/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 To test \(\mu\) for an \(x\) dis... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

To test \(\mu\) for an \(x\) distribution that is mound-shaped using sample size \(n \geq 30,\) how do you decide whether to use the normal or the Student's \(t\) distribution?

Short Answer

Expert verified
Use normal distribution if \( \sigma \) is known and Student's t if \( \sigma \) is unknown.

Step by step solution

01

Understand the Problem

We need to determine which statistical distribution to use (normal or Student's t) when testing the mean \( \mu \) of a mound-shaped distribution with a sample size \( n \geq 30 \). The choice depends on certain conditions related to the sample data.
02

Assess Sample and Population Standard Deviation

Identify if the population standard deviation \( \sigma \) is known or unknown. The choice of distribution depends significantly on this factor.
03

Use the Normal Distribution

If the population standard deviation \( \sigma \) is known, then we should use the normal distribution for testing the mean because the sample size \( n \geq 30 \) makes the student's t-distribution converge to the normal distribution due to the central limit theorem.
04

Use the Student's t Distribution

If the population standard deviation \( \sigma \) is unknown, use the Student's t distribution. This accounts for additional variability introduced by estimating \( \sigma \) from the sample data.
05

Consider the Sample Size

Since the sample size is \( n \geq 30 \), both the normal and t-distribution approaches will be similar in shape, but the decision primarily hinges on the known or unknown status of \( \sigma \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The normal distribution is a fundamental concept in statistics. It's represented by a symmetric, bell-shaped curve where most of the data points are clustered around the mean. This distribution is completely described by two parameters: mean (\(\mu\)) and standard deviation (\(\sigma\)). When conducting a hypothesis test on a sample mean, we use the normal distribution if we know the population standard deviation. This is because the normal distribution allows us to make precise statements about the probability of observing a certain sample mean.
  • The bell curve is symmetric around the mean.
  • Roughly 68% of data falls within one standard deviation (\(\sigma\)) of the mean, 95% within two, and 99.7% within three.
If our sample size is large (\(n \geq 30\)), the Central Limit Theorem tells us that the sampling distribution of the sample mean will approximate a normal distribution regardless of the shape of the population distribution. This property makes the normal distribution especially useful when testing hypotheses about the mean.
Student's t Distribution
The Student's t distribution is crucial when we're working with smaller samples or when the population standard deviation is unknown. It resembles the normal distribution but has thicker tails. These thicker tails mean there's more probability in the tails, which accounts for the additional uncertainty introduced by estimating the population standard deviation from a sample. Several points are important to note about the Student's t distribution:
  • The shape of the t distribution changes with varying degrees of freedom. More data points (higher degrees of freedom) mean the t distribution looks more like the normal distribution.
  • For small sample sizes, the t distribution provides a better approximation than the normal distribution because it captures the variability more accurately.
The t distribution thus serves as an excellent tool when we need to estimate an unknown population standard deviation. As with the normal distribution, when the sample size is large, the t distribution becomes nearly identical to the normal distribution, hence our choice often depends on whether \(\sigma\) is known or not.
Central Limit Theorem
The Central Limit Theorem (CLT) is one of the cornerstones of statistics. It states that, given a sufficiently large sample size, the distribution of the sample mean will approach a normal distribution regardless of the original population's distribution. This theorem is extremely powerful because it allows statisticians to use the normal distribution to make inferences about the population mean even when the population itself is not normally distributed. Key attributes of the Central Limit Theorem include:
  • The sample size should be large enough. Practically, a sample size of 30 or more is usually sufficient.
  • It applies to the mean, variance, and sum of sample observations.
Thanks to the CLT, when dealing with large samples, we can confidently use normal distribution-based methods for hypothesis testing even if we start with a non-normal population distribution. This insight underpins much of inferential statistics and justifies the use of the normal distribution for large sample sizes even in the absence of complete knowledge about the population standard deviation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In general, if sample data are such that the null hypothesis is rejected at the \(\alpha=1 \%\) level of significance based on a two-tailed test, is \(H_{0}\) also rejected at the \(\alpha=1 \%\) level of significance for a corresponding onetailed test? Explain.

