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Suppose \(x\) has a normal distribution with \(\sigma=1.2\). (a) Find the minimal sample size required so that for a \(90 \%\) confidence interval, the maximal margin of error is \(E=0.5\) (b) Based on this sample size and the \(x\) distribution, can we assume that the \(\bar{x}\) distribution is approximately normal? Explain.

Short Answer

Expert verified
(a) Sample size is 16. (b) Yes, \(\bar{x}\) is approximately normal because \(x\) is normal.

Step by step solution

01

Determine Z-Score for 90% Confidence Interval

For a 90% confidence interval, we first need to determine the corresponding Z-score, which represents the number of standard deviations a critical value is from the mean. Since 90% of the data lies within this interval, 5% of the data lies in each tail. The Z-score that corresponds to the 95th percentile is 1.645.
02

Apply Margin of Error Formula

The margin of error formula is given by \(E = Z \cdot \frac{\sigma}{\sqrt{n}}\), where \(E\) is the margin of error, \(Z\) is the Z-score, \(\sigma\) is the standard deviation, and \(n\) is the sample size. Substitute the given values: \(0.5 = 1.645 \cdot \frac{1.2}{\sqrt{n}}\).
03

Solve for Sample Size \(n\)

Rearrange the formula to solve for \(n\): \(\sqrt{n} = \frac{1.645 \cdot 1.2}{0.5}\). Calculating the right-hand side gives \(\sqrt{n} = 3.948\). Square both sides to solve for \(n\), resulting in \(n = 15.578\). Since the sample size must be whole, round up to the next whole number, which is \(16\).
04

Evaluate Normality of \(\bar{x}\) Distribution

The central limit theorem states that for samples of size \(n \geq 30\), the sampling distribution of the mean will be approximately normal, regardless of the shape of the original distribution. However, for smaller sample sizes, such as the 16 we calculated, the assumption of normality depends on the shape of the original distribution. But, since it is given that \(x\) itself is normally distributed, \(\bar{x}\) will also be approximately normally distributed for any \(n\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
A normal distribution is a fundamental concept in statistics. It is characterized by its symmetrical bell-shaped curve. This distribution is defined by two parameters: the mean () and the standard deviation (). The mean determines the center of the distribution, while the standard deviation measures the spread of the data.

In a normal distribution, data is evenly distributed around the mean. The majority of values (about 68%) lie within one standard deviation of the mean. As we move away from the mean, fewer data points fall within each interval:
  • Approximately 95% of values lie within two standard deviations.
  • Nearly 99.7% fall within three standard deviations.
In real-world situations, many variables naturally follow a normal distribution. This makes it easier to apply statistical methods and draw conclusions. The normal distribution is pivotal in hypothesis testing and confidence interval estimation.
Confidence Interval
A confidence interval provides a range of values in which a population parameter is expected to lie. It reflects the uncertainty or precision of an estimate based on sample data. When we say "90% confidence interval," it means that we are 90% confident that the true population parameter falls within this range.

Confidence intervals consist of two parts: the estimate from the data and the margin of error. The central point of a confidence interval is the sample statistic, such as the sample mean (), around which we build an interval with a certain probability. Hence, the interval helps to communicate the reliability of the estimate.
  • A narrower confidence interval indicates a more precise estimate.
  • A wider interval suggests more uncertainty.
The choice of confidence level (e.g., 90%, 95%, 99%) affects the interval's width. Higher confidence levels yield wider intervals because they increase the range of plausible values.
Margin of Error
The margin of error is a key component of confidence intervals, representing the maximum expected difference between the sample estimate and the true population parameter. It provides an absolute measure of uncertainty associated with sample-based estimates.

This margin is influenced by the standard deviation, sample size, and the Z-score associated with the chosen confidence level. The formula for margin of error is:

\[ E = Z \cdot \frac{\sigma}{\sqrt{n}} \]
  •  is the Z-score corresponding to the chosen confidence level.
  •  is the population standard deviation.
  •  is the sample size.
To achieve a smaller margin of error, one can increase the sample size or choose a lower confidence level. However, increasing the sample size typically results in more effective reduction of uncertainty.
Central Limit Theorem
The central limit theorem (CLT) is a critical statistical concept. It states that the sampling distribution of the sample mean becomes approximately normal as the sample size increases, regardless of the population's initial distribution.

However, the theorem assumes large sample sizes. For practical application, a sample size of 30 or more is typically enough to ensure normality of the sample mean distribution. This allows statisticians to make inferences about population parameters.
  • The CLT facilitates the use of statistical techniques that assume normality.
  • It ensures that sample means are more reliable for inferential statistics.
In cases where the original distribution is already normal, even smaller sample sizes can produce a normally distributed sample mean. This is significant because it simplifies calculations and increases accuracy in hypothesis testing and estimation.

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Most popular questions from this chapter

If a \(90 \%\) confidence interval for the difference of proportions contains some positive and some negative values, what can we conclude about the relationship between \(p_{1}\) and \(p_{2}\) at the \(90 \%\) confidence level?

If a \(90 \%\) confidence interval for the difference of means \(\mu_{1}-\mu_{2}\) contains all positive values, what can we conclude about the relationship between \(\mu_{1}\) and \(\mu_{2}\) at the \(90 \%\) confidence level?

At Community Hospital, the burn center is experimenting with a new plasma compress treatment. A random sample of \(n_{1}=316\) patients with minor burns received the plasma compress treatment. Of these patients, it was found that 259 had no visible scars after treatment. Another random sample of \(n_{2}=419\) patients with minor burns received no plasma compress treatment. For this group, it was found that 94 had no visible scars after treatment. Let \(p_{1}\) be the population proportion of all patients with minor burns receiving the plasma compress treatment who have no visible scars. Let \(p_{2}\) be the population proportion of all patients with minor burns not receiving the plasma compress treatment who have no visible scars. (a) Can a normal distribution be used to approximate the \(\hat{p}_{1}-\hat{p}_{2}\) distribution? Explain. (b) Find a \(95 \%\) confidence interval for \(p_{1}-p_{2}\) (c) Explain the meaning of the confidence interval found in part (b) in the context of the problem. Does the interval contain numbers that are all positive? all negative? both positive and negative? At the \(95 \%\) level of confidence, does treatment with plasma compresses seem to make a difference in the proportion of patients with visible scars from minor burns?

A random sample is drawn from a population with \(\sigma=12 .\) The sample mean is 30 (a) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size 49 What is the value of the margin of error? (b) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size \(100 .\) What is the value of the margin of error? (c) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size \(225 .\) What is the value of the margin of error? (d) Compare the margins of error for parts (a) through (c). As the sample size increases, does the margin of error decrease? (e) Critical Thinking Compare the lengths of the confidence intervals for parts (a) through (c). As the sample size increases, does the length of a \(90 \%\) confidence interval decrease?

In a random sample of 519 judges, it was found that 285 were introverts. (See reference in Problem 11.) (a) Let \(p\) represent the proportion of all judges who are introverts. Find a point estimate for \(p\). (b) Find a \(99 \%\) confidence interval for \(p\). Give a brief interpretation of the meaning of the confidence interval you have found. (c) Do you think the conditions \(n p > 5\) and \(n q > 5\) are satisfied in this problem? Explain why this would be an important consideration.

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