Chapter 15: Problem 23
In Exercises \(19-28,\) use a parametrization to find the flux \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d \sigma\) across the surface in the specified direction. \( \mathbf{F}=2 x y \mathbf{i}+2 y z \mathbf{j}+2 x z \mathbf{k}\) upward across the portion of the plane \(x+y+z=2 a\) that lies above the square \(0 \leq x \leq a\) \(0 \leq y \leq a,\) in the \(x y\) -plane
Short Answer
Step by step solution
Surface Parametrization
Compute the Tangent Vectors
Compute the Normal Vector
Compute \(\mathbf{F} \cdot \mathbf{n}\)
Set Up and Evaluate the Double Integral
Final Step: Result of the Flux Integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametrization
Tangent Vectors
- \( \mathbf{r}_u = \frac{\partial}{\partial u}\left\langle u, v, 2a - u - v \right\rangle = \langle 1, 0, -1 \rangle \)
- \( \mathbf{r}_v = \frac{\partial}{\partial v}\left\langle u, v, 2a - u - v \right\rangle = \langle 0, 1, -1 \rangle \)
Normal Vector
- We take the cross product of \( \mathbf{r}_u = \langle 1, 0, -1 \rangle \) and \( \mathbf{r}_v = \langle 0, 1, -1 \rangle \).
- This results in \( \mathbf{n} = \langle 1, 0, -1 \rangle \times \langle 0, 1, -1 \rangle = \langle 1, 1, 1 \rangle \).