Compare statistical testing with legal methods used in a U.S. court setting. Then discuss the following topics in class or consider the topics on your own. Please write a brief but complete essay in which you answer the following questions. (a) In a court setting, the person charged with a crime is initially considered to be innocent. The claim of innocence is maintained until the jury returns with a decision. Explain how the claim of innocence could be taken to be the null hypothesis. Do we assume that the null hypothesis is true throughout the testing procedure? What would the alternate hypothesis be in a court setting? (b) The court claims that a person is innocent if the evidence against the person is not adequate to find him or her guilty. This does not mean, however, that the court has necessarily proved the person to be innocent. It simply means that the evidence against the person was not adequate for the jury to find him or her guilty. How does this situation compare with a statistical test for which the conclusion is "do not reject" (i.e., accept) the null hypothesis? What would be a type II error in this context? (c) If the evidence against a person is adequate for the jury to find him or her guilty, then the court claims that the person is guilty. Remember, this does not mean that the court has necessarily proved the person to be guilty. It simply means that the evidence against the person was strong enough to find him or her guilty. How does this situation compare with a statistical test for which the conclusion is to "reject" the null hypothesis? What would be a type I error in this context? (d) In a court setting, the final decision as to whether the person charged is innocent or guilty is made at the end of the trial, usually by a jury of impartial people. In hypothesis testing, the final decision to reject or not reject the null hypothesis is made at the end of the test by using information or data from an (impartial) random sample. Discuss these similarities between statistical hypothesis testing and a court setting. (e) We hope that you are able to use this discussion to increase your understanding of statistical testing by comparing it with something that is a well-known part of our American way of life. However, all analogies have weak points, and it is important not to take the analogy between statistical hypothesis testing and legal court methods too far. For instance, the judge does not set a level of significance and tell the jury to determine a verdict that is wrong only \(5 \%\) or \(1 \%\) of the time. Discuss some of these weak points in the analogy between the court setting and hypothesis testing.

To use the normal distribution to test a proportion \(p,\) the conditions \(n p>5\) and \(n q>5\) must be satisfied. Does the value of \(p\) come from \(H_{0}\) or is it estimated by using \(\hat{p}\) from the sample?

Please provide the following information for Problems. (a) What is the level of significance? State the null and alternate hypotheses. (b) Check Requirements What sampling distribution will you use? What assumptions are you making? Compute the sample test statistic and corresponding \(z\) or \(t\) value as appropriate. (c) Find (or estimate) the \(P\) -value. Sketch the sampling distribution and show the area corresponding to the \(P\) -value. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level \(\alpha ?\) (e) Interpret your conclusion in the context of the application. Note: For degrees of freedom \(d . f .\) not in the Student's \(t\) table, use the closest \(d . f .\) that is smaller. In some situations, this choice of \(d . f .\) may increase the \(P\) -value a small amount and therefore produce a slightly more "conservative" answer. Environment: Pollution Index Based on information from The Denver Post, a random sample of \(n_{1}=12\) winter days in Denver gave a sample mean pollution index of \(\bar{x}_{1}=43 .\) Previous studies show that \(\sigma_{1}=21 .\) For Englewood (a suburb of Denver), a random sample of \(n_{2}=14\) winter days gave a sample mean pollution index of \(\bar{x}_{2}=36 .\) Previous studies show that \(\sigma_{2}=15 .\) Assume the pollution index is normally distributed in both Englewood and Denver. Do these data indicate that the mean population pollution index of Englewood is different (either way) from that of Denver in the winter? Use a \(1 \%\) level of significance.

Two populations have normal distributions. The first has population standard deviation 2 and the second has population standard deviation \(3 .\) A random sample of 16 measurements from the first population had a sample mean of \(20 .\) An independent random sample of 9 measurements from the second population had a sample mean of \(19 .\) Test the claim that the population mean of the first population exceeds that of the second. Use a \(5 \%\) level of significance. (a) Check Requirements What distribution does the sample test statistic follow? Explain. (b) State the hypotheses. (c) Compute \(\bar{x}_{1}-\bar{x}_{2}\) and the corresponding sample distribution value. (d) Find the \(P\) -value of the sample test statistic. (e) Conclude the test (f) Interpret the results.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.