Chapter 9: Problem 2
Find the Taylor polynomials of orders \(0,1,2,\) and \(3\) generated by \(f\) at \(a.\) $$f(x)=\sin x, \quad a=0$$
Short Answer
Expert verified
Taylor polynomials: Order 0: 0, Order 1: x, Order 2: x, Order 3: x - x^3/6.
Step by step solution
01
Understand the Function and Point of Expansion
We are tasked with finding the Taylor polynomials for the function \(f(x) = \sin x\) at the point \(a = 0\), which is often called the Maclaurin series because it expands around zero.
02
Determine the Function's Derivatives
Calculate the derivatives of \(f(x)\) that will be needed: \(f'(x) = \cos x\), \(f''(x) = -\sin x\), \(f'''(x) = -\cos x\), and \(f^{(4)}(x) = \sin x\).
03
Evaluate Derivatives at \(a = 0\)
We need the value of these derivatives at 0: \(f(0) = 0\), \(f'(0) = 1\), \(f''(0) = 0\), \(f'''(0) = -1\), and \(f^{(4)}(0) = 0\).
04
Form the Taylor Polynomial of Order 0
The zeroth-order Taylor polynomial is simply the function's value at \(a\): \[P_0(x) = f(0) = 0\].
05
Form the Taylor Polynomial of Order 1
The first-order Taylor polynomial uses the first derivative: \[P_1(x) = f(0) + f'(0)(x - 0) = 0 + 1(x) = x\].
06
Form the Taylor Polynomial of Order 2
The second-order Taylor polynomial uses up to the second derivative: \[P_2(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 = 0 + x + 0 = x\].
07
Form the Taylor Polynomial of Order 3
The third-order Taylor polynomial uses up to the third derivative: \[P_3(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 = 0 + x + 0 - \frac{1}{6}x^3 = x - \frac{x^3}{6}\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Maclaurin series
The Maclaurin series is a special case of the Taylor series. It's an expansion of a function around the point zero, which allows us to approximate the function with a polynomial. The idea is to take derivatives of the function, evaluate them at zero, and then use these values to build the polynomial. For any function that can be represented by a Maclaurin series, the formula is:
- \[ f(x) \approx f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \cdots \]
Derivatives
Derivatives are fundamental to constructing Taylor and Maclaurin series. They measure how a function changes as its input changes. By finding the derivatives of a function, particularly at the specific point of expansion, we can understand the function's behavior at that point more deeply. For instance:
- The first derivative \( f'(x) \) tells us how fast the function is changing at any point \(x\).
- The second derivative \( f''(x) \) gives us information about the concavity of the function, i.e., whether it curves upwards or downwards.
- \( f'(x) = \cos x \)
- \( f''(x) = -\sin x \)
- \( f'''(x) = -\cos x \)
- \( f^{(4)}(x) = \sin x \)
Order of polynomial
The "order" of a Taylor polynomial refers to the degree of the highest power of \(x\) in the polynomial. In simpler terms, it's how many derivatives you include in your approximation. Each "order" provides a progressively more accurate approximation of the function around the chosen point.- **Zeroth-order polynomial**: This is just the value of the function right at the point of expansion. It doesn't account for any changes – a flat line.- **First-order polynomial**: Adds the linear approximation using the first derivative, creating a line tangent to the curve at that point.As you add higher-order terms:
- **Second-order**: Incorporates the function's concavity at the point.
- **Third-order**: Begins to approximate the 'twist' of the curve, including the effect of the third derivative.