/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Sketch the areas under the stand... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the areas under the standard normal curve over the indicated intervals and find the specified areas. To the right of \(z=-1.22\)

Short Answer

Expert verified
The area to the right of \(z = -1.22\) is approximately 0.8888.

Step by step solution

01

Understand the Problem

We need to find the area under the standard normal distribution curve to the right of a given z-score, which is \(z = -1.22\). The standard normal distribution is a symmetrical, bell-shaped curve centered at zero, with a standard deviation of 1.
02

Sketch the Normal Curve

Draw a standard normal curve with the mean \(\mu = 0\) at the center. Mark the point \(z = -1.22\) on the horizontal axis. Label this point on the left of the mean since it is a negative value. Shade the area under the curve to the right of this point, which represents the area we're looking for.
03

Use the Z-Table

A Z-table (or standard normal table) gives the area to the left of a specified z-score. First, locate \(z = -1.22\) in the Z-table to find the cumulative probability to the left of this z-score.
04

Compute the Area to the Right

The total area under the standard normal curve is 1. Therefore, to find the area to the right of \(z = -1.22\), subtract the cumulative probability found in Step 3 from 1. For example, if the Z-table value for \(z = -1.22\) is 0.1112, the area to the right is \(1 - 0.1112 = 0.8888\).
05

Verify the Result

Check the calculation to ensure accuracy by revisiting the Z-table and the subtraction operation. Once confirmed, record this area as the final result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-score
A z-score is a statistical measurement that describes a value's relation to the mean of a group of values. It is measured in terms of standard deviations from the mean. For example, if a z-score is 2, it means the value is 2 standard deviations away from the mean. Z-scores can be positive or negative, indicating whether the data point is above or below the mean, respectively. In our exercise, the z-score is 1.22, indicating that the value is 1.22 standard deviations below the mean since it is negative.
Understanding z-scores is crucial because they allow us to compare scores from different distributions and determine probabilities in a standard normal distribution. They help us understand where a specific value lies within a distribution, giving us a sense of how unusual or typical that value is within the dataset.
cumulative probability
Cumulative probability refers to the probability that a random variable takes on a value less than or equal to a particular value. In the context of the standard normal distribution, cumulative probability helps determine how much area lies to the left of a specific z-score.
For our particular problem, finding the cumulative probability for the z-score of 1.22 means identifying the area under the curve to the left of this z-score. This area represents the likelihood of a random variable falling below that z-score value. If this cumulative probability is given by the Z-table, one can find the area under the curve up to that specific z-score, useful for various statistical analyses.
Z-table
A Z-table, also known as a standard normal table, provides the cumulative probabilities of a normal distribution for different z-scores. This table is immensely useful when determining the area under the standard normal curve.
The Z-table displays probabilities to the left of a specified z-score. In our problem, you would use the Z-table to find the cumulative probability for 1.22, helping identify the likelihood or area under the curve for this score. The key is to locate the z-score in the table and read off the corresponding cumulative probability. This value is critical for finding other probabilities, like the area to the right, by performing additional calculations, such as subtraction from 1.
area under the curve
The area under the curve, specifically under the normal curve, represents the probability of a random variable within a certain range. The total area under the standard normal distribution curve equals 1, representing 100% probability.
In statistics, when working with a standard normal distribution, finding areas under the curve helps us determine probabilities related to specific z-scores. For the exercise, identifying the area to the right of a z-score, such as 1.22, involves understanding that the area complements the area found using cumulative probability and the Z-table. By subtracting the cumulative probability from 1, we find the probability of values being greater than the specified z-score, thus determining the area to the right.

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Most popular questions from this chapter

Suppose \(x\) has a distribution with a mean of 8 and a standard deviation of \(16 .\) Random samples of size \(n=64\) are drawn. (a) Describe the \(\bar{x}\) distribution and compute the mean and standard deviation of the distribution. (b) Find the \(z\) value corresponding to \(\bar{x}=9\) (c) Find \(P(\bar{x}>9)\) (d) Interpretation Would it be unusual for a random sample of size 64 from the \(x\) distribution to have a sample mean greater than \(9 ?\) Explain.

The taxi and takeoff time for commercial jets is a random variable \(x\) with a mean of 8.5 minutes and a standard deviation of 2.5 minutes. Assume that the distribution of taxi and takeoff times is approximately normal. You may assume that the jets are lined up on a runway so that one taxies and takes off immediately after another, and that they take off one at a time on a given runway. What is the probability that for 36 jets on a given runway, total taxi and takeoff time will be (a) less than 320 minutes? (b) more than 275 minutes? (c) between 275 and 320 minutes? Hint: See Problem 21

The heights of 18 -year-old men are approximately normally distributed, with mean 68 inches and standard deviation 3 inches (based on information from Statistical Abstract of the United States, 112 th edition (a) What is the probability that an 18 -ycar-old man selected at random is between 67 and 69 inches tall? (b) If a random sample of nine 18 -ycar-old men is selected, what is the probability that the mean height \(\bar{x}\) is between 67 and 69 inches? (c) Interpretation Compare your answers to parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this?

Find the \(z\) value described and sketch the area described.Find \(z\) such that \(55 \%\) of the standard normal curve lies to the left of \(z\).

Sketch the areas under the standard normal curve over the indicated intervals and find the specified areas. To the left of \(z=0.45\)

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