Chapter 9: Problem 121
Which of the sequences converge, and which diverge? Give reasons for your answers. $$a_{n}=\frac{1+\sqrt{2 n}}{\sqrt{n}}$$
Short Answer
Expert verified
The sequence \( a_n \) converges to \( \sqrt{2} \).
Step by step solution
01
Understand Convergence and Divergence
A sequence converges if it approaches a specific number as the index \(n\) goes to infinity. Conversely, a sequence diverges if it does not approach a specific number.
02
Write Down the Given Sequence
The sequence given is \( a_n = \frac{1 + \sqrt{2n}}{\sqrt{n}} \). We need to analyze the behavior of this expression as \( n \to \infty \).
03
Simplify the Sequence
Divide the terms in the numerator by \( \sqrt{n} \): \( a_n = \frac{1}{\sqrt{n}} + \frac{\sqrt{2n}}{\sqrt{n}} = \frac{1}{\sqrt{n}} + \sqrt{2} \).
04
Analyze Each Term as \( n \to \infty \)
- The term \( \frac{1}{\sqrt{n}} \) approaches zero as \( n \to \infty \) because the square root of \(n\) in the denominator increases without bound. - The term \( \sqrt{2} \) remains constant.
05
Conclude the Behavior of the Sequence
Since \( a_n = \frac{1}{\sqrt{n}} + \sqrt{2} \) and \( \frac{1}{\sqrt{n}} \to 0 \) as \( n \to \infty \), the sequence \( a_n \to \sqrt{2} \). Therefore, the sequence converges to \( \sqrt{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits in Sequences
In the study of sequences, the concept of a limit is crucial to determine if a sequence converges. When we talk about the limit of a sequence, we mean the value that the terms of the sequence get closer to as the index grows indefinitely. In mathematical terms, we say that a sequence \(a_n\) converges to a limit \(L\) if for every positive number \(\epsilon\), there's an integer \(N\) such that for all \(n > N, \ |a_n - L| < \epsilon\). This implies that as we continue to increase \(n\), the terms of the sequence get arbitrarily close to \(L\).
- If a sequence has a limit, it converges.
- If it doesn't approach any particular value, as \(n\) approaches infinity, it diverges.
Infinite Sequences
Infinite sequences involve terms ordered in such a way that it does not terminate. These sequences continue indefinitely and their limits help us understand their long-term behavior. Each term in a sequence is associated with a natural number, typically denoted \(n\), and as \(n\) increases, we can observe patterns of convergence or divergence.
- Infinite sequences can have various forms—constant, convergent, or even oscillating.
- Even if a sequence appears chaotic in the beginning, it might demonstrate stabilizing behavior.
Convergence and Divergence
Convergence and divergence are fundamental in understanding sequences. A sequence converges if it settles into a constant value as it's endlessly extended. Conversely, if the sequence fails to settle to a particular value, it diverges.
- Convergent sequences have a finite limit that terms approach.
- Divergent sequences do not have such a finite limit and often exhibit unstable behavior.