if block is left free, maximum compression of spring is [spring constant \(K=200 \mathrm{~N} / \mathrm{m}]:\) (A) \(0.2 \mathrm{~m}\) (B) \(0.1 \mathrm{~m}\) (C) \(0.4 \mathrm{~m}\) (D) \(0.05 \mathrm{~m}\)
Short Answer
Step by step solution
Setting up the Initial Conditions
Applying Conservation of Energy
Calculate the Height of the Block
Solve for the Maximum Compression
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gravitational Potential Energy
GPE can be calculated using the formula: \[GPE = mgh\]where:
- \(m\) is the mass of the object in kilograms (kg).
- \(g\) is the acceleration due to gravity, typically \(9.81\, ext{m/s}^2\) on Earth.
- \(h\) is the height in meters (m) above the reference point.
Spring Potential Energy
The potential energy stored in a spring can be calculated with the formula:\[rac{1}{2} k x^2\]where:
- \(k\) is the spring constant in Newtons per meter (N/m), which measures the spring's stiffness.
- \(x\) is the displacement from the spring's equilibrium position in meters (m).
Hooke's Law
Mathematically, Hooke's Law is expressed as:\[F = -kx\]where:
- \(F\) represents the force applied on the spring in Newtons (N).
- \(k\) is the spring constant (N/m), a measure of the spring's stiffness.
- \(x\) is the compression or elongation distance from its natural length.