Chapter 6: Problem 44
Find the indicated probability, and shade the corresponding area under the standard normal curve. $$P(-1.78 \leq z \leq-1.23)$$
Short Answer
Expert verified
The probability is 0.0718.
Step by step solution
01
Understanding the Problem
We need to find the probability that a standard normal variable \( z \) falls between -1.78 and -1.23. This involves finding the area under the standard normal curve between these two \( z \)-scores.
02
Using the Standard Normal Table
Using the standard normal distribution table (or Z-table), we find the area to the left of \( z = -1.23 \) and \( z = -1.78 \) separately. The table gives us the probability that \( z \) is less than a given value.
03
Finding the Probability for \( z = -1.23 \)
Look up \( z = -1.23 \) in the standard normal table. Usually, the result is around 0.1093, which means the area to the left of \( z = -1.23 \) is 0.1093.
04
Finding the Probability for \( z = -1.78 \)
Similarly, find \( z = -1.78 \) in the table. The result is generally around 0.0375, which shows that the area to the left of \( z = -1.78 \) is 0.0375.
05
Calculating the Probability Between the Two Z-Scores
Subtract the smaller area (for \( z = -1.78 \)) from the larger area (for \( z = -1.23 \)) to find the probability that \( z \) is between -1.78 and -1.23:\[ P(-1.78 \leq z \leq -1.23) = 0.1093 - 0.0375 = 0.0718 \]
06
Shading the Area on the Curve
On the standard normal curve, shade the area between \( z = -1.78 \) and \( z = -1.23 \). This shaded region represents the probability of \( P(-1.78 \leq z \leq -1.23) = 0.0718 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Z-scores
Z-scores are a way of standardizing data points within a distribution. They help us understand how far a specific value is from the mean, using the standard deviation as a unit of measurement. For any data point, the Z-score tells you how many standard deviations it is away from the mean. This makes it easier to compare values from different datasets or distributions.
To calculate a Z-score, use the formula:
To calculate a Z-score, use the formula:
- \( z = \frac{(X - \mu)}{\sigma} \)
Navigating Probability
Probability is the measure of how likely an event is to occur. It is computed as a value between 0 and 1, where 0 indicates impossibility and 1 indicates certainty. In the context of the standard normal distribution, probability is often used to determine how likely it is for a random variable from the distribution to fall within a certain range. For example, in the exercise provided, we want to find the probability that a Z-score will be between -1.78 and -1.23.To find this, we use the cumulative probability from a standard normal distribution table. This table shows the probability that a Z-score will be less than a given value. To find the probability that lies between two Z-scores, as shown in the exercise, you subtract the cumulative probabilities of the lower Z-score from the higher Z-score:
- \( P(-1.78 \leq z \leq -1.23) = P(z \leq -1.23) - P(z \leq -1.78) \)
Examining Normal Curve Area
The area under the standard normal curve is a visual representation of probability. The standard normal curve, also known as the bell curve, is symmetrical around its mean, with a total area of 1. This assumes that all possible probabilities for a random variable under this curve adds up to 100%.
Determining the area under the curve for a particular range of Z-scores indicates the probability of a random variable falling within that range. For instance, in the provided exercise, the area under the curve between Z-scores of -1.78 and -1.23 tells us how likely a score within this region is.
To visualize this, imagine shading the section of the graph between these two Z-scores. The shaded area, calculated by subtracting the cumulative probabilities from a Z-table, embodies the probability of the random variable falling between these two values. It's a visual and quantitative measure rolled into one, making it an essential tool in statistics and probability.