Chapter 15: Problem 8
Find a potential function \(f\) for the field \(\mathbf{F}\). $$\mathbf{F}=(y+z) \mathbf{i}+(x+z) \mathbf{j}+(x+y) \mathbf{k}$$
Short Answer
Expert verified
The potential function is \(f(x, y, z) = xy + xz + yz\).
Step by step solution
01
Understand the Problem
We're given a vector field \(\mathbf{F} = (y+z) \mathbf{i} + (x+z) \mathbf{j} + (x+y) \mathbf{k}\) and need to find a scalar function \(f(x, y, z)\) such that \(abla f = \mathbf{F}\). This function \(f\) is called a potential function or a scalar potential.
02
Express the Gradient of f
The gradient of a function \(f(x, y, z)\) is given by \(abla f = \frac{\partial f}{\partial x} \mathbf{i} + \frac{\partial f}{\partial y} \mathbf{j} + \frac{\partial f}{\partial z} \mathbf{k}\). We need each component of this gradient to match the corresponding component of \(\mathbf{F}\): \[\frac{\partial f}{\partial x} = y + z,\]\[\frac{\partial f}{\partial y} = x + z,\]\[\frac{\partial f}{\partial z} = x + y.\]
03
Integrate with Respect to x
Integrate \(\frac{\partial f}{\partial x} = y + z\) with respect to \(x\): \[ f(x,y,z) = (y + z)x + g(y, z), \]where \(g(y, z)\) is an arbitrary function of \(y\) and \(z\) because the derivative of \(g\) with respect to \(x\) is zero.
04
Integrate with Respect to y
Integrate \(\frac{\partial f}{\partial y} = x + z\) using the expression for \(f(x, y, z)\) found earlier:\[ \frac{\partial}{\partial y}((y+z)x + g(y,z)) = x + \frac{\partial g}{\partial y} = x + z.\]This implies that \(\frac{\partial g}{\partial y} = z\) or, integrating with respect to \(y\),\[ g(y, z) = zy + h(z), \]where \(h(z)\) is an arbitrary function of \(z\).
05
Integrate with Respect to z
Now, consider \(\frac{\partial f}{\partial z} = x + y\) using the partial derivative:\[ \frac{\partial}{\partial z}((y+z)x + zy + h(z)) = x + y + \frac{dh}{dz} = x + y.\]This implies \(\frac{dh}{dz} = 0\), so \(h(z)\) must be a constant, say \(C\).
06
Assemble the Potential Function
Combine all parts to find the potential function \(f\):\[ f(x, y, z) = (y+z)x + zy + C. \]The constant \(C\) does not affect the field, so it can be any constant or zero. Thus, a potential function for \(\mathbf{F}\) is\[ f(x, y, z) = xy + xz + yz. \]
07
Verify the Solution
Differentiate \(f(x, y, z) = xy + xz + yz\) to check:\(\frac{\partial f}{\partial x} = y + z,\)\(\frac{\partial f}{\partial y} = x + z,\)\(\frac{\partial f}{\partial z} = x + y.\)These partial derivatives match the components of \(\mathbf{F}\), confirming that the potential function is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient
In vector calculus, the gradient is a fundamental concept often represented as \( abla f \). It denotes a vector field consisting of the partial derivatives of a scalar function \( f(x, y, z) \). These derivatives provide the directional slope of the function at any point, indicating the steepest ascent direction in the field. For a function \( f(x, y, z) \), the gradient can be expressed as:\[ abla f = \frac{\partial f}{\partial x} \mathbf{i} + \frac{\partial f}{\partial y} \mathbf{j} + \frac{\partial f}{\partial z} \mathbf{k} \]
- Each component of \( abla f \) corresponds to the rate of change of \( f \) with respect to one of the variables \( x, y, \) or \( z \).
- The gradient points in the direction of greatest increase of the scalar field \( f \).
- In the context of potential functions, the gradient of a potential function equals the vector field \( \mathbf{F} \).
Potential Function
A potential function, often denoted as \( f \), serves as a scalar potential for a given vector field \( \mathbf{F} \). If there exists such an \( f(x, y, z) \) for which the gradient \( abla f \) equals \( \mathbf{F} \), then \( f \) is a potential function for \( \mathbf{F} \). This relationship is formalized as:\[ abla f = \mathbf{F} \]
- The existence of a potential function implies that the vector field is conservative.
- It means there are no rotational components in the field, leading to simplifications in the integration over paths.
- To find a potential function, one must integrate the components of the vector field and ensure all partial derivative conditions are satisfied.
Scalar Field
A scalar field associates a scalar value with every point in space. In the context of vector calculus, it is typically represented by a function \( f(x, y, z) \). Scalar fields are crucial because they provide a way to measure quantities like temperature, pressure, or potential energy at any given point:
- The function assigns a single value (a scalar) to each point \( (x, y, z) \) in the space.
- Scalar fields can be visualized using contour maps or level surfaces, where each contour line represents points with the same scalar value.
- The gradient of a scalar field gives a vector field, which points in the direction of the greatest rate of increase of the scalar value.
Vector Field
A vector field assigns a vector to every point in space, represented here as \( \mathbf{F}(x, y, z) \). Each vector has both magnitude and direction, describing phenomena like fluid flow or force fields:
- The vector field \( \mathbf{F} \) can be described as \( (P(x, y, z), Q(x, y, z), R(x, y, z)) \), with each component dependent on spatial variables.
- Vector fields visualize how a vector quantity changes throughout space.
- A vector field is conservative if a scalar potential function exists, making it possible to derive \( \mathbf{F} \) from a gradient of this function.